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\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-3}{5}\)
\(=\frac{5}{9}\cdot\frac{-22}{3}+\frac{5}{9}\cdot\frac{-5}{3}\)
\(=\frac{5}{9}\cdot\left(\frac{-22}{3}+\frac{-5}{3}\right)\)
\(=\frac{5}{9}\cdot\left(-9\right)\)
\(=-5\)
đúng đó nhưng bạn nên nhóm \(\frac{-22}{3}\)và \(\frac{-5}{3}\)vào với nhau và đặt \(\frac{5}{9}\)ra ngoài sẽ tính nhanh hơn
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left(\frac{2}{22}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{10}{15}\right)\)
\(=\frac{5}{9}:\frac{\left(-3\right)}{22}+\frac{5}{9}:\frac{\left(-9\right)}{15}\)
\(=\frac{5}{9}.\frac{22}{\left(-3\right)}+\frac{5}{9}.\frac{15}{\left(-9\right)}\)
\(=\frac{5}{9}.\left(\frac{-22}{3}+\frac{-15}{9}\right)\)
\(=\frac{5}{9}.\left(\frac{-66}{9}+\frac{-15}{9}\right)\)
\(=\frac{5}{9}.\frac{\left(-81\right)}{9}=-5\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left(\frac{-3}{22}\right)+\frac{5}{9}:\left(\frac{-3}{5}\right)\)
\(=\frac{5}{9}.\left(-\frac{22}{3}\right)+\frac{5}{9}.\left(-\frac{5}{3}\right)\)
\(=\frac{5}{9}.\left[-\frac{22}{3}+\left(-\frac{5}{3}\right)\right]\)
\(=\frac{5}{9}.\left(-9\right)\)
\(=-5\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left[\left(\frac{1}{11}-\frac{5}{22}\right)+\left(\frac{1}{15}-\frac{2}{3}\right)\right]\)
\(=\frac{5}{9}:\left[-\frac{3}{22}-\frac{3}{5}\right]\)
\(=\frac{5}{9}:\frac{-81}{110}=\frac{5}{9}.\frac{-110}{81}\)
\(=-\frac{550}{729}\)
\(\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-3}{5}\)
=\(\frac{5}{9}.\frac{-22}{3}+\frac{5}{9}.\frac{-5}{3}\)
=\(\frac{5}{9}.\left(\frac{-22}{3}-\frac{5}{3}\right)\)
=\(\frac{5}{9}.\left(-9\right)\)
=-5
gớm
Ta có: \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left(\frac{2}{22}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{10}{15}\right)\)
\(=\frac{5}{9}:\frac{-3}{22}+\frac{5}{9}:\frac{-9}{15}=\frac{5}{9}\cdot\frac{-22}{3}+\frac{5}{9}\cdot\frac{-5}{3}\)
\(=\frac{5}{9}\left(-\frac{22}{3}+\frac{-5}{3}\right)=\frac{5}{9}\cdot-9=-5\)
\(\frac{5}{9}.\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}.\left(\frac{1}{15}-\frac{2}{3}\right)\)
= \(\frac{5}{9}.\left(-\frac{3}{22}\right)+\frac{5}{9}.\left(-\frac{3}{5}\right)\)
= \(\frac{5}{9}.\left(-\frac{3}{22}+\frac{-3}{5}\right)\)
= \(\frac{5}{9}.\left(-\frac{81}{110}\right)\)
= \(-\frac{9}{22}\)
BT = \(\frac{5}{9}\left(\frac{2}{22}-\frac{5}{22}\right)+\frac{5}{9}\left(\frac{1}{15}-\frac{10}{15}\right)\)
= \(\frac{5}{9}.\frac{-3}{22}+\frac{5}{9}.\frac{-3}{5}\)
= \(\frac{-5}{3}\left(\frac{1}{22}+\frac{1}{5}\right)\) = \(\frac{-5}{3}\left(\frac{5}{110}+\frac{22}{110}\right)\) = \(\frac{-5}{3}.\frac{27}{110}=\frac{-9}{22}\)