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a/ \(=2xy+6x^2-y^2-3xy=2x\left(y+3x\right)-y\left(y+3x\right)=\left(2x-y\right)\left(y+3x\right)\)
b/ \(=2x^2+5xy+y^2\)
c/ \(=-4y^2+6xy-4xy+6x^2=-2y\left(2y-3x\right)-2x\left(2y-3x\right)=\left(-2y-2x\right)\left(2y-3x\right)=-2\left(y+x\right)\left(2y-3x\right)\)
d/ \(=-4y^2-2xy+4xy+2x^2=-2y\left(2y+x\right)+2x\left(2y+x\right)=\left(-2y+2x\right)\left(2y+x\right)=-2\left(y-x\right)\left(2y+x\right)\)
a/ \(=2xy+x^2-2y^2-xy=x\left(2y+x\right)-y\left(2y+x\right)=\left(x-y\right)\left(2y+x\right)\)
b/ \(=x^2-3xy-2y^2\)
c/ \(=2xy-6y^2+x^2-3xy=2y\left(x-3y\right)+x\left(x-3y\right)=\left(2y+x\right)\left(x-3y\right)\)
d/ \(=xy-2y^2+2x^2-4xy=y\left(x-2y\right)+2x\left(x-2y\right)=\left(y+2x\right)\left(x-2y\right)\)
a)(x-y)(x+2y)
b) nghiệm lẻ>mìh nghĩ là sai đề
c)(x-3y)(x+2y)
d)(x-2y)(2x+y)
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li-ke cho mk nha bnLe Ngoc Bao Chau
x^2 + xy - 2y^2 = ( x^2 - 2xy + y^2 ) + 3xy - 3y^2 = ( x - y )^2 + 3y.( x - y ) = ( x - y )(x + 2y)
=x^3-2x^2+2x-4-9
=(x-2)(x^2+2)-9
\(=\left(\sqrt{\left(x-2\right)\left(x^2+2\right)}-3\right)\left(\sqrt{\left(x-2\right)\left(x^2+2\right)}+3\right)\)
\(x^6-2x^3+1=\left(x^3-1\right)^2\)
\(x^4+2x^2+1=\left(x^2+1\right)^2\)
a) x6 - 2x3 + 1
= (x3)2 - 2x3 + 1
= ( x3 - 1)2
b) x4 + 2x2 + 1
= ( x2)2 + 2x2 + 1
= ( x2 + 1)2
\(=\left\{\left(2x+2\right)+\left(2x-2\right)\right\}^2\)2
\(=\left(4x\right)^2\)
\(=16x^2\)