Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(2010^{100}+2010^{99}\)
\(=2010^{99}\left(2010+1\right)\)
\(=2010^{99}.2011⋮2011\left(dpcm\right)\)
b) \(3^{1994}+3^{1993}-3^{1992}\)
\(=3^{1992}\left(3^2+3-1\right)\)
\(=3^{1992}.11⋮11\left(dpcm\right)\)
c) \(4^{13}+32^5-8^8\)
\(=\left(2^2\right)^{13}+\left(2^5\right)^5-\left(2^3\right)^8\)
\(=2^{26}+2^{25}-2^{24}\)
\(=2^{24}\left(2^2+2-1\right)\)
\(=2^{24}.5⋮5\left(dpcm\right)\)
a.
165 + 215 = (24)5 + 215 = 220 + 215 = 215 x (25 + 1) = 215 x (32 + 1) = 215 x 33
Vậy 1615 + 215 chia hết cho 33
b.
817 - 279 - 913 = (34)7 - (33)9 - (32)13 = 328 - 327 - 326 = 322 x (36 - 35 - 34) = 322 x 405
Vậy 817 - 279 - 913 chia hết cho 405
a)\(81^7-27^9-9^{13}=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\)
\(=3^{28}-3^{27}-3^{26}=3^{24}\left(3^4-3^3-3^2\right)\)
\(=3^{24}.45⋮45\)
\(\Rightarrow81^7-27^9-9^{13}⋮45\left(đpcm\right)\)
a) \(2010^{100}\)+ \(2010^{99}\)
= \(2010^{99}\)\(\left(2010+1\right)\)
= \(2010^{99}\). \(2011\)chia hết cho 2011
Vậy ...................................
b) \(3^{1994}\)+ \(3^{1993}\)- \(3^{1992}\)
= \(3^{1992}\)\(\left(3^2+3-1\right)\)
= \(3^{1992}\). \(11\)
Vậy .......................
c) \(4^{13}\)+ \(32^5\)- \(8^8\)
= \(\left(2^2\right)^{13}\)+ \(\left(2^5\right)^5\)- \(\left(2^3\right)^8\)
= \(2^{26}\)- \(2^{25}\)- \(2^{24}\)
= \(2^{24}\). \(\left(2^2+2-1\right)\)
= \(2^{24}\). \(5\)
Vậy .......................
3 cau 3 nhe
a)
\(=2010^{99}\left(2010+1\right)\)
\(=2010^{99}.2011\)
cung thay chia het ro nhi
b)
\(=3^{1992}\left(3^2+3-1\right)\)
\(=3^{1992}.11\)
cung thay chia het ro nhi
c)
\(=\left(2^2\right)^{13}+\left(2^5\right)^5-\left(2^3\right)^8\)
\(=2^{26}+2^{25}-2^{24}\)
\(=2^{24}\left(2^2+2-1\right)\)
\(=2^{24}.5\)
cung thay chia het ro nhi
cho 3 nhe
a: \(\Leftrightarrow3^n:27^n=\dfrac{1}{9}\)
\(\Leftrightarrow\left(\dfrac{1}{9}\right)^n=\dfrac{1}{9}\)
hay n=1
b: \(\Leftrightarrow3^n\cdot3^2=3^8\)
=>n+2=8
hay n=6
c: \(\Leftrightarrow2^n\cdot\dfrac{9}{2}=9\cdot2^5\)
\(\Leftrightarrow2^n=2^6\)
hay n=6
d: \(\Leftrightarrow8^n=512\)
hay n=3
1) 3^1994+4^1993-3^1992
= 3^1992.(9+3-1)=3^1992.11 chia hết cho 11
=> 3^1994+3^1993-3^1992 chia hết cho 11
Có ai bt bài 2 ko z