Tìm x :
3 . ( x + 2 ) = 2 . ( 10 - x ) + 16
Ai tick mk, mk tick lại
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x . y - 12 = 2 - x + y
x . y + x - y = 2 + 12
x . y + x - y = 14
x . y + x . 1 - y = 14
x . ( y + 1 ) - y = 14
x . ( y + 1 ) - y - 1 = 14 - 1
x . ( y + 1 ) - ( y + 1 ) . 1 = 13
( x - 1 ) . ( y + 1 ) = 13
\(\Rightarrow x-1\inƯ\left(13\right)\)\(\Rightarrow x-1\in\){ 1 ; 13 }
Lập bảng :
x-1 | 1 | 13 |
y + 1 | 13 | 1 |
x | 2 | 14 |
y | 12 | 0 |
Vậy ( x ; y ) là : ( 2 ; 12 ) ; ( 14 ; 0 )
2x - 7 = 11 - ( 4 - x )
2x - 7 = 11 - 4 + x
2x - x = 11 - 4 + 7
x = 14
Vậy x = 14
2x - 7 = 11 - ( 4 - x )
2x - 7 = 11 - 4 + x
2x - x = 11 - 4 + 7
x = 14
Vậy x = 14
\(\left|x-\frac{1}{2}\right|+\frac{3}{4}=\left|-1,6+\frac{3}{5}\right|\)
\(\Leftrightarrow\left|x-\frac{1}{2}\right|+\frac{3}{4}=\left|-1\right|\)
\(\Leftrightarrow\left|x-\frac{1}{2}\right|+\frac{3}{4}=1\)
\(\Leftrightarrow\left|x-\frac{1}{2}\right|=\frac{1}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{2}=\frac{1}{4}\\x-\frac{1}{2}=-\frac{1}{4}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=\frac{1}{4}\end{cases}}\)
Vậy \(x\in\left\{\frac{3}{4};\frac{1}{4}\right\}\)
\(\text{Ta có: (x - 2) . (x + 10) = 0}\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x+10=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0+2\\x=0-10\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-10\end{cases}}\)
\(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=0\\ 4x^2-4x+1+x^2+6x+9-5x^2+245=0\\ 2x+255=0\\ 2x=-255\\ x=-\dfrac{255}{2}\)
a) 123- 5(x+4)=38 b(3x -2^4 )*7^3= 2*7^4
5(x+4) =123-38 (3x-16) = 2*7^4 /7^3
5(x+4)=85 3x-16= 2*7
x+4=85/5 3x-16=14
x+4=17 3x=30
=>x= 13 x= 30/3=10
Nhớ k cho mk nha
a ) \(123-5.\left(x+4\right)=38\)
\(5.\left(x+4\right)=123-38\)
\(5.\left(x+4\right)=85\)
\(x+4=85:5\)
\(x+4=17\)
\(x=17-4\)
Ta có : 3x - 7/3 - 2x - 1/2 = 7 .
=> x ( 3 - 2 ) - ( 7/3 + 1/2 ) = 7 .
=> x - ( 14/6 + 3/6 ) = 7 .
=> x - 17/6 = 7 .
=> x = 7 + 17/6 .
=> x = 59/6 .
vậy x = 59/6 .
\(3x-\frac{7}{3}-2x-\frac{1}{2}=7\)
\(\Leftrightarrow\left(3x-2x\right)-\left(\frac{7}{3}+\frac{1}{2}\right)=7\)
\(\Leftrightarrow x-\frac{17}{6}=7\)
\(\Leftrightarrow x=7+\frac{17}{6}\)
\(\Leftrightarrow x=\frac{59}{6}\)
3 . ( x + 2 ) = 2 . ( 10 - x ) + 16
3 . x + 3 . 2 = 2 . 10 - 2 . x + 16
3x + 6 = 20 - 2x + 16
3x + 2x = -6 + 20 + 16
5x = 20 - 6 + 16
5x = 14 + 16
5x = 30
x = 30 : 5
x = 6
Vậy x = 6
3.(x+2)=2.(10-x)+16
3x+6=20-2x+16
3x+2x=20-6+16
5x=30
x=30:5
x=6
Vậy x=6