1) He likes dancing and I do, too. (hobby)

=> He has the same hobby as I do.

2) Today isn't as hot as yesterday.

=> Yesterday  _it was hotter than today________________________

3) I am as old as my cousin.

=> I am the __same age as my cousin_______________________

4) He is the smartest student in my class.

=> No one __in my class is as smart as him______________________

5) My house is green and your house is green, too.

=> My house is _____the same colour as mine____________________

6) The snake is as long as the ruler.

=> The snake ___is the same length as the ruler______________________

7) No one in my family is as heavy as my father.

=> My father is __the heaviest in my family_______________________

I have never eaten a more delicious cake than this before.

=> This is the ____most delicious cake I have ever eaten_____________________

9) Playing video games is not as good as exercising. (better)

=> Exercising ____is better than playing video games_____________________

10) David is more astistic than Nick. (not)

=> Nick ___is not as artistic as David______________________

a: Thời gian dự định sẽ đi hết quãng đường là:

120:50=2,4(giờ)=2h24p

Nếu đúng dự định thì ô tô sẽ đến B lúc:

7h+2h24p=9h24p

b: Đặt AC=x

BC=AB-AC=120-x(km)

Thời gian ô tô đi hết quãng đường AC là \(\dfrac{x}{50}\left(giờ\right)\)

Thời gian ô tô đi hết quãng đường BC là: \(\dfrac{120-x}{60}\left(giờ\right)\)

Ô tô đến B sớm hơn dự kiến 5p nên ta có: \(\dfrac{x}{50}+\dfrac{1}{12}+\dfrac{120-x}{60}=2,4-\dfrac{1}{12}\)

=>\(\dfrac{x}{50}+\dfrac{120-x}{60}=2,4-\dfrac{1}{6}=\dfrac{12}{5}-\dfrac{1}{6}=\dfrac{72-5}{30}=\dfrac{67}{30}\)

=>\(\dfrac{6x+5\left(120-x\right)}{300}=\dfrac{670}{300}\)

=>6x+5(120-x)=670

=>x+600=670

=>x=70(nhận)

Vậy: Độ dài quãng đường AC là 70km

a: Xét ΔDAC và ΔDMB có

DA=DM

\(\widehat{ADC}=\widehat{MDB}\)(hai góc đối đỉnh)

DC=DB

Do đó: ΔDAC=ΔDMB

=>\(\widehat{DCA}=\widehat{DBM}\)

=>CA//BM

b: Xét ΔDNC và ΔDKB có

\(\widehat{DCN}=\widehat{DBK}\)

DC=DB

\(\widehat{NDC}=\widehat{KDB}\)(hai góc đối đỉnh)

Do đó: ΔDNC=ΔDKB

=>DN=DK

=>D là trung điểm của NK

Có thể lập được 6 số là: 1350, 1530, 3150, 3510, 5130, 5310

Có thể lập được 6 số là: 1350, 1530, 3150, 3510, 5130, 5310

hok tốt

\(\dfrac{2}{3}-\left[-\dfrac{7}{4}-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\)

\(=\dfrac{2}{3}+\dfrac{7}{4}+\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\)

\(=\dfrac{8}{12}+\dfrac{21}{12}+\dfrac{6}{12}+\dfrac{3}{8}\)

\(=\dfrac{35}{12}+\dfrac{3}{8}=\dfrac{70}{24}+\dfrac{9}{24}=\dfrac{79}{24}\)

\(\dfrac{2}{3}-\left[\dfrac{-7}{4}-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\\ =\dfrac{2}{3}-\left[\dfrac{-7}{4}-\left(\dfrac{4}{8}+\dfrac{3}{8}\right)\right]\\ =\dfrac{2}{3}-\left(\dfrac{-7}{4}-\dfrac{7}{8}\right)\\ =\dfrac{2}{3}-\left(\dfrac{-14}{8}-\dfrac{7}{8}\right)\\ =\dfrac{2}{3}+\dfrac{21}{8}\\ =\dfrac{16}{24}+\dfrac{63}{24}\\ =\dfrac{79}{24}\)

\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}\)

=\(\left(0,5+0,4\right)+\left(\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{5}{7}-\dfrac{4}{35}\right)\)

= \(0,9+\left(\dfrac{2}{6}+\dfrac{1}{6}\right)+\left(\dfrac{25}{35}-\dfrac{4}{35}\right)\)

= \(0,9+\dfrac{3}{6}+\dfrac{21}{35}\)

= `0,9 +0,5 + 0,6`

= `2`

`(-1/27) . 3/7 + 5/9 . (-3/7)`

`1/27 . (-3/7) + 5/9 . (-3/7)`

`(1/27 + 5/9) . (-3/7)`

`16/27 . (-3/7)`

`-16/63`

(\(\dfrac{3}{7}\)+(\(-\dfrac{3}{7}\))). \(\left(-\dfrac{1}{27}\right)\).\(\dfrac{5}{9}\)

= 0.\(\left(-\dfrac{1}{27}\right)\).​\(\dfrac{5}{9}\)

=0

\(3^{x+1}=27\)

\(3^{x+1}=3^3\)

\(\Rightarrow x+1=3\)

\(x=3-1\)

\(x=2\)

Vậy x = 2.

\(#Paciupibijd\)

\(3^{x+1}=27\)

\(\Rightarrow3^{x+1}=3^3\)

\(\Rightarrow x+1=3\)

\(\Rightarrow x=3-1\)

\(\Rightarrow x=2\)