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a) Ta có: 3.4 = 2.6
\(\Rightarrow\frac{3}{2}=\frac{6}{4};\)\(\frac{3}{6}=\frac{2}{4};\)\(\frac{4}{2}=\frac{6}{3};\)\(\frac{4}{6}=\frac{2}{3}\)
b) Ta có: 14.15 = 10.21
\(\Rightarrow\frac{14}{10}=\frac{21}{15};\)\(\frac{14}{21}=\frac{10}{15};\)\(\frac{15}{10}=\frac{21}{14};\)\(\frac{15}{21}=\frac{10}{14}\)
c) Ta có: AB.CD = 2.3
\(\Rightarrow\frac{AB}{2}=\frac{3}{CD};\)\(\frac{AB}{3}=\frac{2}{CD};\)\(\frac{CD}{2}=\frac{3}{AB};\)\(\frac{CD}{3}=\frac{2}{AB}\)
d) Ta có: A.AB = 5.MN
\(\Rightarrow\frac{A}{5}=\frac{MN}{AB};\)\(\frac{A}{MN}=\frac{5}{AB};\)\(\frac{AB}{5}=\frac{MN}{A};\)\(\frac{AB}{MN}=\frac{5}{A}\)
a)3.4=2.6
=\(\frac{3}{2}=\frac{6}{4};\frac{3}{6}=\frac{2}{4};\frac{2}{3}=\frac{4}{6};\frac{6}{3}=\frac{4}{2}\)
b)14.15=10.21
=\(\frac{14}{10}=\frac{21}{15};\frac{14}{21}=\frac{10}{15};\frac{15}{10}=\frac{21}{14};\frac{15}{21}=\frac{10}{14}\)
c)AB.CD=2.3
=\(\frac{AB}{2}=\frac{3}{CD};\frac{AB}{3}=\frac{2}{CD};\frac{CD}{2}=\frac{3}{AB};\frac{CD}{3}=\frac{2}{AB}\)
D)A.AB=5.MN
=\(\frac{A}{5}=\frac{MN}{AB};\frac{A}{MN}=\frac{5}{AB};\frac{AB}{5}=\frac{MN}{A};\frac{AB}{MN}=\frac{5}{A}\)
\(\frac{2}{3}=\frac{4}{6}\left(1\right)\)
\(\frac{2}{4}=\frac{3}{6}\left(2\right)\)
\(\frac{3}{2}=\frac{6}{4}\left(3\right)\)
\(\frac{4}{2}=\frac{6}{3}\left(4\right)\)
Ticks nha
\(1.\)
\(a,\)
\(7.\left(-28\right)=\left(-49\right).4\)
Ta có : \(\frac{7}{-49}=\frac{4}{-28}\) \(\frac{-28}{4}=\frac{-49}{7}\)
\(\frac{7}{4}=\frac{-49}{-28}\) \(\frac{-28}{-49}=\frac{4}{7}\)
\(b,\)
\(0,36.4,25=0,9.1,7\)
Ta có : \(\frac{0,36}{0,9}=\frac{1,7}{4,25}\) \(\frac{0,36}{1,7}=\frac{0,9}{4,25}\)
\(\frac{4,25}{0,9}=\frac{1,7}{0,36}\) \(\frac{4,25}{1,7}=\frac{0,9}{0,36}\)
