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\(\frac{1}{1\times2}\) + \(\frac{1}{1\times3}\) + \(\frac{1}{1\times4}\) + \(\frac{1}{1\times5}\) + \(\frac{12}{10}\)
= \(\frac{1}{2}\) + \(\frac{1}{3}\) + \(\frac{1}{4}\) + \(\frac{1}{5}\) + \(\frac{12}{10}\)
= \(\frac{149}{60}\)
Ta có : \(\frac{1}{3.7}+\frac{1}{7.11}+...+\frac{1}{x.\left(x+4\right)}=\frac{5}{63}\)
=> \(\frac{1}{4}.\left(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{x\left(x+4\right)}\right)=\frac{5}{63}\)
=> \(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{20}{63}\)
=> \(\frac{1}{3}-\frac{1}{x+1}=\frac{20}{63}\)
=> \(\frac{1}{x+1}=\frac{1}{63}\)
=> x + 1 = 63
=> x = 62
Vậy x = 62
Sửa lại bài làm của XYZ một chút:
=> \(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+..+\)\(\frac{1}{x}-\frac{1}{x+4}\)
=> \(\frac{1}{3}-\frac{1}{x+4}\)= \(\frac{5}{63}\div\frac{1}{4}=\frac{20}{63}\)f
Ta có :
1/1.4+1/4.7+...+1/91.94
=1/3.(1/1-1/4+...+1/91-1/94)
=1/3.(1/1-1/94)
=1/3.93/94
=31/94
Ta có :
1/1.4+1/4.7+...+1/91.94
=1/3.(1/1-1/4+...+1/91-1/94)
=1/3.(1/1-1/94)
=1/3.93/94
=31/94
\(a,\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+....+\frac{1}{384}\)
\(\text{Đ}\text{ặt}\)\(A=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+...+\frac{1}{384}\)
\(2A=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+....+\frac{1}{192}\)
\(2A-A=\frac{1}{3}-\frac{1}{384}\)
a đề sai
b)Đặt A=1/4x7 + 1/7x10 + 1/10x13 +...........+ 1/19x22
\(3A=3\left(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{19.22}\right)\)
\(3A=\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{19}-\frac{1}{22}\)
\(3A=\frac{1}{4}-\frac{1}{22}\)
\(A=\frac{9}{44}:3\)
\(A=\frac{3}{44}\)
a) Ta có \(\frac{1.2+2.4+3.6+4.8+5.10}{3.4+6.8+9.12+12.16+15.20}\)
= \(\frac{1.2+1.2.2.2+1.3.2.3+1.4.2.4+1.5.2.5}{3.4+3.2.4.2+3.3.4.3+3.4.4.4+3.5.4.5}\)
= \(\frac{1.2+1.2.4+1.2.9+1.2.16+1.2.25}{3.4+3.4.4+3.4.9+3.4.16+3.4.25}\)
= \(\frac{1.2.\left(1+4+9+16+25\right)}{3.4.\left(1+4+9+16+25\right)}\)
= \(\frac{1.2.55}{3.4.55}\)
= \(\frac{1.2.55}{3.2.2.55}\)
= \(\frac{1}{3.2}\)
= \(\frac{1}{6}\)
b) \(\frac{111111}{666665}=\frac{111111}{666665}\)
(dấu "." là dấu "x")
Bài 1
a 2/5+3/6=12/30+15/30=27/30=9/10 .
b 5/9-1/6=30/54-9/54=21/54=7/18
\(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+....+\dfrac{1}{24\times25}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{24}-\dfrac{1}{25}\)
\(=1-\dfrac{1}{25}\)
\(=\dfrac{24}{25}\)
55/56
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