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\(\Leftrightarrow\frac{2\sqrt{x}-9}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\)\(-\)\(\frac{\sqrt{x}+3}{\sqrt{x}-2}\)\(+\)\(\frac{2\sqrt{x}+1}{\sqrt{x}-3}\)
\(\Leftrightarrow\frac{2\sqrt{x}-9}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\)\(-\)\(\frac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\)\(+\)\(\frac{\left(2\sqrt{x}+1\right)\left(\sqrt{x}-2\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\)
\(\Leftrightarrow\frac{2\sqrt{x}-9-x+3\sqrt{x}-3\sqrt{x}+9+2x-4\sqrt{x}+\sqrt{x}-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\)
\(\Leftrightarrow\frac{-\sqrt{x}+x-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\)
\(A=15+12+4\sqrt{45}+12\sqrt{5}=27+24\sqrt{5}\)
\(B=\left(2\sqrt{3}+6\sqrt{3}\right).\frac{\sqrt{3}}{2}-5\sqrt{6}=\frac{8\sqrt{3}.\sqrt{3}}{2}-5\sqrt{6}=12-5\sqrt{6}\)
\(C=4\sqrt{3}+\frac{4}{\sqrt{3}}+10\sqrt{5}-\frac{10}{\sqrt{5}}=\frac{16}{\sqrt{3}}+8\sqrt{5}\)
ĐKXĐ: \(a>0\) ; \(a\ne9\)
\(A=\left(\frac{\sqrt{a}\left(\sqrt{a}+3\right)+\sqrt{a}\left(\sqrt{a}-3\right)}{a-9}\right).\frac{\left(a-9\right)}{\sqrt{a}}\)
\(A=\frac{\sqrt{a}\left(2\sqrt{a}\right)}{\left(a-9\right)}.\frac{\left(a-9\right)}{\sqrt{a}}=2\sqrt{a}\)
Để \(A=3\sqrt{a}-16\)
\(\Leftrightarrow2\sqrt{a}=3\sqrt{a}-16\)
\(\Rightarrow\sqrt{a}=16\)
\(\Rightarrow a=16^2=256\)
con cacacacacacacacacacacacacacacacacacca
@@22@22@22@@222@@2@@2@@@2@2
\(B=\left(2\sqrt{9.5}-\frac{3}{2}\sqrt{4.5}+\frac{\sqrt{5.15}}{\sqrt{15}}\right).\frac{3}{\sqrt{10}}\)
\(=\left(6\sqrt{5}-3\sqrt{5}+\sqrt{5}\right).\frac{3}{\sqrt{5}.\sqrt{2}}\)
\(=\frac{4\sqrt{5}.3}{\sqrt{5}.\sqrt{2}}=\frac{12}{\sqrt{2}}=6\sqrt{2}\)