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d) 3 -x = |-4|

3-x=4

x=-1

e) 35 - |2 x+1|=14

|2 x+1|=21

\(\Leftrightarrow\orbr{\begin{cases}2x+1=21\\2x+1=-21\end{cases}\Leftrightarrow\orbr{\begin{cases}x=10\\x=-11\end{cases}}}\)

f) |x| -3 +6 =16

|x|=13

\(x=\pm13\)

P/s tham khảo nha

d)=>3-x=4

=>x=3-4

=>x=-1

vậy x=-1

e)=>l2x+1l=35-14=21

=>\(\orbr{\begin{cases}2x+1=21\\2x+1=-21\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=21-1=20\\2x=-21-1=-22\end{cases}\Leftrightarrow\orbr{\begin{cases}x=20:2=10\\x=-22:2=-11\end{cases}}}.}\)

vậy x=10,x=-11

f)=>lxl=16-6+3=13

\(\Rightarrow x=\pm13\)

vậy..............

a: x+2/5=1/2

=>x=1/2-2/5=5/10-4/10=1/10

b; x-2/5=2/7

=>x=2/7+2/5=10/35+14/35=24/35

c: 3/5-x=1/10

=>x=3/5-1/10=6/10-1/10=5/10=1/2

d: x*3/4=9/20

=>x=9/20:3/4=9/20*4/3=36/60=3/5

e: x:1/7=14

=>x=14*1/7=2

f: =>x+1/4=2/5:1/2=4/5

=>x=4/5-1/4=16/20-5/20=11/20

g: =>x*2/3=9/12+2/3=3/4+2/3=9/12+8/12=17/12

=>x=17/12:2/3=17/12*3/2=51/24=17/8

7 tháng 10 2019

a, \(\frac{-5}{12}+\frac{4}{37}+\frac{17}{12}-\frac{41}{37}\)

\(=\left(-\frac{5}{12}+\frac{17}{12}\right)+\left[\frac{4}{37}+\left(-\frac{41}{37}\right)\right]\)

\(=1+\left(-1\right)\)

\(=-1\)

b, \(\frac{1}{2}+\left(-\frac{3}{5}\right):\left(-1\frac{1}{2}\right)-\left|-\frac{2}{5}\right|\)

\(=\frac{1}{2}+\left(-\frac{3}{5}\right):\left(-\frac{3}{2}\right)-\frac{2}{5}\)

\(=\frac{1}{2}+\frac{2}{5}-\frac{2}{5}\)

\(=\frac{1}{2}\)

Mấy bài còn lại tương tự bn tự làm nha tính số mũ ra xong thực hiện, lấy thừa số chung mà nhân ( H mik bận đi hc thêm rồi)

8 tháng 4 2018

mấy cái này tíck chéo lên là được 

8 tháng 4 2018

\(a,\frac{x}{7}=\frac{6}{-21}\)

\(\Rightarrow x=\frac{6.7}{-21}\)

\(\Rightarrow x=-2\)

p/s: lm như z đóa cn m câu khác bạn tự lm nhé !

1 tháng 9 2023

\(a,3-x=x+1,8\)

\(\Rightarrow-x-x=1,8-3\)

\(\Rightarrow-2x=-1,2\)

\(\Rightarrow x=0,6\)

\(b,2x-5=7x+35\)

\(\Rightarrow2x-7x=35+5\)

\(\Rightarrow-5x=40\)

\(\Rightarrow x=-8\)

\(c,2\left(x+10\right)=3\left(x-6\right)\)

\(\Rightarrow2x+20=3x-18\)

\(\Rightarrow2x-3x=-18-20\)

\(\Rightarrow-x=-38\)

\(\Rightarrow x=38\)

\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)

\(\Rightarrow8x-3+1=1+6x+x\)

\(\Rightarrow8x-3=7x\)

\(\Rightarrow8x-7x=3\)

\(\Rightarrow x=3\)

\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)

\(\Rightarrow-3x+x=\dfrac{4}{3}-\dfrac{2}{9}\)

\(\Rightarrow-2x=\dfrac{10}{9}\)

\(\Rightarrow x=-\dfrac{5}{9}\)

1 tháng 9 2023

\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1}{2}x-\dfrac{3}{4}x=-\dfrac{1}{2}-\dfrac{5}{6}\)

