phân tích đa thúc thành nhân tử: ax -bx -a^2 +2ab -b^2
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\(x^2-xy+x-y\)
\(=x\left(x-y\right)+\left(x-y\right)\)
\(=\left(x+1\right)\left(x-y\right)\)
\(x^2-xy+x-y\)
\(=x\left(x-y\right)+\left(x-y\right)\)
\(=\left(x+1\right)\left(x-y\right)\)
\(3\left(x+4\right)-x^2-4x\)
\(\Leftrightarrow3\left(x+4\right)-x\left(x+4\right)\)
\(\Leftrightarrow\left(3-x\right)\left(x+4\right)\)
\(=\left(x-y\right)\left(x+y\right)-10\left(x+y\right)=\)
\(=\left(x+y\right)\left(x-y-10\right)\)
= (x - y). (x + y) - 10 ( x - y)
= [( x + y) - 10)] . ( x - y)
\(x^2\).(\(x\) - 1) + 16.( 1 - \(x\))
= \(x^2\).(\(x-1\)) - 16.( \(x-1\))
= (\(x\) - 1).(\(x^2\) - 16)
= (\(x\) - 1).(\(x\)2 - 42)
= (\(x\) - 1).(\(x\) - 4)(\(x\) + 4)
= ( x - 2y ) ( x + 2y ) - 2 ( x + 2y )
= ( x + 2y ) ( x - 2y - 2 )
\(x^2-2x-4y^2-4y\)
\(=x^2-4y^2-2x-4y\)
\(=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x-2y-2\right)\)
\(=x\left(a-b\right)-\left(a^2-2ab+b^2\right)=\)
\(=\left(a-b\right)x-\left(a-b\right)^2=\)
\(=\left(a-b\right)\left[x-\left(a-b\right)\right]=\left(a-b\right)\left(x-a+b\right)\)