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câu 1)
\(\dfrac{-12}{18}+\left(\dfrac{-21}{35}\right)=\dfrac{-19}{15}\)
câu 2)
\(-\dfrac{3}{21}+\dfrac{6}{42}=0\)
câu 3)
\(-\dfrac{18}{24}+\dfrac{15}{21}=-\dfrac{1}{28}\)
câu 4)
\(\dfrac{1}{6}+\dfrac{2}{5}=\dfrac{17}{30}\)
câu 5)
\(\dfrac{3}{5}+\left(-\dfrac{7}{4}\right)=-\dfrac{23}{20}\)
câu 6)
\(\left(-2\right)+\left(\dfrac{-5}{8}\right)=\dfrac{-21}{8}\)
câu 7)
\(\dfrac{1}{-8}+\left(-\dfrac{5}{9}\right)=-\dfrac{49}{72}\)
câu 8)
\(\dfrac{4}{13}+\dfrac{12}{39}=\dfrac{8}{13}\)
câu 9)
\(\dfrac{1}{21}+\dfrac{1}{28}=\dfrac{1}{12}\)
câu 10)
\(-\dfrac{3}{29}+\dfrac{16}{58}=\dfrac{5}{29}\)
câu 11)
\(\dfrac{8}{40}+\left(-\dfrac{36}{45}\right)=-\dfrac{3}{5}\)
câu 12)
\(-\dfrac{8}{18}+\left(-\dfrac{15}{27}\right)=-1\)
câu 13)
\(\dfrac{13}{30}+\left(-\dfrac{1}{5}\right)=\dfrac{7}{30}\)
câu 14)
\(\dfrac{2}{21}+\dfrac{1}{28}=\dfrac{11}{84}\)
câu 15)
\(5+\left(-\dfrac{3}{4}\right)=\dfrac{17}{4}\)
câu 16)
\(\dfrac{18}{24}+\dfrac{45}{-10}=-\dfrac{15}{4}\)
1)(-6-25).(-6+2)=-31*(-4)=124
2) \(\frac{7\cdot3-9}{-6}=\frac{12}{-6}=-2\)
3) (-5+19).(-4)=14*(-4)=-56
4) \(\frac{872}{-6\cdot2+4}=\frac{872}{-12+4}=\frac{872}{-8}=-109\)
5) -3*7-4*(-5)+19=-21+20+19=18
6)\(18-\frac{10}{2}-71=18-5-71=-58\)
7) \(\frac{115}{-5}\cdot\left(-3\right)-8=69-8=61\)
8) \(\left(6\cdot8-\frac{20}{5}\right)+3\cdot\left(-7\right)=48-4-21=23\)
a) 10-x-5=-5-7-11
=> 5 - x = -23
=> x = 28
b) |x| -3=0
=> |x| = 3
=> x = 3 hoặc x -3
c) ( 7-|x| ) .(2x-4)=0
=> 7 - |x| = 0 hoặc 2x - 4 = 0
=> |x| = 7 hoặc 2x = 4
=> x = 7 hoặc x = - 7 hoặc x = 2
c)2+3x=-15-19
=> 2 + 3x = -34
=> 3x = 36
=> x = 12
Ta có: \(A=1-2+3-4+5-6+7-8+9\)
\(=(1+9)-(2+8)+(3+7)-(4+6)+5\)
\(=10-10+10-10+5\)
\(=5\)
Vậy \(A=5\)
B = 12 - 14 + 16 - 18 + ... + 2008 - 2010
B = -2 + (-2)+ (-2)+ (-2) + ...+ (-2)
B = -2 . 100
B = -200
1) \(\left|4-2x\right|.\dfrac{1}{3}=\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}:\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}.3\)
\(\left|4-2x\right|=1\)
=>\(4-2x=\pm1\)
+)\(TH1:4-2x=1\) +)\(TH2:4-2x=-1\)
\(2x=4-1\) \(2x=4-\left(-1\right)\)
\(2x=3\) \(2x=4+1\)
\(x=3:2\) \(2x=5\)
\(x=1,5\) \(x=5:2\)
Vậy x=1,5 \(x=2,5\)
Vậy x=2,5
2) \(\left(-3\right)^2:\left|x+\left(-1\right)\right|=-3\)
\(9:\left|x+\left(-1\right)\right|=-3\)
\(\left|x+\left(-1\right)\right|=9:\left(-3\right)\)
\(\left|x+\left(-1\right)\right|=-3\)
=> \(x+\left(-1\right)\) sẽ không có giá trị nào ( Vì giá trị tuyệt đối luôn luôn lớn hơn hoặc bằng 0 )
Vậy x = \(\varnothing\)
`@` `\text {Ans}`
`\downarrow`
`9^8 \div 3^2`
`= (3^2)^8 \div 3^2`
`= 3^16 \div 3^2`
`=`\(3^{16-2}=3^{14}\)
_____
`3^7 * 27^5 * 81^3`
`= 3^7*(3^3)^5 * (3^4)^3`
`= 3^7 * 3^15 * 3^12`
`=`\(3^{7+15+12}\)
`= 3^34`
______
`36^5 \div 18^5`
`= (36 \div 18)^5`
`= 2^5 = 32`
______
`24*5^5 + 5^2*5^3`
`= 24*5^5 + 5^5`
`= 5^5*(24+1)`
`= 5^5 * 25`
`= 5^5*5^2`
`= 5^7`
______
`125^4 \div 5^8`
`= (5^3)^4 \div 5^8`
`= 5^12 \div 5^8`
`= 5^4`
_____
`@` Phép nâng lên lũy thừa: \(\left(a^m\right)^n=a^{m\cdot n}\)
`@` Chia lũy thừa cùng cơ số: \(a^m\div a^n=a^{m-n}\)
`@` Nhân lũy thừa cùng cơ số: \(a^m\cdot a^n=a^{m+n}\)
\(9^8:3^2\)
\(=\left(3^2\right)^8:3^2\)
\(=3^{16}:3^2\)
\(=3^{14}\)
=============
\(3^7\cdot27^5\cdot81^3\)
\(=3^7\cdot\left(3^3\right)^5\cdot\left(3^4\right)^3\)
\(=3^7\cdot3^{15}\cdot3^{12}\)
\(=3^{7+12+15}\)
\(=3^{34}\)
===============
\(36^5:18^5\)
\(=\left(36:18\right)^5\)
\(=2^5\)
\(=32\)
=============
\(24\cdot5^5+5^2\cdot5^3\)
\(=24\cdot5^5+5^5\)
\(=5^5\cdot\left(24+1\right)\)
\(=5^5\cdot25\)
\(=5^5\cdot5^2\)
\(=5^7\)
==============
\(125^4:5^8\)
\(=\left(5^3\right)^4:5^8\)
\(=5^{12}:5^8\)
\(=5^4\)