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bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\)
\(x\times\dfrac{11}{16}=2\)
\(x=2:\dfrac{11}{16}\)
\(x=\dfrac{32}{11}\)
Bài 1 :
\(\dfrac{x}{16}\times\left(2017-1\right)=2\)
\(\dfrac{x}{16}\times2016=2\)
\(\dfrac{x}{16}=\dfrac{2}{2016}\)
\(x=\dfrac{2}{2016}\times16\)
\(x=\dfrac{1}{63}\)
b= 59/10 : 3/2 - [ 21/3 - 41/2 - 2 x 21/3] : 7/4
=9/15 - [ 21/3 - 21/3 x 41/2 - 2]
=9/15 - [ 0 x 41/2 - 2]
=9/15 - 0
=9/15
a) \(\frac{1.3+3.5+5.7+7.9}{3.6+9.10+15.14+21.18}\)
= \(\frac{1.3+3.5+5.7+7.9}{1.3.2.3+3.5.2.3+5.7.2.3+7.9.2.3}\)
= \(\frac{1.3+3.5+5.7+7.9}{1.3.6+3.5.6+5.7.6+7.9.6}\)
= \(\frac{1.3+3.5+5.7+7.9}{6.\left(1.3+3.5+5.7+7.9\right)}=\frac{1}{6}\)
Dấu "." là dấu nhân cấp 2
b) \(\frac{1.2+2.3+3.4+4.5}{3.6+6.9+9.12+12.15}\)
= \(\frac{1.2+2.3+3.4+4.5}{1.2.3.3+2.3.3.3+3.4.3.3+4.5.3.3}\)
= \(\frac{1.2+2.3+3.4+4.5}{1.2.9+2.3.9+3.4.9+4.5.9}\)
= \(\frac{1.2+2.3+3.4+4.5}{9.\left(1.2+2.3+3.4+4.5\right)}=\frac{1}{9}\)
Dấu "." là dấu nhân cấp 2
c) \(\frac{0,3+\frac{3}{7}+\frac{3}{11}}{0,4+\frac{4}{7}+\frac{4}{11}}\)= \(\frac{\frac{3}{10}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{10}+\frac{4}{7}+\frac{4}{11}}\)= \(\frac{3.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}{4.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}=\frac{3}{4}\)
\(4\frac{5}{7}:1=\frac{33}{7}:1==\frac{33}{7}\)
\(\frac{5}{6}+2=\frac{5}{6}+\frac{12}{6}=\frac{17}{6}\)
\(\frac{7}{15}x\frac{21}{74}=\frac{7}{3x5}x\frac{3x7}{74}=\frac{7x7}{5x74}=\frac{49}{370}\)
a) = 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
b) = 1/3 x 4/5 + 1/3 x6/5 + 1/3 x 2 = 1/3(4/5 + 6/5 + 2) = 1/3 x 4 = = 4/3
c) 4/7 x 2/9 + 4/7 x 7/9 + 2/3 = 4/7 x (2/9 + 7/9) + 2/3 = 4/7 x 1 + 2/3 = 26/21
A) 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
B) 1/3 x 4/5 + 1/3 x 6/5 + 1/3 x 2 = 1/3 x(4/5 + 6/5 x 2 ) = 1/3 x 4 = 4/3
c) TƯƠNG TỰ CÂU A VÀ B
* HOKTOT*
NHA
\(5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2\frac{1}{2}\right):\frac{7}{4}\)
=\(\frac{59}{10}:\frac{3}{2}-\left(\frac{7}{3}x\frac{9}{2}-\frac{5}{2}\right):\frac{7}{4}\)
=\(\frac{118}{30}-\left(\frac{63}{6}-\frac{5}{2}\right)x\frac{4}{7}\)
=\(\frac{118}{30}-\left(\frac{63}{6}-\frac{15}{6}\right)x\frac{4}{7}\)
=\(\frac{118}{30}-8x\frac{4}{7}\)
=\(\frac{118}{30}-\frac{32}{7}\)
sau bn tự tính nha
\(1-\left(5\frac{4}{9}+y-7\frac{7}{18}\right):15\frac{3}{4}=0\)
\(1-\left(\frac{49}{9}+y-\frac{133}{18}\right):\frac{63}{4}=0\)
\(1-\left(\frac{49}{9}+y-\frac{133}{18}\right)\times\frac{4}{63}=0\)
\(1-\frac{28}{81}-y\times\frac{4}{63}+\frac{38}{81}=0\)
\(1+\frac{38}{81}-\frac{28}{81}-y\times\frac{4}{63}=0\)
\(1+\frac{10}{81}-y\times\frac{4}{63}=0\)
\(\frac{91}{81}-y\times\frac{4}{63}=0\)
\(y\times\frac{4}{63}=\frac{91}{81}\)
\(y=\frac{91}{81}:\frac{4}{63}\)
\(y=\frac{637}{36}\)
P/s : Số hơi to
\(1-\left(5\frac{4}{9}+y-7\frac{7}{18}\right):15\frac{3}{4}=0\)
\(\Rightarrow1-\left(\frac{49}{9}+y-\frac{133}{18}\right):\frac{63}{4}=0\)
\(\Rightarrow\left(\frac{98}{18}+y-\frac{133}{18}\right):\frac{63}{4}=1-0\)
\(\Rightarrow\left(-\frac{35}{18}+y\right):\frac{63}{4}=1\)
\(\Rightarrow-\frac{35}{18}+y=1\times\frac{63}{4}\)
\(\Rightarrow\frac{-35}{18}+y=\frac{63}{4}\)
\(\Rightarrow y=\frac{63}{4}--\frac{35}{18}\)
\(\Rightarrow y=\frac{63}{4}+\frac{35}{18}\)
\(\Rightarrow y=\frac{637}{36}\)
Vậy \(y=\frac{637}{36}\)