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4 tháng 2 2020

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4 tháng 2 2020

Thui khỏi bt lm òi * nhắn lun ko bt cho nhanh lại cn lm màu *

19 tháng 1 2022

TL :

Gọi số cạnh của khối đa diện là \(C\), số đỉnh là \(Đ\). Vì mỗi đỉnh là đỉnh chung của ba cạnh và mỗi cạnh có \(2\)đỉnh nên \(3Đ=2C\)do đó \(Đ\) là sỗ chẵn.

HT

19 tháng 1 2022

Gọi số cạnh của khối đa diện là C, số đỉnh là Đ. Vì mỗi đỉnh là đỉnh chung của ba cạnh và mỗi cạnh có 2 đỉnh nên 3Đ=2C do đó Đ là sỗ chẵn.

31 tháng 5 2017

Cho khối đa diện G có các đỉnh là  lần lượt là số các mặt của H nhận chúng làm đỉnh chung. Tổng số các cạnh của G là:

 

tự nhiên lẻ nên tổng của chúng là số chẵn khi n chẵn.

Ví dụ: Hình chóp ngũ giác  là đỉnh chung của 5 mặt bên. Mỗi đỉnh

B 1 , B 2 , B 3 , B 4 , B 5 , B 6  là đỉnh chung của ba mặt (hình trên).

Giải bài 2 trang 12 sgk Hình học 12 | Để học tốt Toán 12

 

1 tháng 4 2017

Giả sử đa diện (H) có các đỉnh là A1, … Ad gọi m1, … md lần lượt là số các mặt của (H) nhận chúng là đỉnh chung. Như vậy mỗi đỉnh Ak có mk cạnh đi qua. Do mỗi cạnh của (H) là cạnh chung của đúng hai mặt nên tổng số các cạnh của H bằng

c=12(m1+m2+...+md)c=12(m1+m2+...+md)

Vì c là số nguyên, m1, … md là những số lẻ nên Đ phải là số chẵn. Ví dụ : Số đỉnh của hình chóp ngũ giác bằng sáu.


10 tháng 11 2021

Giả sử đa diện (H)(H) có các đỉnh là A1,…AdA1,…Ad, gọi m1,…mdm1,…md lần lượt là số các mặt của (H)(H) nhận chúng là đỉnh chung, ở đó m1,…mdm1,…md là những số lẻ.

Như vậy mỗi đỉnh AkAk có mkmk cạnh đi qua.

Ta có: đỉnh A1A1 có m1m1 cạnh đi qua.

đỉnh A2A2 có m2m2 cạnh đi qua.

...

đỉnh AdAd có mdmd cạnh đi qua.

Do đó số các cạnh (có thể trùng nhau) của đa diện là m1+m2+...+mdm1+m2+...+md.

Tuy nhiên, do mỗi cạnh là cạnh chung của đúng hai mặt nên số cạnh ở trên được đếm hai lần.

Vậy số cạnh thực tế của (H)(H) bằng

c=12(m1+m2+...+md)c=12(m1+m2+...+md)      

Vì cc là số nguyên, m1,…mdm1,…md là những số lẻ nên dd phải là số chẵn.

Ví dụ : Hình chóp ngũ giác.

Đỉnh S là đỉnh chung của 5 mặt, tất cả các đỉnh còn lại là đỉnh chung của 3 mặt, hình chóp ngũ giác có 6 đỉnh

giup mình cày Sp vơi

25 tháng 4 2019

Lấy một đỉnh B tùy ý của hình đa diện (H). Gọi M 1  là một mặt của hình đa diện (H) chứa B. Gọi A, B, C là ba đỉnh liên tiếp của  M 1 . Khi đó AB, BC là hai cạnh của (H). Gọi  M 2  là mặt khác với  M 1  và có chung cạnh AB với  M 1 . Khi đó  M 2  còn có ít nhất một đỉnh D sao cho A, B, D là ba đỉnh khác nhau liên tiếp của  M 2 . Nếu D ≡ C thì  M 1  và  M 2  có hai cạnh chung AB và BC, điều này vô lí. Vậy D phải khác C. Do đó qua đỉnh B có ít nhất ba cạnh BA, BC và BD.

20 tháng 5 2017

Khối đa diện

31 tháng 8 2018

Đáp án C

Ta có 3d = 3m = 2c, suy ra C đúng.

17 tháng 3 2017

Chọn C.

Dựa vào định nghĩa khối đa diện. Mỗi cạnh là cạnh chung của đúng hai mặt.

5 tháng 2 2020

CÂU NÀY BÀI MẤY SÁCH LỚP 12 VẬY BẠN

5 tháng 2 2020

Câu này ko có trong sách lớp 12 đâu vì cô mk giao mà....