cho biết: 12/x = -9/15. Vậy x bằng
A. x = 20
B. x = -20
C. x = 180
d. -3
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a) x + 10 = 20
<=> x = 20 - 10 = 10
Vậy x = 10
b) 2x + 15 = 35
<=> 2x = 35 - 15 = 20
<=> x = 10
Vậy x = 10
c) 3(x + 2) = 15
<=> x + 2 = 15 : 3 = 5
<=> x = 5 - 2 = 3
Vậy x = 3
d) 10x + 15.11 = 20.10
<=> 10x + 165 = 200
<=> 10x = 200 - 165 = 35
<=> x = 35 : 10 = 3,5
Vậy x = 3,5
e) 4(x + 2) = 3.4
<=> x + 2 = 3
<=> x = 3 - 2 = 1
Vậy x = 1
f) 33x + 135 = 26.9
<=> 33x + 135 = 234
<=> 33x = 234 - 135 = 99
<=> x = 99 : 33 = 3
Vậy x = 3
g) 2x + 15 + 16 + 17 = 100
<=> 2x + 48 = 100
<=> 2x = 100 - 48 = 52
<=> x = 52 : 2 = 26
Vậy x = 26
h) 2(x + 9 + 10 + 11) = 4.12.5
<=> x + 30 = 120
<=> x = 120 - 30 = 90
Vậy x = 90
\(a,\dfrac{12}{5}=\dfrac{x}{1,5}\Rightarrow x=\dfrac{12\cdot1,5}{5}=3,6\\ b,\dfrac{x}{5}=\dfrac{3}{20}\Rightarrow x=\dfrac{5\cdot3}{20}=\dfrac{3}{4}\\ c,\dfrac{4}{x}=\dfrac{10}{9}\Rightarrow x=\dfrac{4\cdot9}{10}=\dfrac{18}{5}\\ d,\Rightarrow\dfrac{x}{15}=\dfrac{60}{x}\Rightarrow x^2=60\cdot15=900\Rightarrow\left[{}\begin{matrix}x=30\\x=-30\end{matrix}\right.\\ 2,\)
a, Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{x+y-z}{3+5-6}=\dfrac{8}{2}=4\\ \Rightarrow\left\{{}\begin{matrix}x=12\\y=20\\z=24\end{matrix}\right.\)
b, Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{x-y+z}{3-5+6}=\dfrac{-4}{4}=-1\\ \Rightarrow\left\{{}\begin{matrix}x=-3\\y=-5\\z=-6\end{matrix}\right.\)
c, Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{2y}{10}=\dfrac{3z}{18}=\dfrac{x-2y+3z}{3-10+18}=\dfrac{-33}{11}=-3\\ \Rightarrow\left\{{}\begin{matrix}x=-9\\y=-15\\z=-18\end{matrix}\right.\)
d, Đặt \(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=k\Rightarrow x=3k;y=5k;z=6k\)
\(x^2-4y^2+2z^2=-475\\ \Rightarrow9k^2-100k^2+72z^2=-475\\ \Rightarrow-19k^2=-475\\ \Rightarrow k^2=25\Rightarrow\left[{}\begin{matrix}k=5\\k=-5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=15;y=25;z=30\\x=-15;y=-25;z=-30\end{matrix}\right.\)
`[ ( 2 xx x - 11 ) : 3 + 1 ] xx 5 = 20`
`( 2 xx x - 11 ) : 3 + 1=20:5`
`( 2 xx x - 11 ) : 3 + 1=4`
`( 2 xx x - 11 ) : 3 =4-1`
`( 2 xx x - 11 ) : 3 =3`
`2xx x -11=3xx3`
`2xx x -11=9`
`2xx x =9+11`
`2 xx x=20`
`x=20:2`
`x=10`
Vậy `x=10`
`b, x - 96 = ( 443 - x ) - 15`
`x-96=443-x-15`
` x+x=443-15+96`
`2x=524`
`x=524:2`
`x= 262`
Vậy `x=262`
\(#Nqoc\)
`a)`
\([ ( 2 \times x - 11 ) \div 3 + 1 ] \times 5 = 20\)
`(2 \times x - 11) \div 3 + 1 = 20 \div 5`
`(2 \times x - 11) \div 3 + 1 = 4`
`(2 \times x - 11) \div 3 = 4 - 1`
`(2 \times x - 11) \div 3 = 3`
`2 \times x - 11 = 3 \times 3`
`2 \times x - 11 = 9`
`2 \times x = 9 + 11`
`2 \times x = 20`
`x = 20 \div 2`
`x = 10`
Vậy, `x = 10`
`b)`
\(x - 96 = ( 443 - x ) - 15\)
`x - 96 = 443 - x - 15`
`x - 96 = 428 - x`
`x = 428 - x + 96`
`x = 524 - x`
`x - 524 + x = 0`
`(x + x) - 524 = 0`
`2x - 524 = 0`
`2x = 524`
`x = 524 \div 2`
`x = 262`
Vậy, `x = 262.`
\(\dfrac{8}{9}\) : ( 2 - 3 \(\times\) y) = \(\dfrac{5}{3}\)
2 - 3 \(\times\) y = \(\dfrac{8}{9}\) : \(\dfrac{5}{3}\)
2 - 3 \(\times\) y = \(\dfrac{8}{15}\)
3 \(\times\) y = 2 - \(\dfrac{8}{15}\)
3 \(\times\) y = \(\dfrac{22}{15}\)
y = \(\dfrac{22}{15}\) : 3
y = \(\dfrac{22}{45}\)
\(\dfrac{12}{x}=\dfrac{-9}{15}\)
\(\dfrac{12}{x}=\dfrac{-3}{5}\)
\(x=-\dfrac{12\times5}{3}\)
\(x=-20\)
`12/x=-9/15`
`=>12*15=-9*x`
`=>-9*x=180`
`=>x=180:(-9)`
`=>x=-20`
`=>B`