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a) \(\left(\frac{-2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
\(=\left(\frac{-2}{3}+\frac{3}{7}+\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
\(=\left(-1+1\right):\frac{4}{5}\)
\(=0:\frac{4}{5}\)
\(=0\)
b) \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-3}{5}\)
\(=\frac{5}{9}.\frac{-22}{3}+\frac{5}{9}.\frac{-5}{3}\)
\(=\frac{5}{9}.\left(\frac{-22}{3}+\frac{-5}{3}\right)\)
\(=\frac{5}{9}.-9\)
\(=-5\)
Ta có:
\(\dfrac{2}{5}\cdot\dfrac{2}{9}+\dfrac{2}{5}:\dfrac{9}{7}+2\)
\(=\dfrac{2}{5}\cdot\dfrac{2}{9}+\dfrac{2}{5}\cdot\dfrac{7}{9}+2\)
\(=\dfrac{2}{5}\cdot\left(\dfrac{2}{9}+\dfrac{7}{9}\right)+2\)
\(=\dfrac{2}{5}\cdot1+2\)
\(=\dfrac{2}{5}+2\)
Ta thấy \(\dfrac{2}{5}+2>\dfrac{2}{5}\)
Vậy: \(\dfrac{2}{5}\cdot\dfrac{2}{9}+\dfrac{2}{5}:\dfrac{9}{7}+2>\dfrac{2}{5}\)
_________________________
\(\dfrac{8}{9}:\left(\dfrac{1}{11}-\dfrac{5}{12}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
\(=\dfrac{8}{9}:-\dfrac{43}{132}+\dfrac{5}{9}:-\dfrac{3}{5}\)
\(=\dfrac{8}{9}\cdot-\dfrac{132}{43}+\dfrac{5}{9}\cdot-\dfrac{5}{3}\)
\(=-\dfrac{352}{129}+-\dfrac{25}{27}\)
\(=\dfrac{-4243}{1161}\)
tính:
a.(-2/3+3/7) : 4/5 + (-1/3+4/7) : 4/5
b. 5/9 : (1/11-5/22) + 5/9 : (1/15 - 2/3)
Help Me, Please !
a.(-2/3+3/7) : 4/5 + (-1/3+4/7) : 4/5
= [(-2/3 + 3/7) + (-1/3 + 4/7)] : 4/5
= [(-2/3 + (-1/3) + (3/7 + 4/7)] : 4/5
= [-1 + 1] : 4/5
= 0 : 4/5
= 0
a) \(\left(\frac{-2}{3}+\frac{3}{7}\right).\frac{5}{4}+\left(\frac{-1}{3}+\frac{4}{7}\right).\frac{5}{4}\)
=\(\left(\frac{-2}{3}+\frac{-1}{3}+\frac{3}{7}+\frac{4}{7}\right).\frac{5}{4}\)
= \(0.\frac{5}{4}=0\)
b) \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}+\frac{1}{15}-\frac{2}{3}\right)\)
=\(\frac{5}{9}:\frac{-81}{110}=\frac{-550}{729}\)
1^3-3^5-(-3^5)+1^64-2^9-1^36+1^15
=1+(-3^5+3^5)+1-2^9-1+1
=2-2^9
=-510
a) \(\frac{1}{3}-\frac{3}{4}-\left(\frac{-3}{5}\right)+\frac{1}{64}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
=\(\left(\frac{1}{3}+\frac{3}{5}+\frac{1}{15}\right)-\left(\frac{3}{4}+\frac{2}{9}+\frac{1}{36}\right)+\frac{1}{64} \)
=\(\frac{5+9+1}{15}-\frac{27+8+1}{36}+\frac{1}{64}\)
= \(1+1+\frac{1}{64}=2\frac{1}{64}\)
a,\(\left(\dfrac{-2}{3}+\dfrac{3}{7}\right):\dfrac{4}{5}+\left(\dfrac{-1}{3}+\dfrac{4}{7}\right):\dfrac{4}{5}\)
\(=\left(-\dfrac{2}{3}+\dfrac{3}{7}\right).\dfrac{5}{4}+\left(\dfrac{-1}{3}+\dfrac{4}{7}\right).\dfrac{5}{4}\)
\(=\left(\dfrac{-2}{3}+\dfrac{3}{7}+\dfrac{-1}{3}+\dfrac{4}{7}\right).\dfrac{5}{4}\)
\(=\left(-1+1\right).\dfrac{5}{4}=0\)
Chúc bạn học tốt!!!
Câu b làm tương tự!
a) Đoàn Đức Hiếu
b) \(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
\(=\dfrac{5}{9}:\left(-\dfrac{3}{22}\right)+\dfrac{5}{9}:\left(-\dfrac{3}{5}\right)\)
\(=-\dfrac{5}{9}\cdot\dfrac{22}{3}-\dfrac{5}{9}\cdot\dfrac{5}{3}\)
\(=-\dfrac{110}{27}-\dfrac{25}{27}\)
\(=-5\)
a. [ -2/3 + 3/7 ] : 4/5 + [ -1/3 + 4/7 ] : 4/5 = 0
b. 5/9 : [ 1/11 - 5/22 ] + 5/9 : [ 1/15 - 2/3 ] = -5
HT/nhớ k cho tôi nha
Ai làm xong sớm nhất tui k cho
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