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a) \(132,5-2x=29,9\)
<=>\(2x=132,5-29,9\)
<=>\(2x=102,6\)
<=>\(x=102,6:2\)
<=>\(x=51,3\)
b) \(18-5x=8\)
<=>\(5x=18-8\)
<=>\(5x=10\)
<=>\(x=10:5\)
<=>\(x=2\)
c) \(2x+14=26\)
<=>\(2x=26-14\)
<=>\(2x=12\)
<=>\(x=12:2\)
<=>\(x=6\)
d) \(x-105:21=15\)
<=>\(x-5=15\)
<=>\(x=15+5\)
<=>\(x=20\)
e) \(315+\left(125-x\right)=81\)
<=>\(125-x=81-315\)
<=>\(125-x=-234\)
<=>\(x=125--234\)
<=>\(x=125+234\)
<=>\(x=359\)
K CHO MINK NHA
a) 35-15+x=70
=> 20+x=70
=> x=50
b) 568-(2x+14)=15
=> 2x+14=553
=> 2x=539
=> x=269,5
c) x-105:21=15
=> x-5=15
=> x=20
d) (x-105)*21=15
=> x-105=5/7
=> x=5/7+105
=> x=740/7
a, 35 - 15 + x = 70 b, 568 - (2.x + 14 )= 15
x = 70 - 35 + 15 2.x + 14 = 568 - 15
x = 50 2.x + 14 =553 => 2.x =553-14=539 =>x=539 : 2 =269.5
c, x - 105 : 21 =15 d, (x - 105) . 21 = 15
x - 105 = 15 x 21 x - 105 = 15 : 21
x - 105 = 315 x - 105 = \(\frac{5}{7}\)
x = 315+105 x = \(\frac{5}{7}\)+ 105
x = 420 x = \(\frac{740}{7}\)
a) x-105 / 21 = 15
=> x - 105 = 15 . 21
x - 105 = 315
=> x = 210
b) 10 + 2x = 45 / 43
=> 10 + 2x = 16
=> 2x = 6
=> x = 3
a) (190-2x) : 35 -32 = 16
=> (190-2x) : 35 =16+32
=> (190-2x) : 35 =48
=> 190-2x = 48.35 = 1680
=> 2x = 190-1680 = -1490
=> x = -1490/2= -745
b) (x : 23 + 45) . 37 -22 =2^4.105
=> (x : 23+45).37=2^4.105+22=1702
=> (x : 23 +45) = 1702/37 = 46
=> x : 23 = 46- 45 =1
=> x = 23
a) ( 190 - 2x ) : 35 - 32 = 16
( 190 - 2x ) : 35 =48
190-2x=1680
2x=-1490
x=-745
b) ( x : 23 + 45) . 37 - 22 = 24 . 105
( x : 23 + 45) . 37 - 22 = 1680
( x : 23 + 45) . 37 =1702
x : 23 + 45= 46
x:23=1
x=23
\(a,2.\left(x+3\right)-3x=-2x+7\)
\(\Leftrightarrow2x+6-3x=-2x-7\)
\(\Leftrightarrow-x+6=-2x+7\)
\(\Leftrightarrow x=-6+7\)
\(\Leftrightarrow x=1\)
\(b,5.\left(x-3\right)-29=-2.\left(7-x\right)-23\)
\(\Leftrightarrow5x-15-29+23=14-2x\)
\(\Leftrightarrow5x-21=14-2x\)
\(\Leftrightarrow5x+2x=35\)
\(\Leftrightarrow x=5\)
\(c,-17+\left|5-x\right|=-2.7\)
\(\Leftrightarrow-17+\left|5-x\right|=-14\)
\(\Leftrightarrow\left|5-x\right|=3\)
\(\Leftrightarrow\orbr{\begin{cases}5-x=3\\5-x=-3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=8\end{cases}}\)
\(d,21-\left|x+7\right|=-42:\left(-2\right)\)
\(\Leftrightarrow21-\left|x+7\right|=21\)
\(\Leftrightarrow\left|x+7\right|=0\)
\(\Leftrightarrow x+7=0\)
\(\Leftrightarrow x=7\)
\(f,\left|3x-5\right|-\left(-15\right)=5\)
\(\Leftrightarrow\left|3x-5\right|+15=5\)
\(\Leftrightarrow\left|3x-5\right|=-10\)
Vì \(\left|a\right|\ge0\)mà \(-10< 0\)nên \(x\in\Phi\)
Đã giải quyết xong!!!
