Trục căn thức ở mẫu -2/3căn11
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Những câu hỏi liên quan
DT
1
14 tháng 9 2017
\(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{2}}=\frac{\sqrt{2}\left(\sqrt{5}-\sqrt{3}\right)}{2}\)
15 tháng 9 2021
\(\dfrac{3}{\sqrt{5}+\sqrt{2}}=\dfrac{3\left(\sqrt{5}-\sqrt{2}\right)}{3}=\sqrt{5}-\sqrt{2}\)
PL
0
30 tháng 9 2021
\(\dfrac{1}{2+\sqrt{3}}+\dfrac{1}{2-\sqrt{3}}=\dfrac{2-\sqrt{3}}{\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)}+\dfrac{2+\sqrt{3}}{\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}\)
\(=\dfrac{2-\sqrt{3}}{4-3}+\dfrac{2+\sqrt{3}}{4-3}=2-\sqrt{3}+2+\sqrt{3}=4\)
H9
HT.Phong (9A5)
CTVHS
25 tháng 7 2023
\(\dfrac{4}{\sqrt{5}-\sqrt{2}}+\dfrac{3}{\sqrt{5}-2}-\dfrac{2}{\sqrt{3}-2}-\dfrac{\sqrt{3}-1}{6}\)
\(=\dfrac{4\left(\sqrt{2}+\sqrt{5}\right)}{\left(\sqrt{5}-\sqrt{2}\right)\left(\sqrt{2}+\sqrt{5}\right)}+\dfrac{3\left(\sqrt{5}+2\right)}{\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)}-\dfrac{2\left(\sqrt{3}+2\right)}{\left(\sqrt{3}-2\right)\left(\sqrt{3}+2\right)}-\dfrac{\sqrt{3}-1}{6}\)
\(=\dfrac{4\left(\sqrt{2}+\sqrt{5}\right)}{\left(\sqrt{5}\right)^2-\left(\sqrt{2}\right)^2}+\dfrac{3\left(\sqrt{5}+2\right)}{\left(\sqrt{5}\right)^2-2^2}-\dfrac{2\left(\sqrt{3}+2\right)}{\left(\sqrt{3}\right)^2-2^2}-\dfrac{\sqrt{3}-1}{6}\)
\(=\dfrac{4\left(\sqrt{2}+\sqrt{5}\right)}{3}+\dfrac{3\left(\sqrt{5}+2\right)}{1}-\dfrac{2\left(\sqrt{3}+2\right)}{-1}-\dfrac{\sqrt{3}-1}{6}\)
\(=\dfrac{8\left(\sqrt{2}+\sqrt{5}\right)}{6}+\dfrac{18\left(\sqrt{5}+2\right)}{6}+\dfrac{12\left(\sqrt{3}+2\right)}{6}-\dfrac{\sqrt{3}-1}{6}\)
\(=\dfrac{8\sqrt{2}+8\sqrt{5}+18\sqrt{5}+36+12\sqrt{3}+24-\sqrt{3}+1}{6}\)
\(=\dfrac{8\sqrt{2}+26\sqrt{5}+11\sqrt{3}+61}{6}\)
25 tháng 7 2023
\(=\dfrac{4\left(\sqrt{5}+\sqrt{2}\right)}{3}+\dfrac{3\left(\sqrt{5}+2\right)}{1}+\dfrac{2\left(2+\sqrt{3}\right)}{1}-\dfrac{\sqrt{3}-1}{6}\)
\(=\dfrac{4\sqrt{5}+4\sqrt{2}+9\sqrt{5}+18}{3}+\dfrac{4+2\sqrt{3}}{1}-\dfrac{\sqrt{3}-1}{6}\)
\(=\dfrac{2\left(13\sqrt{5}+4\sqrt{2}+18\right)+24+12\sqrt{3}-\sqrt{3}+1}{6}\)
\(=\dfrac{26\sqrt{5}+4\sqrt{2}+36+25+11\sqrt{3}}{6}\)
\(=\dfrac{61+11\sqrt{3}+26\sqrt{5}+4\sqrt{2}}{6}\)
4 tháng 7 2021
Ta có: \(\dfrac{2}{5-\sqrt{2}-\sqrt{3}}\)
\(=\dfrac{2\left(5+\sqrt{2}+\sqrt{3}\right)}{5^2-\left(\sqrt{2}+\sqrt{3}\right)^2}\)
\(=\dfrac{2\left(5+\sqrt{2}+\sqrt{3}\right)}{25-5-2\sqrt{6}}\)
\(=\dfrac{2\left(5+\sqrt{2}+\sqrt{3}\right)}{20-2\sqrt{6}}\)
\(=\dfrac{5+\sqrt{2}+\sqrt{3}}{10-\sqrt{6}}\)
\(=\dfrac{\left(5+\sqrt{2}+\sqrt{3}\right)\left(10+\sqrt{6}\right)}{94}\)
\(=\dfrac{50+5\sqrt{6}+10\sqrt{2}+2\sqrt{3}+10\sqrt{3}+3\sqrt{2}}{94}\)
\(=\dfrac{50+5\sqrt{6}+13\sqrt{2}+12\sqrt{3}}{94}\)
\(\dfrac{-2}{3\sqrt{11}}\\ =\dfrac{-2\sqrt{11}}{3\cdot11}\\ =\dfrac{-2\sqrt{11}}{33}\)