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a) \(4\frac{7}{10}< 6\frac{7}{10}\)(4 < 6)
b) \(3\frac{4}{15}< 3\frac{11}{15}\)(4/15 < 11/15)
c) \(5\frac{1}{9}>2\frac{2}{5}\)(5 > 2)
d) \(2\frac{2}{3}=2\frac{10}{15}\)(10/15 = 2/3)
1, 53/51 + 1,75 + 61/8 + 41/4 + 3,875 - 3,4
53/51 + 7/4 + 61/8 + 41/4 + 31/8 - 17/5
53/51 + 7/4 + 61/8 + 31/8 + 41/4 - 17/5
53/51 + 7/4 + 23/2 + 41/4 - 17/5
53/51 + 7/4 + 41/4 + +23/2-17/5
53/51 + 12 + 41/4 + 23/2
= 7097/204
1. \(\frac{9}{30}=\frac{3}{10};\frac{98}{80}=\frac{49}{40};\frac{15}{1000}=\frac{3}{200}\)
Vì \(200⋮10;200⋮40\)
=> BCNN(10; 40; 200) = 200
200 : 10 = 20
200 : 40 = 5
=> \(\frac{3}{10}=\frac{3\cdot20}{10\cdot20}=\frac{60}{200}\), \(\frac{49}{40}=\frac{49\cdot5}{40\cdot5}=\frac{245}{200}\)
Gọi tổng trên là A.Ta có
\(A=\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
\(2A=\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}+\frac{2}{195}\)
\(2A=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}+\frac{2}{13.15}\)
\(2A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}\)
\(2A=\frac{1}{3}-\frac{1}{15}\)
\(2A=\frac{5}{15}-\frac{1}{15}\)
\(2A=\frac{4}{15}\)
\(A=\frac{4}{15}:2\)
\(A=\frac{2}{15}\)
a: \(\Leftrightarrow\left(\dfrac{13}{4}:x\right)\cdot\left(-\dfrac{5}{4}\right)=\dfrac{-10}{6}-\dfrac{5}{6}=\dfrac{-15}{6}=\dfrac{-5}{2}\)
\(\Leftrightarrow\dfrac{13}{4}:x=\dfrac{5}{2}\cdot\dfrac{5}{4}=\dfrac{25}{8}\)
hay \(x=\dfrac{13}{4}:\dfrac{25}{8}=\dfrac{13}{4}\cdot\dfrac{8}{25}=\dfrac{26}{25}\)
b: \(\Leftrightarrow\dfrac{3}{4}:x=\dfrac{11}{36}-\dfrac{1}{4}=\dfrac{2}{36}=\dfrac{1}{18}\)
=>\(x=\dfrac{3}{4}:\dfrac{1}{18}=\dfrac{54}{4}=\dfrac{27}{2}\)
c: \(\Leftrightarrow\left(-\dfrac{6}{5}+x\right):\left(-3.6\right)=-\dfrac{7}{4}+\dfrac{1}{4}\cdot8=\dfrac{1}{4}\)
=>x-6/5=-9/10
=>x=3/10
a/\(2\frac{1}{3}=\frac{2.3+1}{3}=\frac{7}{3}\)
\(4\frac{2}{5}=\frac{4.5+2}{5}=\frac{22}{5}\)
\(3\frac{1}{4}=\frac{3.4+1}{4}=\frac{13}{4}\)
\(9\frac{5}{7}=\frac{9.7+5}{7}=\frac{68}{7}\)
\(11\frac{3}{10}=\frac{11.10+3}{10}=\frac{113}{10}\)
b/\(5\frac{2}{17}=\frac{5.17+2}{17}=\frac{87}{17}\)
\(3\frac{6}{23}=\frac{3.23+6}{23}=\frac{75}{23}\)
\(7\frac{4}{9}=\frac{7.9+4}{9}=\frac{67}{9}\)
\(121\frac{15}{100}=\frac{121.100+15}{100}=\frac{12115}{100}\)
\(8\frac{3}{7}=\frac{8.7+3}{7}=\frac{59}{7}\)