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Question

14⁴.49².21⁵.28³.18³

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Phạm Tuấn Đạt · Accepted Answer

Ta có :

$14^4.4^2.21^5.28^3.18^3$

$=\left(7.2\right)^{14}.\left(2^2\right)^2.\left(7.3\right)^5.\left(7.2^2\right)^3.\left(3^2.2\right)^3$

$=7^{14}.2^{14}.2^4.7^5.3^5.7^3.2^6.3^6.2^3$

$=\left(7^{14}.7^5.7^3\right)\left(2^{14}.2^4.2^6.2^3\right)\left(3^5.3^6\right)$

$=7^{22}.2^{27}.3^{11}$

Câu trả lời:

Ta có :

$14^4.4^2.21^5.28^3.18^3$

$=\left(7.2\right)^{14}.\left(2^2\right)^2.\left(7.3\right)^5.\left(7.2^2\right)^3.\left(3^2.2\right)^3$

$=7^{14}.2^{14}.2^4.7^5.3^5.7^3.2^6.3^6.2^3$

$=\left(7^{14}.7^5.7^3\right)\left(2^{14}.2^4.2^6.2^3\right)\left(3^5.3^6\right)$

$=7^{22}.2^{27}.3^{11}$