x^3 +2x^2y+xy^2-9x
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\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
`a^3-a^2 x -ay+xy`
`=a^2(a-x)-y(a-x)`
`=(a-x)(x^2-y)`
`x^2-2xy+x-2y`
`= (x^2+x)-(2xy+2y)`
`=x(x+1)-2y(x+1)`
`=(x+1)(x-2y)`
`x^2-2x+2y-xy`
`=x(x-2) + y(2-x)`
`=x(x-2)-y(x-2)`
`=(x-2)(x-y)`
1) \(2\left(x-1\right)^3-\left(x-1\right)=\left(x-1\right)\left(2\left(x-1\right)^2-1\right)\)
2) \(y\left(x-2y\right)^2+xy^2\left(2y-x\right)=\left(2y-x\right)\left(2\left(2y-x\right)+1\right)=\left(2y-x\right)\left(4y-2x+1\right)\)
3) \(xy\left(x+y\right)-x-y=xy\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(xy-1\right)\) (xem lại đề sửa -2x thành -x mới đúng)
4) \(xy\left(x-3y\right)-2x+6y=xy\left(x-3y\right)-2\left(x-3y\right)=\left(x-3y\right)\left(xy-2\right)\)
= ( x3 + 2x2y + xy2 ) - 16x
= x (x2 + 2xy + y2) - 16x
= x( x + y)2 - 16x
= x [ ( x + y)2 - 16 ]
= x ( x + y +4) ( x + y - 4)
a, \(x^3+2x^2+x-xy=x\left(x^2+2x+1-y\right)\)
\(=x\left[\left(x+1\right)^2-y\right]\)
b, \(x^3-y^3+2x^2-2y^2=\left(x-y\right)\left(x^2+xy+y^2\right)+2\left(x^2-y^2\right)\)
\(=\left(x-y\right)\left(x^2+xy+y^2\right)+2\left(x-y\right)\left(x+y\right)\)
\(=\left(x-y\right)\left[\left(x^2+xy+y^2\right)+2\left(x+y\right)\right]\)
\(=\left(x-y\right)\left(x^2+xy+y^2+2x+2y\right)\)
^2 + 4xy - 16 + 4y^2
= x^2 + 4xy + 4y^2 - 4^2
= (x + 2y)^2 - 4^2
= (x + 2y - 4)(x + 2y + 4)
2x^2-5xy-3y^2
= 2^x + xy - 6xy - 3y^2
= x(2x + y) - 3y(2x + y)
= (2x + y)(x - 3y)
a) xy+3x-7y-21
=x(y+3)-7(x+3)
=(x-7)(y+3)
b)2xy-15-6x-5y
=2x(y-3)-5(-3+y)
=(2x-5)(y-3)
c)2x^2y+2xy^2-2x-2y
=2x(xy-1)+2y(xy-1)
=(2x+2y)(xy-1)
x(x+3)-5x(x-5)-5(x+3)
=(x-5)(x+3)-5x(x-5)
=(x-5)(x+3-5x)
Câu cuối mình bị nhầm dòng cuối phải là (x-5)(x+3+x-5)=(x-5)(2x-2)nha bạn
x3 + 2x2y + xy2 - 9x
= x( x2 + 2xy + y2 - 9 )
= x[ ( x2 + 2xy + y2 ) - 9 ]
= x[ ( x + y )2 - 32 ]
= x( x + y - 3 )( x + y + 3 )
Bài làm
\(x^3+2x^2y+xy^2-9x=x\left(x^2+2xy+y^2-9\right)\)
\(=x\left[\left(x+y\right)^2-9\right]=x\left(x+y-3\right)\left(x+y+3\right)\)