các bạn giải chi tiết hộ mình nhé
Tìm x, biết
a)x : 9/7 = -3,5
b)0,4 x X -1/5 x =3/4
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a. \(1-2x< 7\)
mà: \(1-n\le1\)với mọi n
\(\Rightarrow2x=n\Rightarrow x=\frac{n}{2}\)với mọi n
b.để: (x-1).(x-2)>0
=> x-1>0hoặc x-2<0
=>x>1hoặc x<2
(mik chỉ làm 2 câu mẫu thôi, bạn cố gắng tự làm nha, rất vui được kết bạn với bạn)
a, 1 - 2x < 7
=> -2x < 6
=> x < -3
=> x thuộc {-4; -5; -6; ...}
b, \(\left(x-1\right)\left(x-2\right)>0\)
th1 :
\(\hept{\begin{cases}x-1< 0\\x-2< 0\end{cases}\Rightarrow\hept{\begin{cases}x< 1\\x< 2\end{cases}\Rightarrow}x< 1\Rightarrow x\in\left\{0;-1;-2;...\right\}}\)
th2 :
\(\hept{\begin{cases}x-1>0\\x-2>0\end{cases}\Rightarrow\hept{\begin{cases}x>1\\x>2\end{cases}\Rightarrow}x>2\Rightarrow x\in\left\{3;4;5;...\right\}}\)
vậy_
c tương tự b
\(a.1-2x< 7\Leftrightarrow2x< 7+1=8\Leftrightarrow x< 8:2\Leftrightarrow x< 4\)
Vậy x < 4
\(b.\left(x-1\right)\left(x-2\right)>0\)
\(\Leftrightarrow\orbr{\begin{cases}x-1>0;x-2>0\\x-1< 0;x-2< 0\end{cases}}\)
\(TH1\Leftrightarrow\orbr{\begin{cases}x-1>0\\x-2>0\end{cases}\Leftrightarrow\orbr{\begin{cases}x>0+1=1\\x>0+2=2\end{cases}\Rightarrow x>2}}\)
\(TH2\Leftrightarrow\orbr{\begin{cases}x-1< 0\\x-2< 0\end{cases}\Leftrightarrow\orbr{\begin{cases}x< 0+1=1\\x< 0+2=2\end{cases}\Rightarrow}}x< 2\)
Vậy \(x\ne2\)
`5/9+4/9:x=1/3`
`=>4/9:x=1/3-5/9`
`=>4/9:x=3/9-5/9`
`=>4/9:x=-2/9`
`=>x=4/9:(-2/9)`
`=>x=4/9.(-9/2)`
`=>x=-4/2`
`=>x=-2`
=>(-12x)-(-60)+21-7x=5
=>(-12x)+60+21-7x=5
=>(-12x-7x)=5-(60+21)=-76
=>(-19x)=-76=>x=4
Vậy x=4
-12(x-5)+7(3-x)=5
-12.x+12.5+7.3-7.x
-19x+60+21=5
-19x=-76
x=-76:(-19)=4
Vậy x=4
1.
=3/5x(3/7+4/7)+2/5x(13/9-4/9)
=3/5x1+2/5x1
=3/5+2/5
=1
2.Xx(3/4+4/5)=7/10
Xx31/20=7/10
X =7/10:31/20
X =14/31
\(\frac{3}{5}\cdot\frac{3}{7}+\frac{3}{5}\cdot\frac{4}{7}+\frac{2}{5}\cdot\frac{13}{9}-\frac{2}{5}\cdot\frac{4}{9}\)
\(=\frac{3}{5}\cdot\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{2}{5}\cdot\left(\frac{13}{9}-\frac{4}{9}\right)\)
\(=\frac{3}{5}\cdot1+\frac{2}{5}\cdot1\)\(=\frac{3}{5}+\frac{2}{5}=1\)
_________________________________________
\(\frac{3}{4}\cdot x+\frac{4}{5}\cdot x=\frac{7}{10}\)
\(\left(\frac{3}{4}+\frac{4}{5}\right)\cdot x=\frac{7}{10}\)
\(\frac{31}{20}\cdot x=\frac{7}{10}\)
\(x=\frac{7}{10}:\frac{31}{20}\)
\(x=\frac{14}{31}\)
12,65 x X + X x 27,35 = 9
(12,65 + 27,35) x X = 9
40 x X = 9
X = 9 : 40
X = 0,225
a)12,65 x x + x x 27,35 = 9
x x ( 12,65 + 27,35 ) = 9
x x 40 = 9
x=\(\frac{9}{40}\)
b)11x(x-5)=5x(x+11)
11x-55=5x+55
11x-55-5x-55=0
6x-110=0
6x=110
x=\(\frac{55}{3}\)
\(a,\frac{1}{2}x+\frac{5}{2}=\frac{7}{2}x-\frac{3}{4}\)
\(\Leftrightarrow\frac{1}{2}x+\frac{5}{2}-\frac{7}{2}x=-\frac{3}{4}\)
\(\Leftrightarrow\frac{1}{2}x-\frac{7}{2}x+\frac{5}{2}=-\frac{3}{4}\)
\(\Leftrightarrow-3x+\frac{5}{2}=-\frac{3}{4}\)
\(\Leftrightarrow-3x=-\frac{13}{4}\)
\(\Leftrightarrow x=-\frac{13}{4}:(-3)=-\frac{13}{4}:\frac{-3}{1}=-\frac{13}{4}\cdot\frac{-1}{3}=\frac{13}{12}\)
\(b,\frac{2}{3}x-\frac{2}{5}=\frac{1}{2}x-\frac{1}{3}\)
\(\Leftrightarrow\frac{2}{3}x-\frac{2}{5}-\frac{1}{2}x=-\frac{1}{3}\)
\(\Leftrightarrow\frac{2}{3}x-\frac{1}{2}x-\frac{2}{5}=-\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{6}x-\frac{2}{5}=-\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{6}x=\frac{1}{15}\)
\(\Leftrightarrow x=\frac{1}{15}:\frac{1}{6}=\frac{1}{15}\cdot6=\frac{6}{15}=\frac{2}{5}\)
\(c,\frac{1}{3}x+\frac{2}{5}(x+1)=0\)
\(\Leftrightarrow\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\)
\(\Leftrightarrow\frac{11}{15}x=-\frac{2}{5}\)
\(\Leftrightarrow x=-\frac{6}{11}\)
d,e,f Tương tự
\(x-\frac{3}{5}=1\div3\)
\(x-\frac{3}{5}=\frac{1}{3}\)
\(x=\frac{1}{3}+\frac{3}{5}=\frac{14}{15}\)
Chắc x 1/6 = 5 : 4 là phép nhân
\(x\times\frac{1}{6}=5\div4\)
\(x\times\frac{1}{6}=\frac{5}{4}\)
\(x=\frac{5}{4}\div\frac{1}{6}\)
\(x=\frac{15}{2}\)
x-3/5=1/3
x=1/3+3/5
x=14/15
x.1/6=5/4
x=5/4:1/6
x=5/4x6
x=15/2
a) \(x=-\dfrac{3}{5}\times\dfrac{9}{7}=-\dfrac{27}{35}\)
b) \(x\left(0,4-\dfrac{1}{5}\right)=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)
a, \(x=-3,5.\dfrac{9}{7}=-\dfrac{9}{2}\)
b, \(\dfrac{2}{5}x-\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)