Question

[Thảo Trần]

Giúp mik vs mik tik cho ạ.

Answer 1

[Nguyễn Thái Thịnh]

\(b,\left|x+\dfrac{1}{2}\right|-\dfrac{3}{4}=\dfrac{5}{8}\)

\(\Rightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{11}{8}\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{11}{8}\\x+\dfrac{1}{2}=-\dfrac{11}{8}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{8}\\x=-\dfrac{15}{8}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{7}{8};-\dfrac{15}{8}\right\}\)

Answer 2

[Nguyễn Lê Phước Thịnh]

\(\Leftrightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{11}{8}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{11}{8}\\x+\dfrac{1}{2}=-\dfrac{11}{8}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{8}\\x=-\dfrac{15}{8}\end{matrix}\right.\)