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1.(3x-1/4)^2=36
(3x-1/4)^2=6^2
3x-1/4 =6
3x =6+1/4
3x = 25/4
x =25/4:3
x =25/12
2.(1/4-2x)^3=8
(1/4-2x)^3=2^3
1/4-2x =2
2x =1/4-2
2x =-7/4
x =-7/8
3.(5-7/2x)^2=25
(5-7/2x)^2=5^2
5-7/2x =5
7/2x =0
x =0
4.x+(1/4)^2=25
x+1/16 =25
x =25-1/16
x =399/16
7.(2/5x-3/4)^2=1/9
(2/5x-3/4)^2=(1/3)^2
2/5x-3/4 =1/3
2/5x =1/3+3/4
2/5x =13/12
x =13/12:2/5
x =65/24
8.(3/7-x)^2=1/49
(3/7-x)^2=(1/7)^2
3/7-x =1/7
x =3/7-1/7
x =2/7
9.(2/3x+1/4)^3=125
(2/3x+1/4)^3=5^3
2/3x+1/4 =5
2/3x =5-1/4
2/3x =19/4
x =19/4:2/3
x =57/8
10.(-3/4x+1/4)^2=25/16
(-3/4x+1/4)^2=(5/4)^2
-3/4x+1/4 =5/4
-3/4x =5/4-1/4
-3/4x =1
x =1:-3/4
x =-4/3
11.2.(x+1/4)^2=1/4
2x^2+1/8 =1/4
2x^2 =1/4-1/8
2x^2 =1/8
x^2 =1/8:2
x^2 =1/16
x =1/4
\(A=3\left(1+3+3^2\right)+3^4\left(1+3+3^2\right)+3^7\left(1+3+3^2\right)\)
\(=\left(1+3+3^2\right)\left(3+3^4+3^7\right)=13\left(3+3^4+3^7\right)⋮13\) (đpcm)
Lời giải:
Ta có:
\(A=(3+3^2+3^3)+(3^4+3^5+3^6)+(3^7+3^8+3^9)\)
\(=(3.1+3.3+3.9)+(3^4.1+3^4.3+3^4.9)+(3^7.1+3^7.3+3^7.9)\)
\(=3.(1+3+9)+3^4\left(1+3+9\right)+3^7.\left(1+3+9\right)\)
\(=3.13+3^4.13+3^7.13\)
\(=13.(3+3^4+3^7)\) ⋮ 13 . Vậy: A ⋮ 13
Chúc bạn học tốt!Tick cho mình nhé!
câu1
\(x+30\%=-1,3\)
\(x+\frac{3}{10}=\frac{-13}{10}\)
\(x=\frac{-13}{10}-\frac{3}{10}\)
\(x=\frac{-10}{10}=-1\)