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1.
0,2 . \(\sqrt{100}\) - \(\sqrt{\dfrac{16}{25}}\)
= 0,2 . 10 - \(\dfrac{4}{5}\)
= 2 - \(\dfrac{4}{5}\)
= \(\dfrac{6}{5}\)
1/ \(0,2.\sqrt{100}-\sqrt{\dfrac{16}{25}}\)
\(=0,2.10-0,8\)
\(=2-0,8=1,2\)
2/ \(\dfrac{2^7.9^3}{6^5.8^2}\)
\(=\dfrac{93312}{497664}=\dfrac{3}{16}=0,1875\)
3/ \(\sqrt{0,01}-\sqrt{0,25}\)
\(=0,1-0,5\)
\(=-0,4\)
4/ \(0,5.\sqrt{100}-\sqrt{\dfrac{1}{4}}\)
\(=0,5.10-0,5\)
\(=5-0,5=4,5\)
5/ \(7.\sqrt{0,01}+2.\sqrt{0,25}\)
\(=7.0,1+2.0,5\)
\(=0,7+1=1,7\)
6/ \(0,5.\sqrt{100}-\sqrt{\dfrac{1}{25}}\)
\(=0,5.10-0,2\)
\(=5-0,2=4,8\)
a) \(\sqrt{0,01}-\sqrt{0,25}=\sqrt{\left(0,1\right)^2}-\sqrt{\left(0,5\right)^2}=0,1-0,5=-0,4\)b) \(0,5\sqrt{100}-\sqrt{\frac{1}{4}}=0,5\sqrt{10^2}-\sqrt{\left(\frac{1}{2}\right)^2}=0,5.10-\frac{1}{2}=5-\frac{1}{2}=\frac{9}{2}\)
a) \(\sqrt{0,01}+\sqrt{0,25}=0,1\cdot0,5=0,05\)
b) \(0,5\sqrt{100}-\frac{\sqrt{1}}{4}=0,5\cdot10-\frac{1}{4}=5-\frac{1}{4}=\frac{19}{4}\)
a)\(\sqrt{0,01}-\sqrt{0,25}\)
=\(\sqrt{\left(0,1\right)^2}-\sqrt{\left(0,5\right)^2}\)
= 0,1 - 0,5 = - 0,4
b)\(0,5.\sqrt{100}-\sqrt{\dfrac{1}{4}}\)
=0,5.\(\sqrt{10^2}-\sqrt{\left(\dfrac{1}{2}\right)^2}\)
=0,5.10−\(\dfrac{1}{2}\)
= 5 - 0,5
= 4,5.
a) 0,1 - 0,5 = -0,4
b)0,5 . 10 - 0,5 = 5 - 0,5 = 4,5
thầy thông cảm máy em không có dấu căn.
\(\)a)
\(\sqrt{0,01}-\sqrt{0,25}=\sqrt{\frac{1}{100}}-\sqrt{\frac{1}{4}}=\frac{1}{10}-\frac{1}{2}=\frac{1}{10}-\frac{5}{10}=\frac{-4}{10}=\frac{-2}{5}\)
b)
\(0,5.\sqrt{100}-\sqrt{\frac{1}{4}}=0,5.10-\frac{1}{2}=5-\frac{1}{2}=\frac{10}{2}-\frac{1}{2}=\frac{9}{2}\)
ai k mình mình k lại
a) \(\sqrt{0,01}=0,1;\sqrt{0,25}=0,5\)= 0,1-0,5 = -0,4
b) = 0,5 x 10 - \(\frac{1}{2}\)= 4,5 . ( Đơn giản nhỉ :) )
\(\sqrt{81}=9\)
\(\sqrt{0,64}=0,8\)
\(\sqrt{\frac{49}{100}}=\frac{7}{10}\)
\(\sqrt{8100}=90\)
\(\sqrt{100=}10\)
\(\sqrt{0,01}=0,1\)
\(\sqrt{\frac{4}{25}}=\frac{2}{5}\)
\(\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}\)
\(\sqrt{81}=9\);\(\sqrt{0,64}=0,8\);\(\sqrt{\frac{49}{100}}=\frac{7}{10}\);\(\sqrt{8100}=90\); \(\sqrt{100}=10\); \(\sqrt{0,01}=0,1\); \(\sqrt{\frac{4}{25}}=\frac{2}{5}\); \(\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}=\frac{3}{110}\)
a) \(\sqrt{0.01}-\sqrt{0.25}=0,1-0,5=-0,4\)
b)\(0,5.\sqrt{100}-\sqrt{\frac{1}{4}}=0,5.10-0,5=4,5\)
\(100\times\sqrt{0,01}-0,5\times\sqrt{400}+\sqrt{0,09}=100\times0,1-0,5\times20+0,3\)
\(=10-10+0,3=0+0,3=0,3\)
0,3