K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

23 tháng 8 2017

\(a,2x^2-4xy+2y^2-8t^2\)

\(=2\left[\left(x^2-2xy+y^2\right)-4t^2\right]\)

\(=2\left[\left(x-y\right)^2-\left(2t^2\right)\right]-\)

\(=2\left(x-y+2t\right)\left(x-y-2t\right)\)

\(b,x^3+x+3x^2y+2xy^2+y^3+y\)

\(=\left(x^3+3x^2y+3xy^2+y^3\right)+\left(x+y\right)\)

\(=\left(x+y\right)^3+\left(x+y\right)\)

\(=\left(x+y\right)\left[\left(x+y\right)^2+1\right]\)

\(=\left(x+y\right)\left(x^2+2xy+y^2+1\right)\)

\(c,x^4-7x^2=x^2\left(x^2-7\right)\)

\(=x^2\left(x+\sqrt{7}\right)\left(x-\sqrt{7}\right)\)

Sửa đề:\(d,5x-5y-x^2+2xy-y^2\)

\(=5\left(x-y\right)-\left(x-y\right)^2\)

\(=\left(x-y\right)\left(5-x+y\right)\)

\(e,x^4+4x^3+4x^2-x^2y^2\)

\(=\left(x^4+4x^3+4x^2\right)-x^2y^2\)

\(=\left(x^2+2x\right)^2-\left(xy\right)^2\)

\(=\left(x^2+2x+xy\right)\left(x^2+2x-xy\right)\)

\(g,x^2-y^2-2y-1\)

\(=x^2-\left(y+1\right)^2\)

\(=\left(x+y+1\right)\left(x-y-1\right)\)

23 tháng 8 2017

a) \(2x^2-4xy+2y^2-8t^2=2\left(x^2-2xy+y^2-4t^2\right)\)

\(=2\left(\left(x-y\right)^2-\left(2t\right)^2\right)=2\left(x-y-2t\right)\left(x-y+2t\right)\)

b) \(x^3+x+3x^2y+3xy^2+y^3+y=\left(x^3+3x^2y+3xy^2+y^3\right)+\left(x+y\right)\)

\(=\left(x+y\right)^3+\left(x+y\right)=\left(x+y\right)^2\left(x+y\right)+\left(x+y\right)\)

\(=\left(x^2+2xy+y^2\right)\left(x+y\right)+\left(x+y\right)=\left(x^2+2xy+y^2+1\right)\left(x+y\right)\)

c) \(x^4-7x^2=\left(x^2\right)^2-\left(\sqrt{7}x\right)^2=\left(x^2-\sqrt{7}x\right)\left(x^2+\sqrt{7}x\right)\)

d) câu này hình như đề sai thì phải

e) \(x^4+4x^3+4x^2-x^2y^2=x^2\left(x^2+4x+4-y^2\right)\)

\(=x^2\left(\left(x+2\right)^2-y^2\right)=x^2\left(x+2-y\right)\left(x+2+y\right)\)

g) \(x^2-y^2-2y-1=x^2-\left(y^2+2y+1\right)=x^2-\left(y+1\right)^2\)

\(=\left(x-y-1\right)\left(x+y+1\right)\)

12 tháng 8 2015

a) x^4 - x^3 - x + 1 

= x^3 ( x - 1 ) - ( x- 1 )

= ( x^3 - 1 )(x - 1)

= ( x- 1 )^2 (x^2 + x +  1 )

 

12 tháng 8 2015

a)x4-x3-x+1

=x3(x-1)-(x-1)

=(x-1)(x3-1)

=(x-1)(x-1)(x2+x+1)

=(x-1)2(x2+x+1)

b)5x2-4x+20xy-8y

(sai đề)

 

12 tháng 7 2019

a,\(xy+3x-7y-21\)

\(=x\left(y+3\right)-7\left(y+3\right)\)

\(=\left(y+3\right)\left(x-7\right)\)

12 tháng 7 2019

\(b,2xy-15-6x+5y\)

\(=\left(2xy-6x\right)+\left(-15+5y\right)\)

\(=2x\left(y-3\right)-5\left(3-y\right)\)

\(=2x\left(y-3\right)+5\left(y-3\right)\)

\(=\left(y-3\right)\left(2x+5\right)\)

6 tháng 12 2017

a) \(=\left(x-2y\right)\left(x^2+5x\right)\)

b) \(=\left(x-1\right)\left(x^2+2x+1\right)=\left(x-1\right)\left(x+1\right)^2\)

c) \(=\left(x^2+1-2x\right)\left(x^2+1+2x\right)\)

    \(=\left(x^2-2x+1\right)\left(x^2+2x+1\right)\)

    \(=\left(x-1\right)^2\left(x+1\right)^2\)

d) \(=3\left(x+3\right)-\left(x-3\right)\left(x+3\right)\)

     \(=\left(x+3\right)\left(3-x+3\right)\)

     \(=\left(x+3\right)\left(6-x\right)\)

e) \(=\left(x^2-\frac{1}{3}x\right)\left(x^2+\frac{1}{3}x\right)\)

f) \(=2x\left(x-y\right)-16\left(x-y\right)\)

    \(=2\left(x-y\right)\left(x-8\right)\)

  

11 tháng 10 2020

a) \(4x^3y-12x^2y^3-8x^4y^3\)

\(=4x^2y\left(x-3y^2-2x^2y^2\right)\)

b) \(2x^2+4x+2-2y^2\)

\(=2\left(x^2+2x+1-y^2\right)\)

\(=2\left[\left(x+1\right)^2-y^2\right]\)

\(=2\left(x-y+1\right)\left(x+y+1\right)\)

c) \(x^3-2x^2+x-xy^2\)

\(=x\left(x^2-2x+1-y^2\right)\)

\(=x\left[\left(x-1\right)^2-y^2\right]\)

\(=x\left(x-y-1\right)\left(x+y-1\right)\)

d) \(x\left(x-2y\right)+3\left(2y-x\right)\)

\(=x\left(x-2y\right)-3\left(x-2y\right)\)

\(=\left(x-3\right)\left(x-2y\right)\)

e) \(x^2+4\)

\(=\left(x^4+4x^2+4\right)-4x^2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2\)

\(=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)

f) \(5x^2-7x-6\)

\(=\left(5x^2-10x\right)+\left(3x-6\right)\)

\(=5x\left(x-2\right)+3\left(x-2\right)\)

\(=\left(5x+3\right)\left(x-2\right)\)