Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
câu a) lấy mẫu số chung cộng với nhau
câu b) lấy 1 để ngoài nhân r 1/2-1/3 rồi tương tự
x x - 4/7 = 15/20
(hình như sai đề, tại vì lớp 4 chưa học lũy thừa)
x * 2/7 -2/3 =1/2
x* 2/7 = 1/2 + 2/3
x* 2/7 = 7/6
x= 7/6 : 2/7
x= 49/12
x : 5/4 + 4/5 =2
x: 5/4 = 2 - 4/5
x: 5/4 = 6/5
x= 6/5 * 5/4
x= 3/2
4/3 x 7/8 x 5
= 7/6 x 5
= 35/6
8/9 x 6/5 x 2/3
= 16/15 x 2/3
= 32/45
4/7 : 5/7 x 10/11
= 4/5 x 10/11
= 8/11
8/13 : 7/13 : 4
= 8/7 : 4
= 2/7
2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35 18/27 - 2/6=1/3 37/12 - 3=1/12
11/9 x 3/22=1/6 7/13 x 13/7=1 4 x6/7=24/7
2/5 : 3/10=4/3 3/8 : 9/4=1/6 8/21 : 4/7=2/3
một thửa ruộng hình vuông có chu vi là 100 mét.Người ta cấy lúa trung bình là 1 mét vuông thu hoạch được 12/25 kg.hỏi trên thửa ruộng đó người ta thu hoạch được bao nhiêu tạ thóc
a, 7/15 +4/5 =7/15+12/15 = 19/15
b,2/3-3/8=16/24-9/24=7/24
C,4/7x21/16:5/8=4/7x21/16x8/5=6/5
D,13x42x11/33x26x35=1/5
7/15 + 4/15 = 11/15
13/5 - 2 = 13/5 - 10/5 = 3/5
4/7 x 5/8 = 20/56=5/14
8/3 : 8 = 8/3 x 1/8 = 8/24 = 1/3
a.11/7.8/13+8/13.3/7+8/13
=8/13.(11/7+3/7+1)
=8/13.3
=24/13
b.5/7.8/13+8/13.9/7-8/13
=8/13.(5/7+9/7-1)
=8/13.1
=8/13
c.157.199-56.199-199
=199.(157-56-1)
=199.100
19900
\(a,\dfrac{1}{3}+\dfrac{3}{4}\times\dfrac{2}{9}=\dfrac{1}{3}+\dfrac{6}{36}=\dfrac{1}{3}+\dfrac{1}{6}=\dfrac{2}{6}+\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)
\(b,2-\left(\dfrac{2}{5}+\dfrac{2}{3}\right)=2-\left(\dfrac{6}{15}+\dfrac{10}{15}\right)=2-\dfrac{16}{15}=\dfrac{30}{15}-\dfrac{16}{15}=\dfrac{14}{15}\)
\(c,\dfrac{2}{5}:\dfrac{4}{7}+\dfrac{1}{3}=\dfrac{2}{5}\times\dfrac{7}{4}+\dfrac{1}{3}=\dfrac{14}{20}+\dfrac{1}{3}=\dfrac{7}{10}+\dfrac{1}{3}=\dfrac{21}{30}+\dfrac{10}{30}=\dfrac{31}{30}\)
\(d,\dfrac{9}{13}:\dfrac{3}{26}-\dfrac{8}{13}=\dfrac{9}{13}\times\dfrac{26}{3}-\dfrac{8}{13}=\dfrac{234}{39}-\dfrac{8}{13}=6-\dfrac{8}{13}=\dfrac{78}{13}-\dfrac{8}{13}=\dfrac{70}{13}\)
a:=1/3+6/36
=1/3+1/6
=1/2
b: =2-16/15
=14/15
c: =2/5*7/4+1/3
=14/20+1/3
=7/10+1/3
=21/30+10/30=31/30
d: =9/13*26/3-8/13
=3-8/13=31/13
a)5/12 + 1/4 = \(\dfrac{5}{12}+\dfrac{3}{12}=\dfrac{8}{12}=\dfrac{2}{3}\)
b)23/5 - 11/3 = \(\dfrac{69}{15}-\dfrac{55}{15}=\dfrac{14}{15}\)
c)4/5 + 13 = \(\dfrac{4}{5}+\dfrac{65}{5}=\dfrac{69}{5}\)
d)8/5 : 1/3 = \(\dfrac{8}{5}x3=\dfrac{24}{5}\)
e)3/7 x 2 =\(\dfrac{6}{7}\)
\(a,\) \(\dfrac{5}{12}+\dfrac{1}{4}=\dfrac{5}{12}+\dfrac{3}{12}=\dfrac{8}{12}=\dfrac{2}{3}\)
\(b,\) \(\dfrac{23}{5}-\dfrac{11}{3}=\dfrac{69}{15}-\dfrac{55}{15}=\dfrac{14}{15}\)
\(c,\) \(\dfrac{4}{5}+\dfrac{1}{3}=\dfrac{12}{15}+\dfrac{5}{15}=\dfrac{17}{15}\)
\(d,\) \(\dfrac{8}{5}:\dfrac{1}{3}=\dfrac{8}{5}\times\dfrac{3}{1}=\dfrac{24}{5}\)
\(e,\) \(\dfrac{3}{7}\times2=\dfrac{3\times2}{7}=\dfrac{6}{7}\)
a) Thiếu đề
b) ` 4/7 xx 8/13 + 8/13 xx 3/7`
= ` 8/13 xx ( 4/7 + 3/7)`
` = 8/13 xx 7/7`
` = 8/13 xx 1`
` = 8/13`
b)\(\dfrac{4}{7}x\dfrac{8}{13}+\dfrac{8}{13}x\dfrac{3}{7}=\dfrac{8}{13}x\left(\dfrac{4}{7}+\dfrac{3}{7}\right)=\dfrac{8}{13}x1=\dfrac{8}{13}\)