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a.
\(5x^2\left(x-2y\right)-15x\left(x-2y\right)\)
\(=\left(x-2y\right)\left(5x^2-15x\right)\)
\(=5x\left(x-2y\right)\left(x-3\right)\)
b.
\(3\left(x-y\right)-5x\left(y-x\right)\)
\(=3\left(x-y\right)+5x\left(x-y\right)\)
\(=\left(x-y\right)\left(3+5x\right)\)
4x(x-2y)+8y(2y-x)
=4x(x-2y)-8y(x-2y)
=(4x-8y)(x-2y)
=4(x-2y)(x-2y)
=4(x-2y)^2
\(4x\left(x-2y\right)+8y\left(2y-x\right)\)
\(=\left(x-2y\right)\left(4x-8y\right)\)
\(=\left(x-2y\right)\left(x-2y\right).4\)\(=\left(x-2y\right)^2\)
\(\left(x+1\right)^4+\left(x^2+x+1\right)^2\)
\(=\left(x+1\right)^4+x^2\left(x+1\right)^2+2x\left(x+1\right)+1\)
\(=\left(x+1\right)^2.\left(2x^2+2x+1\right)+\left(2x^2+2x+1\right)\)
\(=\left(2x^2+2x+1\right)\left(x^2+2x+2\right)\)
\(a,3x-6y=3\left(x-2y\right)\)
\(b,\frac{2}{5}x^2+5x^3+x^2y=x^2\left(\frac{2}{5}+5x+y\right)\)
Sửa đề: \(x\left(x-3\right)+2y\left(2y-3\right)+4xy+19\)
a: \(x\left(x-3\right)+2y\left(2y-3\right)+4xy+19\)
\(=x^2-3x+4y^2-6y+4xy+19\)
\(=\left(x^2+4xy+4y^2\right)-3\left(x+2y\right)+19\)
\(=\left(x+2y\right)^2-3\left(x+2y\right)+19\)
\(=\left(-5\right)^2-3\cdot\left(-5\right)+19\)
=25+15+19=59
b: \(=x^3+x^2+8y^3+4y^2+2xy\left[3\left(x+2y\right)+2\right]+70\)
\(=x^3+8y^3+x^2+4y^2+2xy\cdot\left[3\cdot\left(-5\right)+2\right]+70\)
\(=\left(x+2y\right)^3-3\cdot x\cdot2y\left(x+2y\right)+\left(x+2y\right)^2-4xy+2xy\cdot\left(-13\right)+70\)
\(=\left(-5\right)^3+\left(-5\right)^2-6xy\cdot\left(-5\right)-4xy-26xy\)+70
\(=-125+25+70=-30\)
A.(x+2y).(x+2y-1) = x^2 +4xy + 4y^2 - x - 2y
B. (x-2y).(x+2y-1) = x^2 - x - 4y^2 + 2y
C. (x-2y).(x-2y+1) = x^2 - 4xy + 4y^2 + x - 2y
D.(x+2y).(x-2y) = x^2 - 4y^2
=>....