If \(\frac{x+24}{16}=\frac{45}{24}\)then \(x\)
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\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.\frac{24}{25}...\frac{63}{64}\)
\(=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.\frac{4.6}{5.5}...\frac{7.9}{8.8}\)
\(=\frac{1.3.2.4.3.5.4.6...7.9}{2.2.3.3.4.4.5.5...8.8}\)
\(=\frac{1.9}{2.8}=\frac{9}{16}\)
ĐKXĐ: x≠8
Ta có: \(\frac{3}{2x-16}+\frac{3x-20}{x-8}+\frac{1}{8}=\frac{13x-102}{3x-24}\)
\(\Leftrightarrow\frac{3}{2\left(x-8\right)}+\frac{3x-20}{x-8}+\frac{1}{8}-\frac{13x-102}{3\left(x-8\right)}=0\)
\(\Leftrightarrow\frac{9}{6\left(x-8\right)}+\frac{6\left(3x-20\right)}{6\left(x-8\right)}+\frac{6\left(x-8\right)}{48\left(x-8\right)}-\frac{2\left(13x-102\right)}{6\left(x-8\right)}=0\)
\(\Leftrightarrow9+6\left(3x-20\right)+6\left(x-8\right)-2\left(13x-102\right)=0\)
\(\Leftrightarrow9+18x-120+6x-48-26x+204=0\)
\(\Leftrightarrow45-2x=0\)
\(\Leftrightarrow2x=45\)
hay \(x=\frac{45}{2}\)(tm)
Vậy: \(x=\frac{45}{2}\)
Ta nhận thấy mẫu của biểu thức trên là:
x26+x24+x22+...+x2+1=(x26+x22+...+x2)+(x24+x20+...+x4+1)
=x2(x24+x20+...+x16+...+1)+(x24+x20+...+x4+1)
=(x24+x20+...+1)(x2+1)
Như vậy\(\frac{x^{24}+x^{20}+x^{16}+...+1}{\left(x^{24}+x^{20}+...+1\right)\left(x^2+1\right)}\)=\(\frac{1}{x^2+1}\)
\(B=\frac{1+x^2+x^4+...+x^{26}}{1+x^4+x^8+...+x^{24}}\)
\(=\frac{\frac{\left(x^2-1\right)\left(1+x^2+x^4+...+x^{26}\right)}{x^2-1}}{\frac{\left(x^4-1\right)\left(1+x^4+x^8+...+x^{24}\right)}{x^4-1}}\)
\(=\frac{\frac{x^{28}-1}{x^2-1}}{\frac{x^{28}-1}{x^4-1}}=\frac{x^4-1}{x^2-1}=x^2+1\)
x + 3/16 = -5/24
=> x = -5/24 - 3/16
=> x = -19/48
Vậy x = -19/48
\(x+\frac{3}{16}=-\frac{5}{24}\)
\(x=-\frac{5}{24}-\frac{3}{16}\)
\(x=-\frac{19}{48}\)
\(\frac{x+24}{16}=\frac{45}{24}\)
<=> \(\frac{\left(x+24\right)x24}{16x45}\)
<=> \(\frac{\left(x+24\right)x24}{720}\)
<=> x+24 = 720 : 24
<=> x+24 = 30
<=> x = 30-24
<=>x = 6
vậy x=6
=>(x+24)x24=45x16
=>(x+24)x24=720
=>x+ 24=30
=>x=6