41-2^x+1=9
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1) 41 - 2x + 1 = 9
-2x + 1 = 9 - 41
-2x + 1 = -32
2x + 1 = 32
2x + 1 = 25
x + 1 = 5
x = 5 - 1
x = 4
\(\dfrac{9}{10}\)
\(\dfrac{1}{24}\)
\(\dfrac{5}{2}\)
a) \(x=\dfrac{25}{72}\)
b)\(x=-\dfrac{1}{4}\)
\(x=\dfrac{3}{2}\)
c)\(x=\dfrac{5}{4}\) hoặc
x \(=\dfrac{8}{5}\)
d và e chịu vì mk kg giỏi lắm về mũ
f)\(x=-2\)
G)\(x=-\dfrac{5}{12}\)
\(a,\left(x+6\right)\left(x-3\right)=2\left(x-3\right)\)
\(\Leftrightarrow\left(x+6\right)\left(x-3\right)-2\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+6-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+4=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
\(b,x^2+5x+6=0\)
\(\Leftrightarrow x^2+2x+3x+6=0\)
\(\Leftrightarrow x\left(x+2\right)+3\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=0\\x+3=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-3\end{matrix}\right.\)
\(c,\left(x-1\right)^2=0\)
\(\Leftrightarrow x-1=0\)
\(\Leftrightarrow x=1\)
\(d,\dfrac{x+1}{x-3}-\dfrac{41}{x+3}+\dfrac{x^2-3}{9-x^2}=0\left(dkxd:x\ne\pm3\right)\)
\(\Leftrightarrow\dfrac{x+1}{x-3}-\dfrac{41}{x+3}-\dfrac{x^2-3}{x^2-9}\)\(=0\)
\(\Leftrightarrow\left(x+1\right)\left(x+3\right)-41\left(x-3\right)-x^2+3=0\)
\(\Leftrightarrow x^2+4x+3-41x+123-x^2+3=0\)
\(\Leftrightarrow-37x=-129\)
\(\Leftrightarrow x=\dfrac{129}{37}\left(n\right)\)
−(32)+(𝑥−21)=−1
−32+𝑥−21=−1
−53+𝑥=−1
𝑥−53=−1
𝑥−53+53=−1+53
𝑥=52
\(41-2^{x+1}=9\)
=>\(2^{x+1}=41-9=32\)
=>\(2^{x+1}=2^5\)
=>x+1=5
=>x=5-1=4