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các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha
a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)
-\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)
-6 < \(x\) < -4
vì \(x\) \(\in\) Z nên \(x\) = -5
a\()\) 16/9 +3/5
=107/45
b\()\) 4/13--2/17
=51/221--26/221
=77/221
c\()\) -3/2+4/5
=-15/10+8/10
=-7/10
d\()\) 3/-4-1/4
=-1
e\()\) -1/5.5/7
=-1/7
f\()\) 7/8.64/49
=8/7
g\()\) 3/4.15/24
=15/32
a)2/3 + 5+3/7:2+4/49.(-7)+1/2.(-2)\(^4\)
= 2/3+5+3/14+-4/7+8
=(2/3+3/14+-4/7)+(5+8)
=13/42+13
=559/42
b)2+3/4.(-0,4)-1-3/5.2,75+(-1/2):4/11
=2+(-0,3) - 1 - 1,65 + (-11/8)
= -2,325
c)( 2 + 1/3 +3 +1/2 ) : ( -4 - 1/6 +3 +1/7 ) +7 +1/2
=35/6 : -43/42 + 7 + 1/2
= -245/43 +7 +1/2
= 155/86
d) 2/3+ -5/12
= 8/12 + -5/12
= 3/12
e) -2/3 . -9/12
= \(\frac{-2.-9}{3.12}\)
= 18/36
=1/2
f) -2/9 - 7/12
=\(\frac{-24}{108}\)- \(\frac{14}{108}\)
= \(\frac{-38}{108}\)
=\(\frac{-19}{54}\)
g) 2/3 : -4/9
= \(\frac{2}{3}\). \(\frac{-9}{4}\)
= -3/2
h) 4 . ( -1/3)\(^3\)- 2 . ( -1/2)\(^2\)+3 .( 1/2 ) +1
=- 4 . 1/27 - 2 . 1/4 + 3 .1/2 +1
= -4/27 - 1/2 + 3/2 + 1
= 50 / 27
k ) ( 4 - 5/12 ) : 2 +5/24
= 43/12 : 2 +5/24
= 43/24 + 5/24
= 48/24
= 2
\(-\frac{1}{10}< =x< =\frac{3}{5}\)
\(\frac{-4}{9}< x< =\frac{2}{3}\)
\(a)\)\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
\(=6\frac{4}{5}-1\frac{2}{3}-3\frac{4}{5}\)
\(=\left(6\frac{4}{5}-3\frac{4}{5}\right)-1\frac{2}{3}\)
\(=\left(6+\frac{4}{5}-3-\frac{4}{5}\right)-\frac{5}{3}\)
\(=3-\frac{5}{3}\)
\(=\frac{9}{3}-\frac{5}{3}\)
\(=\frac{4}{3}\)
\(b)\)\(6\frac{5}{7}-(1\frac{3}{4}+2\frac{5}{7})\)
\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)
\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)
\(=\left(6+\frac{5}{7}-2-\frac{5}{7}\right)-\frac{7}{4}\)
\(=4-\frac{7}{4}\)
\(=\frac{16}{4}-\frac{7}{4}\)
\(=\frac{9}{4}\)
\(c)\)\(7\frac{5}{9}-\left(2\frac{3}{4}+3\frac{5}{9}\right)\)
\(=7\frac{5}{9}-2\frac{3}{4}-3\frac{5}{9}\)
\(=\left(7\frac{5}{9}-3\frac{5}{9}\right)-2\frac{3}{4}\)
\(=\left(7+\frac{5}{9}-3-\frac{5}{9}\right)-\frac{11}{4}\)
\(=4-\frac{11}{4}\)
\(=\frac{16}{4}-\frac{11}{4}\)
\(=\frac{5}{4}\)
P/s: Câu b bạn thiếu ngoặc.
Linz
a) 6 và 4/5 - ( 1 và 2/3 + 3 và 4/5)
= 34/5- ( 5/3 + 19/5 )
= 34/5 - 5/3 - 19/5
= (34/5 - 9/5 ) - 5/3
=25/5 -5/3
= 5/1 - 5/3
= 15/3 - 5/3
=10/3
b) 6 và 5/7 - (1 và 3/4 + 2 và 5/7)
=47/7 - (7/4 + 19/7 )
= 47/7 -7/4 - 19/7
= (47/7 -19/7 ) - 7/4
= 28/7 -7/4
=4/1 - 7/4
= 16/4 - 7/4
= 9/4
c) 7 và 5/9 - ( 2 và 3/4 + 3 và 5/9 )
= 68/9 - ( 11/4 + 32/9 )
= 68/9 - 11/4 - 32/9
= (68/9 - 32/9 )- 11/4
= 36/9 -11/4
= 4/1 - 11/4
= 16/4 - 11/4
= 5/4
Chúc bạn học tốt nha!!!!!
a,
A=1−3−5−7−9−...−97−99a)A=1−3−5−7−9−...−97−99
=1−(3+5+7+...+99)=1−(3+5+7+...+99)
=1−(99+3).[(99−3):2+1]2=1−(99+3).[(99−3):2+1]2
=1−2499=−2498=1−2499=−2498
b)B=1+3−5−7+9+...+97−99b)B=1+3−5−7+9+...+97−99
=(−8)+(−8)+(−8)+...+(−8)+97−99=(−8)+(−8)+(−8)+...+(−8)+97−99
=(−8).12+(−2)=−98=(−8).12+(−2)=−98
c)C=1−3−5+7+9−11−13+15+...+97−99c)C=1−3−5+7+9−11−13+15+...+97−99
=0+0+0+0+0+...+0−99=0+0+0+0+0+...+0−99
=−99
a; \(\dfrac{3}{11}\) + \(\dfrac{5}{-9}\) + \(\dfrac{4}{11}\) - \(\dfrac{4}{9}\) + \(\dfrac{3}{17}\) + \(\dfrac{15}{11}\)
= (\(\dfrac{3}{11}\) + \(\dfrac{4}{11}\) + \(\dfrac{15}{11}\)) - (\(\dfrac{5}{9}\) + \(\dfrac{4}{9}\)) + \(\dfrac{3}{17}\)
= 2 - 1 + \(\dfrac{3}{17}\)
= 1 + \(\dfrac{3}{17}\)
= \(\dfrac{20}{17}\)
c; N = \(\dfrac{\dfrac{5}{7}-\dfrac{5}{9}-\dfrac{5}{11}}{\dfrac{15}{7}+\dfrac{15}{9}+\dfrac{15}{11}}\)
Phải là - \(\dfrac{5}{7}\) chỗ tử số mới đúng em nhé!
a.3/7*49/6+3/4*-12/33
=7/2-3/11
=71/22
b.5/3*14/9+1/6-2/10
=-70/27-1/30
=-709/270