giúp mình với: so sánh -37/56 với -377/567 ai giải đc mình cho
a) ta có : \(|-x+8|\ge0\)
=> \(|-x+8|-21\ge-21\)
=> A \(\ge-21\)
Vậy A đạt GTNN là -21 khi x=8
b) ta có :\(|-x-17|+|y-36|\ge0\)
=> \(|-x-17|+|y-36|+12\ge0+12\)
=> B \(\ge12\)
Vậy B đạt GTNN là 12 khi x=-17 và y =36
c) ta có: \(-|2x-8|\le0\)
=> \(-|2x-8|-35\le0-35\)
=> C \(\le-35\)
Vậy C đạt GTLN là -35 khi 2x-8=0==> x=4
d) ta có : \(3.\left(3x-12\right)^2\ge0\)
=> \(3.\left(3x-12\right)^2-35\ge0-35\)
=> \(D\ge-35\)
Vậy D đạt GTNN là -35 khi x =4
e) ta có : \(-3.|2x+50|\le0\)
=>: \(-21-3.|2x+50|\le0-21\)
=> E \(\le-21\)
vậy E đạt GTLN là -21 khi x=-25
a) \(-39-\left(15+x\right)=18\)
\(-39-15-x=18\)
\(-54-x=18\)
\(x=-54-18\)
\(x=-72\)
vậy \(x=-72\)
b) \(31-\left(13+x\right)=18.\left(-4\right)\)
\(31-13-x=-72\)
\(18-x=-72\)
\(x=18+72\)
\(x=90\)
vậy \(x=90\)
c) \(58-\left(47+3x\right)=-18-2x\)
\(58-47-3x+2x=-18\)
\(11-x=-18\)
\(x=11+18\)
\(x=29\)
vậy \(x=29\)
d) \(37-\left(115+x\right)=188\)
\(37-115-x=188\)
\(-78-x=188\)
\(x=-78-188\)
\(x=-266\)
vậy \(x=-266\)
a)
\(-39-\left(15+x\right)=18\)
\(\Rightarrow15+x=-39-18\)
\(\Rightarrow15+x=-57\)
\(\Rightarrow x=-57-15\)
\(\Rightarrow x=-72\)
Vậy \(x=-72\)
b)
\(31-\left(13+x\right)=18.\left(-4\right)\)
\(\Rightarrow31-\left(13+x\right)=-72\)
\(\Rightarrow13+x=31-\left(-72\right)\)
\(\Rightarrow13+x=103\)
\(\Rightarrow x=103-13\)
\(\Rightarrow x=90\)
Vậy \(x=90\)
x - 7 = 15 - (-21)
x - 7 = 36
x = 36 + 7
x = 43
b) 3x + 17 = 2
3x = 2 - 17
3x = -15
x = -5
c) ( x - 9) = 45 - ( -35)
x - 9 = 80
x = 80 + 9
x = 89
a/ \(15-\left(x-7\right)=-21\)
\(15-x+7=-21\)
\(x=15-\left[\left(-21\right)-7\right]=15-\left(-28\right)=43\)
b/\(3x+17=2\)
\(3x=2-17=-15\)
\(x=-\frac{15}{3}=-5\)
c/\(45-\left(x-9\right)=-35\)
\(45-x+9=-35\)
\(x=45-\left[\left(-35\right)-9\right]=89\)
d/\(\left(-5\right)+x=15\)
\(x=15-\left(-5\right)=20\)
e/\(2x-\left(-17\right)=15\)
\(2x=15-17=-2\)
\(x=-\frac{2}{2}=-1\)
g/ \(Ix-2I=3\)
TH1: \(x-2=3\)
\(x=3+2=5\)
TH2: \(x-2=-3\)
\(x=\left(-3\right)+2=-1\)
=> \(x\in\left\{-1;5\right\}\)
A) 149 - ( 2x - 53 ) = 54
2x - 53 = 149 - 54
2x - 53 = 95
2x = 95 + 53
2x = 148
x = 148 : 2
x = 74
B) 47 - 3( 2x - 18 ) = 35
3( 2x - 18 ) = 47 - 35
3( 2x - 18 ) = 12
2x - 18 = 12 : 3
2x - 18 = 4
2x = 4 + 18
2x = 22
x = 22 : 2
x = 11
C) 2x - 105 : 21 = 15
2x - 5 = 15
2x = 15 + 5
2x = 20
x = 20 : 2
x = 10
D) ( 2x - 105 ) : 21 = 15
2x - 105 = 15 x 21
2x - 105 = 315
2x = 315 + 105
2x = 420
x = 420 : 2
x = 210
2x-53=149-54
2x-53=95
2x =95+53
2x =148
x =148:2
x =74