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2x . 26 . 24 = 23 . 260
2x + 6 + 4 = 23 + 60
2x + 10 = 263
=> x + 10 = 63
x = 63 - 10
x = 53
a/ 5x.52.53=52.540
5x.55=542
5x=537
x=37
b/ 2x.26.24=23.260
2x.210=263
2x=253
x=53
\(2^{x-5}=8\cdot2^{130}\)
\(2^{x-5}=2^3\cdot2^{130}=2^{133}\)
\(\Rightarrow x-5=133\)
\(\Rightarrow x=138\)
Vậy,........
2x-5=8.2130
2x-5=23.2130
2x-5=2133
=>x-5=133
x=133+5
x=128
k nha!
a) ( 15x +2.2\(^3\)) -4=10
\(\Rightarrow15x+2^4=14\)
\(\Rightarrow15x=14-16\)
\(\Rightarrow x=\left(-2\right):15\)
\(\Rightarrow x=-\frac{2}{15}\)
b)\(3x.15^5=15^6\)
\(\Rightarrow3x=15^6:15^5\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=\frac{15}{3}=5\)
a) \(\text{2(x-51)=2.2^2+20}\)
\(2\left(x-51\right)=2.4+20\)
\(2\left(x-51\right)=28\)
\(x-51=28\div2\)
\(x-51=14\)
\(x=14+51\)
\(\text{b)3.(x+1)-26=541}\)
\(3.\left(x+1\right)=541+26\)
\(3\cdot\left(x+1\right)=567\)
\(x+1=567\div3\)
\(x+1=189\)
\(x=189-1\)
\(x=188\)
\(x=65\)
\(\text{c)4(x-3)=7^2-1^10}\)
\(4\left(x-3\right)=49-1\)
\(4\left(x-3\right)=48\)
\(x-3=48\div4\)
\(x-3=12\)
\(x=12+3\)
\(x=15\)
\(\text{e)2x-138=2^3.3^2}\)
\(2x-138=8\cdot9\)
\(2x-138=72\)
\(2x=72+138\)
\(2x=210\)
\(x=210\div2\)
\(x=105\)
\(\text{f)(x-1)^4=16}\)
\(\left(x-1\right)^4=2^4\)
\(x-1=2\)
\(x=2+1\)
\(x=3\)
a, 2(x - 51) = 2.23 + 20
=> 2(x - 51) = 2.8 + 20
=> 2(x - 51) = 16 + 20
=> 2(x - 51) = 36
=> x - 51 = 18
=> x = 69
vậy_
b, 32(x + 4) - 52 = 5.22
=> 9(x + 4) - 25 = 5.4
=> 9x + 36 - 25 = 29
=> 9x + 9 = 29
=> 9x = 20
=> x = 20/9
vậy_
tìm x
a, 2.x -138=2³.3²
\(2.x-138=8.9\)
\(2.x-138=72\)
\(2.x=72+138\)
\(2.x=210\)
\(x=210:2\)
\(x=105\)
\(\Rightarrow x=105\)
b, 2x-5=8.2-130
Sai đề bài !
2.22x+43.4x=264
2.4x+64.4x=264
4xx(2+64)=264
4xx66=264
4x=264:66
4x=4
x=1
|x+5|<3
=>|x+5| E {0;1;2;}
=>x E {-5;-4;-3}
Bạn nhớ tích ch0 mình nha !
Tìm cặp số nguyên(x,y) biết
a) (2+x).( -1+ 2y)= 5
b) 3xy - y + 3x = 5
\(5^{x+1}-5^x=2.2^x+8.2^x\\ \Leftrightarrow5^x.5-5^x=2.2^x+8.2^x\\ \Leftrightarrow5^x\left(5-1\right)=2^x\left(2+8\right)\\ \Leftrightarrow5^x.4=2^x.10\\ \Leftrightarrow5^x:2^x=\dfrac{5}{2}\\ \Leftrightarrow\left(\dfrac{5}{2}\right)^x=\dfrac{5}{2}\\ \Rightarrow x=1\)