tim x biet /3x+1/+/4-x/=3
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\(\left(\dfrac{3x}{4}+5\right)-\left(\dfrac{2x}{3}-4\right)-\left(\dfrac{x}{6}+1\right)=\left(\dfrac{1}{3}+4\right)-\left(\dfrac{1}{3}x-3\right)\)
\(\Leftrightarrow\dfrac{3x}{4}-\dfrac{2x}{3}-\dfrac{x}{6}+5+4-1=\dfrac{13}{3}-\dfrac{1}{3}x+9\)
\(\Leftrightarrow\dfrac{9x-8x-2x}{12}+8=\dfrac{13-x}{3}+\dfrac{27}{3}\)
\(\Leftrightarrow\dfrac{-x}{12}+\dfrac{96}{12}=\dfrac{40-x}{3}\Leftrightarrow\dfrac{96-x}{12}=\dfrac{160-4x}{12}\)
\(\Rightarrow96-160=-4x+x\Leftrightarrow-64=-3x\Leftrightarrow x=\dfrac{64}{3}\)
3/4x + 5-(2/3x-4)-(1/6+1)=(1/3x+4)-(1/3x-3)
=3/4x+5-2/3x-4-1/6x+1=1/3x+4-1/3x-3
=-1/12=7
x=84
Đ/S...
ta co (2x-1)(3x+1)+(3x+4)(3-2x)=5
(=)6x2-3x+2x-1+6x-6x2+12-8x=5
(=)-4x+11=5
(=)-4x=-6
(=)x=3/2
(2x-1)(3x+1)+(3x-4)(3-2x)=5
<=> 6x2+2x-3x-1+9x-6x2-12+8x=5
<=> 16x-13=5
<=> 16x = 18
<=> x=9/8
\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
\(\Rightarrow\frac{1}{9x}=\frac{-21}{4}\)
\(\Rightarrow-189x=4\)
\(\Rightarrow x=-\frac{4}{189}\)
1/4 + 1/3 :3x= -5
=> 1/3 : 3x= (-5) - 1/4 = -21/4
=> 3x = -4/63
=> x = -4/189
nhớ cho mk nha
nhận xét 3 >0
=> /3x+1/= 3x+1
/4-x/= 4-x
ta có 3x+1 + 4 -x = 3
=> 2x + 5 = 3
=> 2x = -2
=> x= -1
cam on ban Nguyen Quang Tung