Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{1919}{1212}\)+\(\frac{51515151}{36363636}\)
=\(\frac{1919:101}{1212:101}\)+\(\frac{51515151:1010101}{36363636:1010101}\)
=19/12+51/36
=3
\(\frac{1919}{1212}\)+ \(\frac{51515151}{36363636}\)= \(\frac{1919:101}{1212:101}\)+ \(\frac{51515151:1010101}{36363636:1010101}\)= \(\frac{19}{12}\)+ \(\frac{51}{36}\)= \(3\)
\(\frac{1919}{121212}+\frac{51515151}{36363636}\)
\(=\frac{19.101}{12.10101}+\frac{51.1010101}{36.1010101}\)
\(=\frac{19}{12}+\frac{51}{36}\)
\(=\frac{19}{12}+\frac{17}{12}\)
\(=\frac{36}{12}=3\)
Ta có: \(A=\frac{432143214321}{999999999999}=\frac{4321\times100010001}{9999\times100010001}=\frac{4321}{9999}< \frac{1}{2}\)
\(B=\frac{1212+1212+1212+1212}{1919+1919+1919+1919}=\frac{1212\times4}{1919\times4}=\frac{1212}{1919}=\frac{12\times101}{19\times101}=\frac{12}{19}>\frac{1}{2}\)
Do:\(A< \frac{1}{2}< B\Rightarrow A< B\)
\(\frac{121212+12121212-1212}{363636+36363636-3636}\)
\(=\frac{12.10101+12.1010101-12.101}{36.10101+36.1010101-36.101}\)
\(=\frac{12\left(10101+1010101-101\right)}{36\left(10101+1010101-101\right)}\)
\(=\frac{12}{12.3}\)
\(=\frac{1}{3}\)
Ta có: \(\frac{121212+12121212-1212}{363636+36363636-3636}\)
=\(\frac{12\times\left(10101+1010101-101\right)}{36\times\left(10101+1010101-101\right)}\)
=\(\frac{12}{36}\)
=\(\frac{1}{3}\)
\(\frac{1919}{1212}+\frac{515151}{363636}\)
\(=\frac{19}{12}+\frac{17}{12}\)
\(=\frac{36}{12}\)
\(=3\)
1919/1212 + 51515151/36363636 = 3.
Ai tk cho mình mình tk lại.
bằng 3 nhé