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`@` `\text {Ans}`
`\downarrow`
\(1793\cdot\left(x\div1792\right)=0\)
`\Rightarrow x \div 1792 = 0 \div 1793`
`\Rightarrow x \div 1792 = 0`
`\Rightarrow x = 0. 1792`
`\Rightarrow x = 0`
Vậy, `x = 0.`
\(1793.\left(x:1792\right)=0\)
\(=>x:1792=0:1793\)
\(=>x:1792=0\)
\(=>x=0.1792\)
\(=>x=0\)
Tìm x biết:
a,x-5/7=1/9
b,2x/5=6/2x+1
c,11/8+13/6=85/x
d,2x-2/11=1.1/5
e,x/15=3/5+-2/3
f,x/182=-6/14.35/91
a, \(x\) - \(\dfrac{5}{7}\) = \(\dfrac{1}{9}\)
\(x\) = \(\dfrac{1}{9}\) + \(\dfrac{5}{7}\)
\(x\) = \(\dfrac{52}{63}\)
b, \(\dfrac{2x}{5}\) = \(\dfrac{6}{2x+1}\)
2\(x\).(2\(x\) + 1) = 30
4\(x^2\)+ 2\(x\) - 30 = 0
4\(x^2\) + 12\(x\) - 10\(x\) - 30 = 0
(4\(x^2\) + 12\(x\)) - (10\(x\) + 30) =0
4\(x\).(\(x\) + 3) - 10.(\(x\) +3) = 0
2 (\(x\) + 3).(2\(x\) - 5) = 0
\(\left[{}\begin{matrix}x+3=0\\2x-5=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-3\\x=\dfrac{5}{2}\end{matrix}\right.\)
Vậy \(x\) \(\in\) {-3; \(\dfrac{5}{2}\)}
b) 17x – ( -16x – 37) = 2x + 43
-> 33x +37 =2x +43
->31x=6
-> x= 6/31
c) -2x –3. (x – 17) = 34 – 2(-x + 25)
->-5x + 51= 2x-16
->7x= 67
x= 67/7
d) (-x - 6) (x + 9) = 0
Ta có (-x-6)= 0 hoặc (x+9)=0
-> x=-6 hoặc x=-9
1a) (2x - 6)(x + 2) = 0
=> \(\orbr{\begin{cases}2x-6=0\\x+2=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x=6\\x=-2\end{cases}}\)
=> \(\orbr{\begin{cases}x=3\\x=-2\end{cases}}\)
b) (x2 + 7)(x2 - 25) = 0
=> \(\orbr{\begin{cases}x^2+7=0\\x^2-25=0\end{cases}}\)
=> \(\orbr{\begin{cases}x^2=-7\\x^2=25\end{cases}}\)
=> x ko có giá trị vì x2 \(\ge\)0 mà x2= -7
hoặc x = \(\pm\)5
190 - 2 ( 2.X - 6 ) = 182
=> 2( 2.X - 6) = 190 - 182 = 8
=> 2.X - 6 = 8 : 2 = 4
=> 2.X = 4 + 6 = 10
=> X = 10 : 2 = 5
=> X = 5
a,\(\left(x-15\right):50+22=24\)
\(< =>\frac{\left(x-15\right)}{50}=2< =>x-15=100\)
\(< =>x=100+15=115\)
b,\(42-\left(2x+32\right)+12:2=6\)
\(< =>42-2x-32=0\)
\(< =>10-2x=0< =>x=\frac{10}{2}=5\)
Làm nốt :
c) \(134-2\left\{156-6\cdot\left[54-2\cdot\left(9+6\right)\right]\right\}\cdot x=86\)
=> 134 - 2{156 - 6 . [54 - 2 . 15]} . x = 86
=> 134 - 2{156 - 6 . [54 - 30]} . x = 86
=> 134 - 2{156 - 6. 24} . x = 86
=> 134 - 2{156 - 144} . x = 86
=> 134 - 2.12 . x = 86
=> 134 - 24 . x = 86
=> 24.x = 48
=> x = 2
Bài 2 : a) 120 : [21 - (4x - 4)] = 23.3
=> 120 : [21 - (4x - 4)] = 8.3
=> 120 : [21 - (4x - 4)] = 24
=> 21 - (4x - 4) = 5
=> 4x - 4 = 16
=> 4x = 20
=> x = 5
b) 3.[205 - (x - 9)] - 486 = 0
=> 3.[205 - (x - 9)] = 486
=> 205 - (x - 9) = 162
=> x - 9 = 205 - 162 = 43
=> x = 43 + 9 = 52
c) 204 - 2{200 - 5.[64 - 2.(11 + 6)]} . x = 4
=> 204 - 2{200 - 5.[64 - 2.17]} . x = 4
=> 204 - 2{200 - 5 .[64 - 34]}.x = 4
=> 204 - 2{200 - 5.30} . x = 4
=> 204 - 2{200 - 150}.x = 4
=> 204 - 2.50 . x = 4
=> 2.50.x = 200
=> 100.x = 200
=> x = 2
[(8x-14):2-2].31=341
=> (8x-14):2-2=341:31
=> (8x-14):2-2=11
=> (8x-14):2=11+2
=> (8x-14):2=13
=> 8x-14=13.2
=> 8x-14=26
=> 8x=26+14
=> 8x=40
=> x=40:8
=> x=5
4x+3=256
=> 4x+3=44
=> x+3=4
=> x=4-3
=> x=1
6+3x+2=87
=> 3x+2=87-6
=> 3x+2=81
=> 3x+2=34
=> x+2=4
=> x=4-2
=> x=2
1300:[120-(x-9)]=25
=> 120-(x-9)=1300:25
=> 120-(x-9)=52
=> x-9=120-52
=> x-9=68
=> x=68+9
=> x=77
a, 190 - 2(2x-6) = 182
=> 2 ( 2x - 6 ) = 8
=> 2x - 6 = 4
=> 2x = 10
=> x = 5
b, 1300 : [ 120 - ( x - 9 ) ] = 25
=> [ 120 -( x - 9 ) ] = 52
=> x - 9 = 68
=> x = 77
c, 1793 ( x : 1792 ) = 0
=> x : 1972 = 0
=> x = 0
a)
190-2(2x-6)=182
2(2x-6)=190-182
2(2x-6)=8
2x-6=8:2
2x-6=4
2x=4-6
2x=-2
x=-2:2
x=-1