Giúp tớ với,năn nit đấyyy,tớ cần gấpp
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When a tropical storm reaches 120 kilometers per hour, it is called a typhoon
Wearing uniforms encourages students to be proud of being students of their school
the weather was snowy, we couldn't go to work yesterday
put the garbage into the dustbins, we will minimize pollution
so slowly that his students get bored
difficult to find a better solution
When a tropical storm reaches 120 kilometers per hour, it is called a typhoon
Wearing uniforms encourages students to be proud of being students of their school
the weather was snowy, we couldn't go to work yesterday
put the garbage into the dustbins, we will minimize pollution
so slowly that his students get bored
difficult to find a better solution
17 surprisingly
18 time-consuming
19 replacing
20 independent
21 qualifications
22 activists
The Internet provides us with a rich source of educational materials and courses.
Facebook has become very popular today because it makes communication around the world very easy
on working despite the rain
worked as a fashion designer for 2 years
I would join your family on the trip to your home village
schoolyard should be kept clean
- Giống nhau: có hoa văn khắc hình chim, mái nhà, cảnh sinh hoạt.
- Khác nhau: khác nơi phát hiện và Trống đồng Cổ Loa có ý nghĩa là trong việc nghiên cứu lịch sử thời dựng nước của dân tộc ta, còn trống đồng Hoàng Hạ góp phần dựng lại bức tranh lịch sử của Hà Nội.
1) \(A=\left|\dfrac{3}{5}-x\right|+\dfrac{1}{9}\ge\dfrac{1}{9}\left(\left|\dfrac{3}{5}-x\right|\ge0,\forall x\in R\right)\)
Dấu "=" xảy ra \(\Leftrightarrow\dfrac{3}{5}-x=0\Leftrightarrow x=\dfrac{3}{5}\)
\(\Rightarrow GTNN\left(A\right)=\dfrac{1}{9}\left(khi.x=\dfrac{3}{5}\right)\)
2) \(A=\left|\dfrac{x}{3}-\dfrac{3}{2}\right|+\dfrac{2}{3}\ge\dfrac{2}{3}\left(\left|\dfrac{x}{3}-\dfrac{3}{2}\right|\ge0,\forall x\in R\right)\)
Dấu "=" xảy ra \(\Leftrightarrow\dfrac{x}{3}-\dfrac{3}{2}=0\Leftrightarrow x=3.\dfrac{3}{2}=\dfrac{9}{2}\)
\(\Rightarrow GTNN\left(A\right)=\dfrac{2}{3}\left(khi.x=\dfrac{9}{2}\right)\)
12) \(A=\dfrac{6}{11}+2\left|\dfrac{5}{8}x+\dfrac{3}{5}\right|\ge\dfrac{6}{11}\left(2\left|\dfrac{5}{8}x+\dfrac{3}{5}\right|\ge0,\forall x\in R\right)\)
Dấu "=" xảy ra khi \(\dfrac{5}{8}x+\dfrac{3}{5}=0\Leftrightarrow x=-\dfrac{8}{5}.\dfrac{3}{5}=-\dfrac{24}{25}\)
\(\Rightarrow GTNN\left(A\right)=\dfrac{6}{11}\left(khi.x=-\dfrac{24}{25}\right)\)