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\(\frac{8}{3}:x=\frac{16}{9}:\frac{8}{3}\)
\(\frac{8}{3}:x=\frac{16}{9}.\frac{3}{8}\)
\(\frac{8}{3}:x=\frac{2}{3}\)
\(x=\frac{8}{3}:\frac{2}{3}\)
\(x=\frac{8}{3}.\frac{3}{2}\)
\(x=4\)
Vậy x = 4
a)(x-8)(x3+8)=0
<=>x-8=0 hoặc x3+8=0
<=>x=8 hoặc x3=-8
<=>x=8 hoặc x=-2
b)(4x-3)-(x+5)=3(10-x)
<=>4x-3-x-5=30-3x
<=>(4x-x)+(-3-5)=30-3x
<=>3x-8=30-3x
<=>6x=38
<=>x=\(\frac{38}{6}=\frac{19}{3}\)
a) => x - 8 = 0 hoặc x3 + 8 = 0
+) x - 8 = 0 => x = 8
+) x3 + 8 = 0 => x3 = - 8 = (-2)3 => x = -2
Vậy x = 8; -2
b) => 4x - 3 - x - 5 = 30 - 3x
=> 3x - 8 = 30 - 3x
=> 3x + 3x = 30 + 8
=> 6x = 38 => x = 38/6 = 19/3
Vậy x = 19/3
a) => x - 8 = 0 hoặc x3 + 8 = 0
+) x - 8 = 0 => x = 8
+) x3 + 8 = 0 => x3 = - 8 = (-2)3 => x = -2
Vậy x = 8; -2
b) => 4x - 3 - x - 5 = 30 - 3x
=> 3x - 8 = 30 - 3x
=> 3x + 3x = 30 + 8
=> 6x = 38 => x = 38/6 = 19/3
Vậy x = 19/3
\(\frac{x+3}{-8}=\frac{-18}{x+3}\Leftrightarrow\left(x+3\right)\left(x+3\right)=\left(-18\right).\left(-8\right)=144\)
\(\Rightarrow\left(x+3\right)^2=144=12^2\Leftrightarrow x+3=12\)
\(\Rightarrow x=12-3=9\) Vậy \(x=9\)
Ta có: \(\frac{x+3}{-8}=\frac{-18}{x+3}\)
\(\Rightarrow\left(x+3\right).\left(x+3\right)=-18.\left(-8\right)\)
\(\Rightarrow\left(x+3\right)^2=144\)
\(\Rightarrow\left(x+3\right)^2=\left(\pm12\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x+3=12\\x+3=-12\end{cases}\Rightarrow\orbr{\begin{cases}x=9\\x=-15\end{cases}}}\)
\(\Rightarrow x\in\left\{-15;9\right\}\)
_Học tốt-.-_
a) \(\left(x-8\right)\left(x^2+8\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-8=0\\x^2+8=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=8\\x^2=-8\left(loai\right)\end{cases}}\)
Vậy x=8
b) \(\left(4x-3\right)-\left(x+5\right)=3.\left(10-x\right)\)
\(\Leftrightarrow4x-3-x-5=30-3x\)
\(\Leftrightarrow4x-x+3x=30+5+3\)
\(\Leftrightarrow6x=38\)
\(\Leftrightarrow x=\frac{19}{3}\)
Vaayjh\ ...
a) \(6.8^{x-1}+8^{x+1}=6.8^{19}+8^{21}\)
\(\Rightarrow x-1+x+1=19+21\)
\(=2x=40\)
\(\Rightarrow x=20\)
b) \(4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(\Rightarrow x-1+x+2=6+9\)
\(\Rightarrow2x+1=15\)
\(\Rightarrow2x=14\)
\(\Rightarrow x=7\)
a)( x - 8 ).( x3 + 8 ) =0
=>x-8=0 hoặc x3+8=0
=>x=8 hoặc x=-2
b)( 4x - 3 ) - ( x + 5) = 3.(10 - x)
<=>3x-8=-3(x-10)
=>3x-8=30-3x
=>6x=38
=>x=\(\frac{19}{3}\)
Xét 3 trường hợp:
TH1: x < 1
TH2: x > 3
TH3: \(1\le x<3\)
tự làm mỗi trường hợp nha
<=>(1.2x)^3=(-2)^3
<=>1.2x=-2
<=>2x=-2
<=>x=-2:2
<=>x=-1
Vậy x=-1
<3 <3