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a: BC=căn 6^2+8^2=10cm
AM=BC/2=5cm
b:
ΔAEH vuông tại A có AI là trung tuyến
nên IH=IA
=>góc IHA=góc IAH
góc IAH+góc MAB
=góc MBA+góc IHA=90 độ
=>góc IAM=90 độ
=>AI vuông góc AM
\(\lim\dfrac{3^n+2.6^n}{6^{n-1}+5.4^n}=\lim\dfrac{6^n\left[\left(\dfrac{3}{6}\right)^n+2\right]}{6^n\left[\dfrac{1}{6}+5\left(\dfrac{4}{6}\right)^n\right]}=\lim\dfrac{\left(\dfrac{3}{6}\right)^n+2}{\dfrac{1}{6}+5\left(\dfrac{4}{6}\right)^n}=\dfrac{0+2}{\dfrac{1}{6}+0}=12\)
\(\lim\left(\sqrt{n^2+9}-n\right)=\lim\dfrac{\left(\sqrt{n^2+9}-n\right)\left(\sqrt{n^2+9}+n\right)}{\sqrt{n^2+9}+n}=\lim\dfrac{9}{\sqrt{n^2+9}+n}\)
\(=\lim\dfrac{n\left(\dfrac{9}{n}\right)}{n\left(\sqrt{1+\dfrac{9}{n^2}}+1\right)}=\lim\dfrac{\dfrac{9}{n}}{\sqrt{1+\dfrac{9}{n^2}}+1}=\dfrac{0}{1+1}=0\)
\(\lim\dfrac{\sqrt{15+9n^2}-3}{5-n}=\lim\dfrac{n\sqrt{\dfrac{15}{n^2}+9}-3}{5-n}=\lim\dfrac{n\left(\sqrt{\dfrac{15}{n^2}+9}-\dfrac{3}{n}\right)}{n\left(\dfrac{5}{n}-1\right)}\)
\(=\lim\dfrac{\sqrt{\dfrac{15}{n^2}+9}-\dfrac{3}{n}}{\dfrac{5}{n}-1}=\dfrac{\sqrt{9}-0}{0-1}=-3\)
Ex1
1 usually walks
2 does - usually get
3 rarely washes
4 Do - often visit
5 isn't often
6 usually walks
7 is occasionally
8 am hardly
9 are always
10 often washes
Ex2
1 are working
3 are making
3 is having
4 is reading
5 is studying
6 am studying
7 is having
8 aren't studying
9 is having
10 are making
Bài 1:
a: \(A=\left\{2\right\}\)
b: \(B=\left\{0;4;5\right\}\)
3.Have you finished your homework yet?
5.I have never donated blood before
tớ biết mỗi 2 câu này thôi
69 scared
70 energetically
71slavery
72 colorfully
73complaint
74 suggestions
75 prohibition
76 uneatable
77 protection
78 celebrations
79nominated
80 unexpected
81 energetic
82 effectively
83 wasted
84products
85 voluntarily
86 respiratory
87 careless
88 cultural
89 unpolluted
90 electrician
91 preserve
92 installed
\(\text{#♪◈₰♣}\)