- |1,7 - x| - 5/3 = 2/3
Giúp mik vs mik đang cần gấp ạ
Cảm ơn
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\(\left(x+y\right)^3-\left(x-y\right)^3=x^3+3x^2y+3xy^2+y^3-x^3+3x^2y-3xy^2+y^3=6x^2y+2y^3\)
I'd like to visit New York in United States of America OR London in United Kingdom
đây bản dịch : Khi bạn đến một đất nước mới, bạn muốn làm gì đầu tiên?
Vietnam is a wonderful country located in Southeast Asia. The impact of the Western wave on culture has slowed somewhat where it has changed many things. So if a brother or a foreign friend came to Vietnam, would you introduce him to what to do in Vietnam?
In my opinion, here are some things to do when coming to Vietnam:
1. KARAOKE SING
2. at HOMESTAY
3,VISIT SON MY RULES4,EXPERIENCE Phong Nha - Ke Bang National Parkit's great, come to vietnam my country, i will take you to many places. That promise
Bạn tham khảo bài của chị Tuệ Lâm làm nhé!!
Dear Glory,
Vietnam is a wonderful country located in Southeast Asia. The impact of the Western wave on culture has slowed somewhat where it has changed many things. So if a brother or a foreign friend came to Vietnam, would you introduce him to what to do in Vietnam?
In my opinion, here are some things to do when coming to Vietnam:
1. KARAOKE SING
2. at HOMESTAY
3,VISIT SON MY RULES4,EXPERIENCE Phong Nha - Ke Bang National Parkit's great, come to vietnam my country, i will take you to many places. That promise
Friend,
< Ghi tên của bạn vào đây nha! >
Many people using cars and motobikes nowadays, however they have a lot of smoke into the air. It cause air polluted and have much bad effects on people
Fix: pollution
\(\dfrac{x+2}{x-3}+\dfrac{x-2}{x}=\dfrac{x^2+2x+6}{x\left(x-3\right)}\) đkxđ: x khác 3 , x khác 0
\(\Leftrightarrow\dfrac{x\left(x+2\right)}{x\left(x-3\right)}+\dfrac{\left(x-2\right)\left(x-3\right)}{x\left(x-3\right)}-\dfrac{x^2+2x+6}{x\left(x-3\right)}=0\)
\(\Leftrightarrow\dfrac{x^2+2x}{....}+\dfrac{x^2-3x-2x+6}{.....}-\dfrac{x^2+2x+6}{...}=0\)
\(\Leftrightarrow x^2+2x+x^2-3x-2x+6-x^2-2x-6=0\)
\(\Leftrightarrow x^2-5x=0\)
\(\Leftrightarrow x\left(x-5\right)=0\)
\(\Rightarrow\left\{{}\begin{matrix}x=0\left(tm\right)\\x=5\left(tm\right)\end{matrix}\right.\)
\(-\left|1,7-x\right|-\dfrac{5}{3}=\dfrac{2}{3}\\ \Rightarrow\left|1,7-x\right|=-\dfrac{5}{3}-\dfrac{2}{3}=-\dfrac{7}{3}\left(l\right)\)
Vậy không có giá trị x thoả mãn