20-[7(x-3)+4]=2
(4600+6400)-7x=3839
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( 4600 + 6400 ) - 7x = 3839
11000 - 7 . x = 3839
7 . x = 11000 - 3839
7 . x = 7161
x = 7161 : 7
x = 1023
Vậy x = 1023
a) (4600 + 6400) -7.x=3839
11000 - 7.x=3839
7.x=11000-3839
7.x=7161
x=7161:7
x=1023
b) (8x-14) :2-2= 341:31
(8x-14):2-2=11
(8x-14):2= 11+2
(8x-14):2=13
8x-14=13.2
8x-14=26
8x=26+14
8x=40
x=40:8
x=5
a)(4600 + 6400) - 7.x = 3839
11000-7x=3839
7x=7161
x=1023
Vậy x=1023
b)[(8x - 14 ) : 2 - 2 ]. 31 = 341
(8x - 14 ) : 2 - 2=11
(8x - 14 ) : 2=13
8x - 14 =26
8x=40
x=5
Vậy x=5
c)2.(x - 3) - x = 4.2^3
2.(x - 3) - x=32
2x-6-x=32
x-6=32
x=38
Vậy x=38
Bài 1 : Tìm x
a, ( 4600 + 6400 ) - 7.x = 3839
11000 - 7.x = 3839
7.x = 11000 - 3839
7.x = 7161
x = 7161: 7
x = 1023
b, [ ( 8x - 14 ) : 2 - 2 ] . 31 = 341
( 8x -14 ) : 2 -2 = 11
( 8x -14 ) : 2 = 13
8x -14 = 26
8x = 40
x = 5
c, 2. ( x -3 ) - x = 4. 23
2x - 6 - x = 32
x - 6 = 32
x = 38
a) 219 - 7(y+1) = 100
7(y+1) = 119
y+1 = 17
y = 16
các bài cn lại lm tương tự nha!
\(\left(6400+4600\right)-7y=3839\)
\(11000-7y=3839\)
\(7y=11000-3839\)
\(7y=7161\)
\(y=7161:7\)
\(y=1023\)
Vậy \(y=1023\)
Tham khảo nhé~
( 6400 + 4600 ) - 7y = 3839
=> 110000 - 7y = 3839
=> 7y = 110000 - 3839
=> 7y = 7161
=> y = 7161 : 7
=> y = 1023
Vậy y = 1023
Học tốt #
a/ 440 + 2 [ 125 - x ] = 546
==> 2 [ 125 - x ] = 546 - 440
==> 2 [ 125 - x ] 106
==> 125 - x = 106 : 2
==> 125 - x = 53 ==> x = 125 - 53 =72
b/ 7x - 33 = 27 : 24
==> 7x - 27 = 27-4 = 23 = 8
==> 7x = 8+ 27
==> 7x = 35 ==> x = 35 : 7 = 5
c/ [ 12x - 43 ] . 83 = 4 . 84
==> [ 12x - 26 ] . 29 = 22 . 212
==> [ 12x - 26 ] . 29 = 214
==> [ 12x - 26 ] = 214 : 29 = 25
==>. 12x = 25 + 26 = 96
==> x = 96 : 12 = 8
d/ 123 - 5. [ x + 4 ] = 38
==> 5. [ x + 4 ] = 123 - 38
==> 5. [ x + 4 ] = 85
==> x + 4 = 85 : 5
==> x + 4 = 17
==> x = 17 - 4 = 13
e/ [ 2600 + 6400 ] - 3.x = 1200
==> 9000 - 3x = 1200
==> 3x = 9000 -1200 = 7800
==> x = 7800 : 3 = 2600
f/ x2 - 72 : 36 = 23
==> x2 - 2 = 23
==> x2 = 23 + 2
==>x2 = 25
==> x2 = 52
==> x = 5
1: Ta có: 7x+6(3-x)=27-20+73
\(\Leftrightarrow7x+18-6x=80\)
\(\Leftrightarrow x=80-18=62\)
Vậy: x=62
2: Ta có: \(6x-5\left(x-7\right)=\left(27-514\right)-486-73\)
\(\Leftrightarrow6x-5x+35=27-514-486-73\)
\(\Leftrightarrow x+35=-1046\)
\(\Leftrightarrow x=-1081\)
Vậy: x=-1081
`a,4x-10=0 `
`<=> 4x=10`
`<=>x=10/4`
`<=>x=5/2`
`b, 7-3x=9-x `
`<=>-3x+x=9-7`
`<=>-2x=2`
`<=>x=-1`
`c, 2x-(3-5x) = 4(x+3)`
`<=>2x-3+5x=4x+12`
`<=>2x+5x-4x=12+3`
`<=>3x=15`
`<=>x=5`
`d, 5-(6-x)=4(3-2x) `
`<=>5-6+x=12-8x`
`<=>x+8x=12-5+6`
`<=>9x=13`
`<=>x=13/9`
`e, 4(x+3)=-7x+17 `
`<=>4x+12=-7x+17`
`<=>4x+7x=17-12`
`<=>11x=5`
`<=>x=5/11`
`f, 5(x-3) - 4=2(x-1)+7`
`<=>5x-15-4=2x-2+7`
`<=>5x-2x=15+4-2+7`
`<=>3x=24`
`<=>x=8`
`g, 5(x-3)-4=2(x-1)+7 `
`<=>5x-15-4=2x-2+7`
`<=>5x-2x=15+4-2+7`
`<=>3x=24`
`<=>x=8`
`h,4(3x-2)-3(x-4)=7x+20`
`<=>12x-8-3x+12=7x+20`
`<=>12x-3x-7x=20+8+12`
`<=>2x=40`
`<=>x=20`