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NT
1
5 tháng 4 2021
Bài 1:
Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)
Vậy: \(x=\dfrac{4}{65}\)
5 tháng 4 2021
Bài 2:
a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)
\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)
\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)
\(=\dfrac{5366}{527}\)
HN
9 tháng 4 2020
1) 2763 +152 =2915
2) (-7) +(-14) = -21
3) (-35) + (-9) = -44
4) (-5) + (-248) = -253
5) (-23) + 105 = 82
6) 78 + (-123) = -45
7) 23 +(-13) = 10
8) (-23) +13 = -10
9) 26 + (-6) = 20
10) (-75) +50 = -25
11) 80 + (-220) = -140
12) (-23) + (-13) = -36
13) (-26) + (-6) = -32
14) (-75) + (-50) = -125
15) ❏-18❏ + (-12) = -17❏ -12
16)17 + ❏ - 33❏ = 17 -32❏
17) (-20) +❏ - 88❏ = -20 -87❏
18) ❏- 3❏+ ❏5❏ = ❏5❏ -2❏
19)❏-37❏+❏15❏ = ❏15❏ -36❏
20) ❏-37❏+(-❏15❏) = -❏15❏ - 36❏
21) (-❏-32❏) +❏5❏ = ❏5❏ -33❏
22) (-❏-22❏) + (-❏16❏) = -❏16❏ -23❏
23) (-23) +13 +(-17) +57 = 30
24) 14 +6 + (-9) + (-14) = -3
25) (-123 ) +❏-13❏+(-7) = -130-12❏
26) ❏0❏ + ❏45❏ +(-❏-455)❏+❏-796❏ = ❏45❏-❏\(^2\) -1250❏
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 1 2024
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 1 2024
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
\(1,2\cdot\dfrac{17}{23}+1\dfrac{1}{5}\cdot\dfrac{6}{23}\)
\(=1,2.\dfrac{17}{23}+\dfrac{6}{5}\cdot\dfrac{6}{23}\)
\(=1,2\cdot\dfrac{17}{23}+1,2\cdot\dfrac{6}{23}\)
\(=1,2.\left(\dfrac{17}{23}+\dfrac{6}{23}\right)\)
\(=1,2\cdot\dfrac{23}{23}\)
\(=1,2.1\)
\(=1,2\)
\(1,2\times\dfrac{17}{23}+1\dfrac{1}{5}\times\dfrac{6}{23}\\ =1,2\times\dfrac{17}{23}+1,2\times\dfrac{6}{23}\\ =1,2\times\left(\dfrac{17}{23}+\dfrac{6}{23}\right)\\ =1,2\times1\\ =1,2\)