2.3x+1 = 10. 312 + 8. 312
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\(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=10.3^{12}+8.\left(3^3\right)^4\)
\(2.3^x=18.3^{12}\)
\(3^x=9.3^{12}=3^{14}\)
\(x=14\)
2.3ˣ = 10.3¹² + 8.27⁴
2.3ˣ = 10.3¹² + 8.(3³)⁴
2.3ˣ = 10.3¹² + 8.3¹²
2.3ˣ = 3¹².(10 + 8)
2.3ˣ = 3¹².18
3ˣ = 3¹².18 : 2
3ˣ = 3¹² . 9
3ˣ = 3¹² . 3²
3ˣ = 3¹⁴
x = 14
312 * 425 + 312 * 574 + 312
= 312 x ( 425 + 574 + 1 )
= 312 x 1000
= 312000
k mik nha
=312 x 425 + 312 x 574 + 312 x 1
= 312 x ( 425 + 574 + 1 )
= 312 x 1000 = 312000
Ta có: \(\dfrac{312}{x}-\dfrac{312}{x+4}=\dfrac{1}{2}\)
\(\Leftrightarrow x\left(x+4\right)=624x+2496-624x\)
\(\Leftrightarrow x^2+4x-2496=0\)
\(\Leftrightarrow\left(x+2\right)^2=2500\)
\(\Leftrightarrow\left[{}\begin{matrix}x=48\\x=-52\end{matrix}\right.\)
Lời giải:
1. Bạn coi lại đề
2. $=234\times (1257-257)=234\times 1000=234000$
3. $=175\times (1274-273-1)=175\times 1000=175000$
4. $=(4\times 25)\times (125\times 8)=100\times 1000=100000$
\(2.3^{x+1}=10.3^{12}+8.3^{12}\\ VP=\left(10+8\right).3^{12}=18.3^{12}=2.3^2.3^{12}\\ =2.3^{2+12}=2.3^{14}\\ VT=VP\\ \Rightarrow2.3^{x+1}=2.3^{14}\\ \Rightarrow x+1=14\\ Vậy:x=14-1=13\)
\(2\cdot3^{x+1}=10\cdot3^{12}+8\cdot3^{12}\\\Rightarrow 2\cdot3^{x+1}=3^{12}\cdot(10+8)\\\Rightarrow 2\cdot3^{x+1}=3^{12}\cdot18\\\Rightarrow 2\cdot3^{x+1}=3^{12}\cdot3^2\cdot2\\\Rightarrow 3^{x+1}=3^{12}\cdot3^2\\\Rightarrow 3^{x+1}=3^{14}\\\Rightarrow x+1=14\\\Rightarrow x=14-1\\\Rightarrow x=13\\Vậy:x=13\)