Question

[IzunaHatsune]

Bài 1: Tìm x

a. \(x-\frac{5}{12}-\frac{4}{9}=\frac{-13}{18}\)

b. \(2-\left(x+\frac{3}{7}\right)=\frac{9}{-21}\)

c. \(x-\frac{-3}{11}=\frac{6}{22}+\frac{1}{4}\)

d. \(\frac{13}{36}-\frac{5}{18}-x=\frac{-11}{9}\)

e. \(x-\frac{3}{7}:\frac{9}{14}=\frac{-17}{3}\)

f. \(\left(x-\frac{1}{2}\right):\frac{3}{11}=\frac{11}{4}\)

g. \(\left(2x+\frac{3}{8}\right).\frac{7}{4}=-\frac{21}{32}\)

h. \(x-\frac{x}{3}=\frac{3}{57}:\frac{12}{19}\)

Vì dài qua cho nên bài 2 mình để riêng nhé

Answer 1

[uzumaki naruto]

 mik ko chép lại đề, mik làm luôn: 

a)  x - \(\frac{31}{36}=\frac{-13}{38}\)

x = \(\frac{-13}{18}+\frac{31}{36}\)

\(x=\frac{5}{36}\)

b)\(2-x-\frac{3}{7}=\frac{9}{-21}\)

\(\frac{11}{7}-x=\frac{3}{7}\)

x = \(\frac{11}{7}-\frac{3}{7}\)

x = 8/7

c) x + 3/11 = 23/44

x = 23/44 - 3/11

x = 1/4

d) \(\frac{1}{12}-x=\frac{-11}{9}\)

x = \(\frac{1}{12}+\frac{11}{9}\)

x = 47/36

e) \(x-\frac{2}{3}=\frac{-17}{3}\)

x= -17/3 + 2/3

x = -5 

f) \(x-\frac{1}{2}=\frac{11}{4}.\frac{3}{11}\)

x - 1/2 = 3/4

x = 3/4 + 1/2 

x = 5/4

g) \(2x+\frac{3}{8}=\frac{-21}{32}.\frac{4}{7}\)

2x + 3/8 = -3 / 8

2x = -3/8 - 3/8 

2x = -9/8

x = -9/8.1/2 

x = -9/16

h) x - \(\frac{x}{3}=\frac{3}{57}.\frac{19}{12}\)

x  - \(\frac{x}{3}=\frac{1}{12}\)

x = \(\frac{1}{12}+\frac{x}{3}\)

x = \(\frac{1+4x}{12}\)

=> 12x = 1+4x

12x - 4x = 1

8x = 1

x = 1/8 

Answer 2

[IzunaHatsune]

Trả lời nhanh gọn lẹ nhé, mình k cho :)