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\(\left(6:3,5-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\\ =\left(\dfrac{12}{7}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\\ =\left(\dfrac{17}{7}-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)\\ =\dfrac{10}{7}:9\\ =\dfrac{10}{63}\)
\(\left(6:\dfrac{3}{5}-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\)
\(=\left(6\times\dfrac{5}{3}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\)
\(=\left(10-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)=9:9=1\)
a/\(x-\dfrac{5}{7}-\dfrac{13}{14}=1\)
\(x=1+\dfrac{5}{7}+\dfrac{13}{14}\)
\(x=\dfrac{14}{14}+\dfrac{10}{14}+\dfrac{13}{14}\)
\(x=\dfrac{37}{14}\)
Vậy \(x=\dfrac{37}{14}\)
b/\(\dfrac{3}{5}+x+1\dfrac{1}{5}=\dfrac{11}{3}\)
\(x+\dfrac{3}{5}+\dfrac{6}{5}=\dfrac{11}{3}\)
\(x+\dfrac{9}{5}=\dfrac{11}{3}\)
\(x=\dfrac{11}{3}-\dfrac{9}{5}\)
\(x=\dfrac{55}{15}-\dfrac{27}{15}\)
\(x=\dfrac{28}{15}\)
Vậy \(x=\dfrac{28}{15}\)
#kễnh
a) \(x-\dfrac{5}{7}-\dfrac{13}{14}=1\)
\(x-\dfrac{23}{14}=1\)
\(x=1+\dfrac{23}{14}\)
\(x=\dfrac{37}{14}\)
b) \(\dfrac{3}{5}+x+1\dfrac{1}{5}=\dfrac{11}{3}\)
\(x+1+\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{11}{3}\)
\(x+\dfrac{9}{5}=\dfrac{11}{3}\)
\(x=\dfrac{11}{3}-\dfrac{9}{5}\)
\(x=\dfrac{28}{15}\)
a: \(x+\dfrac{3}{9}=\dfrac{7}{6}\cdot\dfrac{2}{3}\)
=>\(x+\dfrac{1}{3}=\dfrac{14}{18}=\dfrac{7}{9}\)
=>\(x=\dfrac{7}{9}-\dfrac{1}{3}=\dfrac{7}{9}-\dfrac{3}{9}=\dfrac{4}{9}\)
b: \(x-\dfrac{2}{3}=\dfrac{1}{8}:\dfrac{5}{4}\)
=>\(x-\dfrac{2}{3}=\dfrac{1}{8}\cdot\dfrac{4}{5}=\dfrac{1}{10}\)
=>\(x=\dfrac{1}{10}+\dfrac{2}{3}=\dfrac{3+20}{30}=\dfrac{23}{30}\)
\(\dfrac{1}{3}+\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}\cdot\dfrac{6}{5}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}\)
\(x=\dfrac{27}{10}\)
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}:\dfrac{5}{6}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}=\dfrac{27}{10}\)
X-3/5=1+2/3 4/7:X=1/2x2/5
X-3/5=5/3 4/7:X=1/5
X=5/3+3/5 X=4/7:1/5
X=34/15 X=4
Vậy X=34/15 Vậy X=4
\(a,x=\dfrac{13}{2}-2\\ x=\dfrac{9}{2}\\ b,x=\dfrac{4}{5}\times\dfrac{3}{4}\\ x=\dfrac{12}{20}=\dfrac{3}{5}\)
\(\left(\dfrac{2}{5}-\dfrac{1}{4}\right):\dfrac{3}{4}x\dfrac{5}{2}=\dfrac{3}{20}:\dfrac{3}{4}x\dfrac{5}{2}=\dfrac{3}{20}x\dfrac{4}{3}x\dfrac{5}{2}=\dfrac{3x4x5}{20x3x2}=\dfrac{1}{2}\)
X x ( X - 13 ) = 0
=> XxX-Xx13=0
=> XxX-13X=0
=XxX=13X
=>X=12X
=> x=0
b) ( X - 1) x ( 3 x X - 15 ) = 0
=> \(\orbr{\begin{cases}x-1=0\\3x-15=0\end{cases}}\)giải ra
c) X x ( X + 1 ) = 2 + 4 + 6 + ... +2500
Dãy 2 + 4 + 6 + ... +2500 có số số hạng là:
(2500-2):2+1=1250 (số)
Tỗng của dãy là:
(2500+2)x1250:2=1563750
=> X x ( X + 1 )=1563750
Giải ra
xong nhé
a) X x ( X - 13 ) = 0
\(\hept{\begin{cases}x=0\\x-13=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x=13\end{cases}}}\)
vậy..................
b) ( X - 1) x ( 3 x X - 15 ) = 0
\(\hept{\begin{cases}x-1=0\\3\cdot x-15=0\end{cases}\Rightarrow\hept{\begin{cases}x=1\\3x=15\end{cases}}}\Rightarrow\hept{\begin{cases}x=1\\x=5\end{cases}}\)
vậy x=1
x=5
Ta có \(\frac{2}{5}x+\frac{1}{3}x=\frac{3}{5}\)
\(\Rightarrow x.\left(\frac{2}{5}+\frac{1}{3}\right)=\frac{3}{5}\)
\(\Rightarrow x.\frac{8}{15}=\frac{3}{5}\)
\(\Rightarrow x=\frac{9}{8}\)