\(\Rightarrow-\dfrac{1}{4}x=-\dfrac{4}{3}\)

\(\Rightarrow x=\dfrac{16}{3}\)

\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)

\(\Rightarrow x-4=5-x\)

\(\Rightarrow x+x=5+4\)

\(\Rightarrow2x=9\)

\(\Rightarrow x=\dfrac{9}{2}\)

\(k,7x^2-11=6x^2-2\)

\(\Rightarrow7x^2-6x^2=-2+11\)

\(\Rightarrow x^2=9\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

\(m,5\left(x+3\cdot2^3\right)=10^2\)

\(\Rightarrow5\left(x+24\right)=100\)

\(\Rightarrow x+24=20\)

\(\Rightarrow x=-4\)

\(n,\dfrac{4}{9}-\left(\dfrac{1}{6^2}\right)=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{4}{9}-\dfrac{1}{36}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{5}{12}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2=0\)

\(\Rightarrow x-\dfrac{2}{3}=0\Rightarrow x=\dfrac{2}{3}\)

#\(Urushi\text{☕}\)

8 tháng 5 2019

a) x × 5 = 35 – 5

x × 5 = 30

x = 30 : 5

x = 6

b) x : 4 = 12 – 8

x : 4 = 4

x = 4 × 4

x = 16

c) 4 × x = 6 × 2

4 × x = 12

x = 12 : 4

x = 3

d) x : 3 = 16 : 4

x : 3 = 4

x = 4 × 3

x = 12

a: =>4x-4-3x+6=-5

=>x+2=-5

=>x=-7

b: =>\(-4x-4+8x-24=24\)

=>4x-28=24

=>4x=52

=>x=13

c: \(\Leftrightarrow12x-48+6x-12-16x-48=7\cdot4=28\)

=>2x-108=28

=>2x=136

=>x=68

d: =>2|x-6|=2

=>|x-6|=1

=>x=7 hoặc x=5

e: =>|x+2|=20-6x+6x-24=-4(loại)

21 tháng 12 2022

e: =>3x-6=12x-4

=>-9x=2

=>x=-2/9

f: =>5x=x+16

=>4x=16

=>x=4

a) Ta có: x-43=(35-x)-48

⇔x-43=35-x-48

⇔x-43=-x-13

⇔x-43+x+13=0

⇔2x-30=0

⇔2(x-15)=0

mà 2≠0

nên x-15=0

hay x=15

b) Ta có: 305-x+14=48+(x-23)

⇔319-x=48+x-23

⇔319-x=x+25

⇔319-x-x-25=0

⇔-2x+294=0

⇔-2x=-294

hay x=147

Vậy: x=147

c) Ta có: -(x-6+85)=(x+51)-54

⇔-x+6-85=x+51-54

⇔-x-79=x-3

⇔-x-79-x+3=0

⇔-2x-76=0

⇔-2x=76

hay x=-38

Vậy: x=-38

d) Ta có: -(35-x)-(37-x)=33-x

⇔-35+x-37+x-33+x=0

⇔3x-105=0

⇔3(x-35)=0

mà 3≠0

nên x-35=0

hay x=35

Vậy: x=35

e) Ta có: 13-|x|=|-4|

⇔13-|x|=4

⇔|x|=9

⇔x∈{9;-9}

Vậy: x∈{9;-9}

f) Ta có: |x|-3+6=16

⇔|x|+3=16

⇔|x|=13

hay x∈{-13;13}

Vậy: x∈{-13;13}

g) Ta có: 35-|2x-1|=14

⇔|2x-1|=21

\(\left[{}\begin{matrix}2x-1=21\\2x-1=-21\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=22\\2x=-20\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-10\end{matrix}\right.\)

Vậy: x∈{11;-10}

h) Ta có: |3x-2|+5=9-x

⇔|3x-2|+5-9+x=0

⇔|3x-2|-4+x=0

⇔|3x-2|=0-(-4+x)

⇔|3x-2|=4-x

\(\left[{}\begin{matrix}3x-2=4-x\\3x-2=x-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x-2-4+x=0\\3x-2-x+4=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}4x-6=0\\2x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=6\\2x=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{3}{2}\left(ktm\right)\\x=-1\left(tm\right)\end{matrix}\right.\)

Vậy: x=-1