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a) 98 + 3 + 97 +2
= (98 +2) + ( 97 + 3)
= 100 + 100 = 200
56 + 399 + 1 + 4
= (56 + 4) +( 399 + 1)
= 60 + 400 = 460
b) 364 + 136 + 219 + 181
= (364 + 136) + (219 + 181
= 500 + 400 = 900
178 277 + 123 + 422
= (178 + 422) + (277 + 123)
= 600 + 400 = 1000
\(a.98+3+97+2\)
\(=\left(98+2\right)+\left(97+3\right)\)
\(=100+100\)
\(=200\)
\(56+399+1+4\)
\(=\left(56+4\right)+\left(399+1\right)\)
\(=60+400\)
\(=460\)
\(b.364+136+219+181\)
\(=\left(364+136\right)+\left(219+181\right)\)
\(=500+400\)
\(=900\)
\(178+277+123+422\)
\(=\left(178+422\right)+\left(277+123\right)\)
\(=600+400\)
\(=1000\)
\(HocTot!!!\)
\(@VR\)
a) 98+3+97+2
= (98+2)+(97+3)
= 100 + 100
= 200
56+399+1+4
= (56+4)+(399+1)
= 60 + 400
= 460
b)364+136+219+181
= (364+136)+(219+181)
= 500 + 400
= 900
178+277+123+422
= (178+422)+(277+123)
= 600 + 400
= 1000
178 277 + 123 + 422
= (178 + 422) + (277 + 123)
= 600 + 400 = 1000
\(364+136+219+181\)
\(=\left(364+136\right)+\left(219+181\right)\)
\(=500+400\)
\(=900\)
(92 x 156 - 97 x 56) x (1 + 2 + 3 + ... + 100)
= [97 x (156 - 56)] x [(1 + 100) + (2 + 99) + (3 + 98) + ... + (50 + 51)] -> Có tất cả 50 cặp
= (97 x 100) x (101 x 50)
= 9700 x 5050
= 48985000
Từ công thức:1+2+3+..........+n=\(\frac{nx\left(n+1\right)}{2}\)
Ta có:(97*156-97*56)*(1+2+3+........+100)
=97*(156-56)+\(\frac{100x\left(100+1\right)}{2}\)
=97*100-5050
=9700-5050
=4650
200
460
900
1000
98+3+97+2=(98+2)+(97+3)
=100+100=200
56+399+1+4=(56+4)+(399+1)
=60+400
=460
364+136+219+181=(364+136)+(219+181)
=500+400=900
178+277+123+422=(178+422)+(277+123)
600+400=1000