tìm x
\(10^6-55\%.x=45\%.x\)
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NT
0
DT
0
PT
1
22 tháng 4 2018
(x/6+x/10+...+x/66+x/78)*2=220/39*2
x/12+x/20+...x/132+x/156=440/39
x/2-x/3+x/3-x/4+...+x/11-x/12+x/12-x/13=440/39
x/2-x/13=440/39
11x/26=440/39
33x/78=880/78
33x=880
x=880/33
x=80/3=26, (6)
OY
10 tháng 8 2021
\(x.\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+...+\dfrac{1}{78}\right)=\dfrac{220}{39}\)
\(x.\dfrac{20}{39}=\dfrac{220}{39}\)
\(x=\dfrac{220}{39}:\dfrac{20}{39}\)
x\(=11\)
DT
0
VQ
3
OY
31 tháng 5 2021
x.(\(\dfrac{1}{6}\)+\(\dfrac{1}{10}\)+\(\dfrac{1}{15}\)+\(\dfrac{1}{21}\)+\(\dfrac{1}{28}\)+\(\dfrac{1}{36}\)+\(\dfrac{1}{45}\)+\(\dfrac{1}{55}\)+\(\dfrac{1}{66}\)+\(\dfrac{1}{78}\))=\(\dfrac{220}{39}\)
x.\(\dfrac{20}{39}\)=\(\dfrac{220}{39}\)
x=\(\dfrac{220}{39}\):\(\dfrac{20}{39}\)
x=11
LA
3 tháng 3 2018
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{55}+\frac{x}{66}+\frac{x}{78}+\frac{x}{78}=\frac{220}{39}\)
\(\Leftrightarrow x\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}+\frac{1}{55}+\frac{1}{66}+\frac{1}{78}+\frac{1}{78}\right)=\frac{220}{39}\)
\(\Leftrightarrow x\cdot\frac{20}{39}=\frac{220}{39}\Rightarrow x=11\)
3 tháng 3 2018
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{55}+\frac{x}{66}+\frac{x}{78}+\frac{x}{78}=\frac{220}{39}\)
\(=>x=\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}+\frac{1}{55}+\frac{1}{66}+\frac{1}{78}+\frac{1}{78}=\frac{220}{39}\)
\(x\cdot\frac{20}{39}=\frac{220}{39}\)
\(x=\frac{220}{39}:\frac{20}{39}=11\)
106=45%.x + 55%.x
106=x.(45%+55%)
106.1=x.1
106=x
10^6=100%x=x
nên x=10^6