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\(\dfrac{373737}{474747}+\dfrac{5757}{4747}\)
\(\left(=\dfrac{373737:10101}{474747:10101}+\dfrac{5757:101}{4747:101}\right)\)
\(=\dfrac{37}{47}+\dfrac{57}{47}=\dfrac{37+57}{47}=\dfrac{94}{47}=2\)
Lời giải:
$\frac{373737}{474747}+\frac{5757}{4747}$
$=\frac{373737:10101}{474747:10101}+\frac{5757:101}{4747:101}$
$=\frac{37}{47}+\frac{57}{47}=\frac{94}{47}=2$
Ta có: \(\frac{373737}{474747}=\frac{373737:10101}{474747:10101}=\frac{37}{47}\)
\(\frac{5757}{4747}=\frac{5757:101}{4747:101}=\frac{57}{47}\)
\(\Rightarrow A=\frac{373737}{474747}+\frac{5757}{4747}=\frac{37}{47}+\frac{57}{47}=\frac{37+57}{47}=\frac{94}{47}=2\)
Vậy A = 2
rút gọn đi:373737/474747= 37/47 5757/4747=57/47
A=37/47+57/47= 94/47=2
\(A=18\cdot\left(\frac{373737}{424242}+\frac{373737}{565656}+\frac{373737}{727272}\right)\)
\(=18\cdot\left(\frac{37}{42}+\frac{37}{56}+\frac{37}{72}\right)=18\cdot37\cdot\left(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)\)
\(=18\cdot37\cdot\left(\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}\right)\)
\(=18\cdot37\cdot\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\right)\)
\(=18\cdot37\cdot\left(\frac{1}{6}-\frac{1}{9}\right)=18\cdot37\cdot\left(\frac{3}{18}-\frac{2}{18}\right)\)
\(=18\cdot37\cdot\frac{1}{18}=18\cdot\frac{1}{18}\cdot37=1\cdot37=37\)
\(=18\times\left(\frac{37\times10101}{42\times10101}+\frac{37\times10101}{56\times10101}+\frac{37\times10101}{72\times10101}\right)\)
\(=18\times\left(\frac{37}{42}+\frac{37}{56}+\frac{37}{72}\right)\)
\(=666\left(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)\)
\(=666\times\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\right)\)
\(=666\times\left(\frac{1}{6}-\frac{1}{9}\right)\)
\(=666\times\frac{1}{18}=37\)
\(18\times\left(\frac{373737}{424242}+\frac{373737}{565656}+\frac{373737}{727272}\right)\)
\(=18\times\left(\frac{37}{42}+\frac{37}{56}+\frac{37}{72}\right)\)
\(=18\times\frac{37}{18}\)
\(=37\)
A=37/47+57/47
A=94/47
A = 373737/474747 + 5757/4747
A = 379494/479494
A = 2