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\(\left(\frac{4}{5}\right)\cdot2x=\frac{625}{256}-7\)
\(\left(\frac{4}{5}\right)\cdot2x=-\frac{1167}{256}\)
\(\frac{4}{5}\cdot x=-\frac{1167}{256}\div2\)
\(\frac{4}{5}\cdot x=-\frac{1167}{512}\)
\(x=-\frac{1167}{512}\div\frac{4}{5}\)
\(x=-2,849121094\)
\(\frac{4}{5}\times2x=\frac{625}{256}-7=-\frac{1167}{256}\)
\(\Rightarrow2x=\left(-\frac{1167}{256}\right):\frac{4}{5}=-\frac{5835}{1024}\)
\(\Rightarrow x=\left(-\frac{5835}{1024}\right):2=-2,849121094\)
d, \(=>\left(\frac{4}{5}\right)^{2x+7}=\left(\frac{4}{5}\right)^4.\)
=> \(2x+7=4\)
=> 2x= -3
=> x=-3/2 . Vậy x=-3/2
e, => \(\frac{7^x.7^2+7^x.7+7^x}{57}=\frac{5^{2x}+5^{2x}.5+5^{2x}.5^2}{131}.\)
=> \(\frac{7^x\left(7^2+7+1\right)}{57}=\frac{5^{2x}\left(1+5+5^2\right)}{131}\)
= > \(\frac{7^x.57}{57}=\frac{5^{2x}.131}{131}\)
=> \(7^x=5^{2x}\)
Đến đoạn này là mik nghĩ không ra nhé
Cô làm tiếp giúp Linh Đan:
\(7^x=5^{2x}\Rightarrow7^x=25^x\Rightarrow\frac{7^x}{25^x}=1\Rightarrow\left(\frac{7}{25}\right)^x=1\Rightarrow x=0\)
a, (x-1) . 0,5 = 7,5 : (x-1)
=> = ( x - 1 ) 0,5 = \(\frac{x-1}{2}\)
\(=\frac{7,5}{x-1}=\frac{15}{2\left(x-1\right)}\)
=> x = - 1 \(\sqrt{15}\)
x = \(\sqrt{15+1}\)
đề sao sao ý
\(T=\left(1-\frac{1}{4}\right).\left(1-\frac{1}{9}\right).\left(1-\frac{1}{16}\right)...\left(1-\frac{1}{576}\right).\left(1-\frac{1}{625}\right)\)
\(T=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{575}{576}.\frac{624}{625}\)
\(T=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}...\frac{23.25}{24.24}.\frac{24.26}{25.25}\)
\(T=\frac{1.2.3...23.24}{2.3.4...24.25}.\frac{3.4.5...25.26}{2.3.4...24.25}\)
\(T=\frac{1}{25}.\frac{26}{2}=\frac{1}{25}.13=\frac{13}{25}\)
\(\left(\frac{1}{3}-1,35x\right)^4=\frac{625}{256}\)
\(\left(\frac{1}{3}-1,35x\right)^4=\left(\frac{5}{4}\right)^4\)
\(\Rightarrow\frac{1}{3}-1,35x=\frac{5}{4}\)
\(1,35x=\frac{1}{3}-\frac{5}{4}\)
\(1,35x=\frac{-11}{12}\)
\(x=\frac{-11}{12}:1,35\)
\(x=\frac{-55}{81}\)
\(\left(\frac{1}{3}-1,35x\right)^4=\frac{625}{256}\)
\(\left(\frac{1}{3}-\frac{27}{20}\cdot x\right)^4=\frac{625}{256}\)
\(\left(\frac{1}{3}-\frac{27}{20}\cdot x\right)^4=\left(\frac{5}{4}\right)^4\)
\(\Rightarrow\left(\frac{1}{3}-\frac{27}{20}\cdot x\right)=\left(\frac{5}{4}\right)^4\)vì \(\left(\frac{5}{4}\right)^4=\frac{625}{256}\)
còn lại bạn tự tính nhé