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a, 879 + [ 64 + (-879) + 36 ]
= 879 + 64 - 879 + 36
= (879 - 879) + (64 + 36)
= 100
b, -564 + [ (-724) + 564 + 224 ]
= - 564 - 724 + 564 + 224
= (-564 + 564) + (-724 + 224)
= 0 - 500
= 500
c, [ 461 + (-78) + 40 ] + (-461)
= 461 - 78 + 40 - 461
= (461 - 461) + (40 - 78)
= -38
d, [ 53 + (-76) ] - [ -76 - (-53) ]
= 53 - 76 + 76 - 53
= (53 - 53) + (-76 + 76)
= 0
e, 371 + 731 - 271 - 531
= (371 - 271) + (731 - 531)
= 100 + 200
= 300
f, 57+59+60+61-17-18-19-20-21
= (57 - 17) + (59 - 19) + (60 -20) + (61 - 21) - 18
= 40 + 40 + 40 + 40 -18
= 40 *4 - 18
= 160 - 18
= 142
g, 9-10 + 11-12 + 13-14 + 15-16
= (9-10) + (11-12) + (13-14) + (15-16)
= -1 + (-1) + (-1) + (-1)
= -1 * 4
= -4
h, -1-2-3-4-5 ... -1999-2000-2001-2002
i, [ 453 + 64 + (-879) ] + (-517)
= 453 + 64 - 879 - 517
= [(453 + 64) - 517] - 879
= 0 - 879
= -879
j, -323 + [ (-874) + 564 - 241 ]
= -323 - 874 + 564 - 241
= [(-323 - 241) + 564] - 874
= 0 -874
= -874
a) \(13+22+\left(-20\right)+\left(-153\right)+8=13+22-20-153+8\)
\(=\left(13-153\right)+\left(22+8\right)-20=-140+30-20=-130\)
b) \(371+731+\left(-271\right)+\left(-281\right)=371+731-271-281\)
\(=\left(371-271\right)+\left(731-281\right)=100+450=550\)
c) \(9+\left(-10\right)+11+\left(-12\right)+13+\left(-14\right)+15+\left(-16\right)\)
\(=9-10+11-12+13-14+15-16\)
\(=\left(9-10\right)+\left(11-12\right)+\left(13-14\right)+\left(15-16\right)\)
\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)=-4\)
a) tự làm
b) (57-17)+(58-18)+(59-19)+(60-20)+(61-21)=40+40+40+40+40=200
c) (9+15)+(11+13)+(-10-14)+(-12-12-4)=24+24-24-24-4=-4
d)-(1+2+3+.....+2007)=\(-\dfrac{\left(1+2007\right).2007}{2}=-2015028\)
a) (371-271)+(731-531)=100+200=300
b) (57-17)+(58-18)+(59-19)+(60-20)+(61-21)=40+40+40+40+40=200
c) (9+15)+(11+13)+(-10-14)+(-12-12-4)=24+24-24-24-4=-4
d)-(1+2+3+.....+2007)=−(1+2007).20072=−2015028
a) 22 + ( - 47 ) + ( - 153 ) + 8
= ( 22 + 8 ) - ( 47 + 153 )
= 30 - 200
= - 170
b) 9 + ( - 10 ) + 11 + ( - 12 ) + 13 + ( - 14 ) + 15 + ( - 16 )
= ( 9 - 10 ) + ( 11 - 12 ) + ( 13 - 14 ) + ( 15 - 16 )
= - 1 - 1 - 1 - 1
= - 4
c) 371 + ( - 271 ) + ( - 531 )
= ( 371 - 271 ) - 531
= 100 - 531
= - 431
d) ( - 18 ) - 54 + ( - 46 ) - 62
= ( - 18 - 62 ) - ( 54 + 46 )
= 80 - 100
= - 20
a) = 1/10 - 1/11 + 1/11 -1/12 + 1/12 - 1/13 +1/13 1/14 +...+ 1/78 - 1/79
= 1/10 - 1/79
= máy tính ok
mấy câu khác bn làm tương tự là đc nhưng nhớ nhanh thêm khoảng cách giữa các mẫu nha
a)\(\frac{1}{10.11}+\frac{1}{11.12}+...+\frac{1}{78.79}=\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{78}-\frac{1}{79}=\frac{1}{10}-\frac{1}{79}=\frac{69}{790}\)
b) \(\frac{8}{7.9}+\frac{8}{9.11}+...+\frac{8}{133.135}=4\left(\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{133.135}\right)\)
\(=4\left(\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{133}-\frac{1}{135}\right)=4\left(\frac{1}{7}-\frac{1}{135}\right)=4.\frac{128}{945}=\frac{456}{945}\)
c) \(\frac{12}{8.11}+\frac{12}{11.14}+...+\frac{12}{503.506}=4\left(\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{503.506}\right)\)
\(=4\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{503}-\frac{1}{506}\right)=4\left(\frac{1}{8}-\frac{1}{506}\right)=\frac{249}{506}\)
d) \(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{391.394}=\frac{1}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{391.394}\right)\)
\(=\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{391}-\frac{1}{394}\right)=\frac{1}{3}.\left(\frac{1}{4}-\frac{1}{394}\right)=\frac{1}{3}.\frac{195}{788}=\frac{65}{788}\)
e) \(\frac{4}{5.8}+\frac{4}{8.11}+...+\frac{4}{602.605}=\frac{4}{3}.\left(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{602.605}\right)\)
\(=\frac{4}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{602}-\frac{1}{605}\right)=\frac{4}{3}\left(\frac{1}{5}-\frac{1}{605}\right)=\frac{4}{3}.\frac{24}{121}=\frac{32}{121}\)
g) Sửa đề\(1+\frac{1}{3}+\frac{1}{6}+...+\frac{1}{820}=2\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{1640}\right)=2\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{40.41}\right)\)
\(=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{40}-\frac{1}{41}\right)=2\left(1-\frac{1}{41}\right)=2.\frac{40}{41}=\frac{80}{41}\)
đế nhá