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a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)
- 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50
2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51
7\(x\) = 67
\(x\) = 67 : 7
\(x\) = \(\dfrac{67}{7}\)
Vậy \(x\) = \(\dfrac{67}{7}\)
b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)
17\(x\) - 48\(x\) - 111 = 2\(x\) - 4\(x\) + 43
- 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43
- \(x\) x (31 + 2 - 4) = 154
- \(x\) x (33 - 4) = 154
- \(x\) x 29 = 154
- \(x\) = 154 : (-29)
\(x\) = - \(\dfrac{154}{29}\)
Vậy \(x=-\dfrac{154}{29}\)
c) 10 . {[(x : 3 + 17) : 10 + 3 . 2^2] : 10} = 5
[(x : 3 + 17) : 10 + 3 . 4] : 10 = 5 : 10
[(x : 3 + 17) : 10 + 12] : 10 = 1/2
(x : 3 + 17) : 10 + 12 = 1/2 . 10
(x : 3 + 17) : 10 + 12 = 5
(x : 3 + 17) : 10 = 5 - 12
(x : 3 + 17) : 10 = -7
=> x : 3 + 17 = -7 . 10
x : 3 + 17 = -70
x : 3 = -70 - 17
x : 3 = -87
x = -87 . 3
x = -261
a ) \(\left(4x+5\right):3-121:1=4\)
\(\Leftrightarrow\left(4x+5\right):3-11=4\)
\(\Leftrightarrow\left(4x+5\right):3=15\)
\(\Leftrightarrow\left(4x+5\right)=45\)
\(\Leftrightarrow4x=40\)
\(\Leftrightarrow x=10\)
Tiếp tịch như z là đc
a: \(=\dfrac{3\cdot\left(-7\right)^7-10\cdot\left(-7\right)^7}{\left(-7\right)^6}=3\cdot\left(-7\right)-10\cdot\left(-7\right)=-21+70=49\)
b: \(=\dfrac{\left(-11\right)^9}{\left(-11\right)^5\cdot\left(-11\right)}=\left(-11\right)^3=-1331\)
\(5x+2x=6^2-5^0\Leftrightarrow5x+2x=6^2-1\)
\(\Leftrightarrow5x-2x=36-1\Leftrightarrow5x-2x=35\Leftrightarrow x\left(5+2\right)=35\)
\(\Leftrightarrow7x=35\Leftrightarrow x=35:7\Leftrightarrow x=5\)
\(5x+x=150:2+3\Leftrightarrow5x+x=75+3\)
\(\Leftrightarrow5x+x=78\Leftrightarrow x\left(5+1\right)=78\Leftrightarrow x6=78\)
\(\Leftrightarrow x=78:6\Leftrightarrow x=13\)
a) 5x + 2x = 62 - 50
7x = 35 => x = 5
b) 5x + x = 150 : 2 + 3
6x = 78 => x = 13
c) 6x + x = 511 : 59 + 31
7x = 28 => x = 4
d) 5x + 3x = 36 : 33 x 4 + 12
8x = 120 => x = 15
e) 4x + 2x = 68 - 219 : 216
6x = 60 => x = 10
f) 5x + x = 39 - 311 : 39
6x = 30 => x = 5
g) 7x - x = 521 : 519 + 3 x 22 - 70
6x = 36 => x = 6
h) 7x - 2x = 617 : 615 + 44 : 11
5x = 40 => x = 8
a. 8x+2x =25. 2 mũ 2
8x+2x=100
(8+2)x=100
10x=100
x=100:10
x=10
b.5x+2x=35
(5+2)x=35
7x=35
x=35:7
x=5
a) \(\left(4x+5\right):3-121:11=4\)
\(\Leftrightarrow\left(\dfrac{4x}{3}+\dfrac{5}{3}\right)-11=4\)
\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5}{3}-11=4\)
\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5}{3}-\dfrac{33}{3}=4\)
\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5-33}{3}=4\)
\(\Leftrightarrow\dfrac{4x}{3}-\dfrac{28}{3}=4\)
\(\Leftrightarrow\dfrac{4x}{3}=4+\dfrac{28}{3}\)
\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{12}{3}+\dfrac{28}{3}\)
\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{12+28}{3}\)
\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{40}{3}\)
\(\Leftrightarrow4x=\dfrac{40}{3}.3\)
\(\Leftrightarrow4x=40\)
\(\Leftrightarrow x=\dfrac{40}{4}=10\)
Vậy \(x=10\)
c) ( 2x + 1 )3 =125
=> (2x+1)3=53
=> 2x+1=5
=> 2x=4
=> x=2
vậy x=2
a) (3x +5)3 =121.(-11)
(3x +5)3 = -113
3x + 5 = -11
3x = -11 - 5
x = \(-\frac{16}{3}\)
b) 3.|2x +1| - 10= |-11|
3.|2x+1| = 11 + 10
|2x+1| = 7
\(\Rightarrow\orbr{\begin{cases}2x+1=7\\2x+1=-7\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-4\end{cases}}}\)
c) 100-(x -5)2 = (-6)2
(x-5)2 = 82
x-5 = 8
x = 13
\(\left(3x+5\right)^3=121\left(-11\right)\)
\(\Rightarrow\left(3x+5\right)^3=-1331=\left(-11\right)^3\)
\(\Rightarrow3x+5=-11\)
\(\Rightarrow3x=-16\)
\(\Rightarrow x=-\frac{16}{3}\)
\(3\left|2x+1\right|-10=\left|-11\right|\)
\(\Rightarrow\left|2x+1\right|=7\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=7\\2x+1=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=-4\end{cases}}\)
\(100-\left(x-5\right)^2=\left(-6\right)^2\)
\(\Rightarrow\left(x-5\right)^2=64=\left(\pm8\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=8\\x-5=-8\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=13\\x=-3\end{cases}}\)