- Tìm x thõa mãn
a, \(5^x+5^{x+2}=650\)
b, \(3^{x-1}+5.3^{x-1}=162\)
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3x-1+5.3x-1=162
=>3x-1.(1+5)=162
=>3x-1.6=162=>3x-1=162:6=27=33
=>x-1=3=>x=4
5x+5x+2=650
=>5x+5x.52=650
=>5x.(1+25)=650
=>5x.26=650=>5x=650:26=25=52
=>x=2
a) \(5^x+5^{x+2}=650\)
\(5^x+5^x.5^2=650\)
\(5^x.\left(1+5^2\right)=650\)
\(5^x.26=650\)
\(5^x=25\)
\(5^x=5^2\)
\(\Rightarrow x=2\)
Vậy x = 2
b) \(3^{x-1}+5.3^{x-1}=162\)
\(3^{x-1}.\left(1+5\right)=162\)
\(3^{x-1}.6=162\)
\(3^{x-1}=162:6\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(x=3+1\)
\(x=4\)
Vậy x = 4
a) 5x+5x + 2 = 650
=> 5x+ 5x.52 = 650
=> 5x(1+ 52) = 650
=> 5x.26 = 650
=> 5x = 650:26
=> 5x = 25
=> 5x = 52
=> x = 2
Vậy x = 2
b) 3x-1 + 5.3x-1 = 162
=> 3x-1(1+5) = 162
=> 3x-1. 6 = 162
=> 3x-1 = 162
=> x ko có giá trị
Vậy x ko tìm đc giá trị thỏa mãn đề bài.
a) 5^x + 5^x+2 = 650
<=> 5^x. (1+5^2)= 650
<=> 5^x. 26= 650
<=> 5^x= 25
=> x= 2
b) 3^x-1 + 5.3^x-1 = 162
<=> 3^x-1. (1+5)= 162
<=> 3^x+1. 6= 162
<=> 3^x+1= 27
=> x+1= 3
=> x= 2
a, 5x+5x+2=650
<=>5x+5x.52=650
<=>5x.(1+52)=650
<=>5x.26=650
=>5x=650:26
=>5x=25=52
=>x=2
b, 3x-1+5.3x-1=162
<=>3x-1.(5+1)=162
<=>3x-1.6=162
=>3x-1=162:6
=>3x-1=27=33
=>x-1=3
=>x=3+1
=>x=4
Chúc bạn học giỏi nha!!!
K cho mik với nhé Nguyễn Công Đạt
Ta Có ;
a. 5x + 5x+2 = 650
=> 5x ( 1 + 25 ) = 650
=> 5x . 26 = 650
=> 5x = 25
=> x = 2
b. 3x-1 + 5.3x-1 =162
=> 3x-1 ( 1 + 5 ) = 162
=> 3x-1 . 6 = 162
=> 3x-1 = 27
=> x - 1 = 3
=> x = 3+1 = 4
CHO TÍCH NHA !
Tìm x,biết:
a) (2x-4)4= 81 b) (x-1)5 = -32 c) (2x-1)6=(2x-1)
a) (2x-1)^3=27
b) (2x-1)^4=81
c) (x-2)^5=-32
d) (3x-1)^4=(3x-1)^6
đ) 5^x +5^x+2=650
g) 3^x-1 +5.3^x-1=162
a) (2x-1)3 = 27
(2x-1)3 = 93
2x-1 = 9
2x = 9+1
2x = 10
x = 10:5
x = 2
Vậy x = 2
b) (2x-1)4 = 81
(2x-1)4 = (\(\pm\)34)
2x-1 = \(\pm\)3
Trường hợp 1:
2x-1 = 3
2x = 3+1
2x = 4
x = 4:2
x = 2
Trường hợp 2:
2x-1 = -3
2x = -3+1
2x = -2
x = -2:2
x = -1
Vậy x \(\in[_{ }2;-1]\)
Vì không tìm thấy ngoặc nhọn nên mình dùng tạm ngoặc vuông nhé
a ) \(5^x+5^{x+2}=650\)
\(\Leftrightarrow5^x+5^x5^2=650\)
\(\Leftrightarrow5^x\left(1+25\right)=650\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow5^x=5^2\)
\(\Leftrightarrow x=2\)
b ) \(3^{x-1}+5.3^{x-1}=162\)
\(\Leftrightarrow3^{x-1}\left(1+5\right)=162\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow3^{x-1}=3^3\)
\(\Leftrightarrow x-1=3\Leftrightarrow x=4\)
a)\(5^x+5^{x+2}=650\Rightarrow5^x+5^2.5^x=650\Rightarrow5^x+25.5^x=650\Rightarrow26.5^x=650\)\(5^x=25\Rightarrow5^x=5^2\Rightarrow x=2\)
b) \(3^{x-1}+5.3^{x-1}=162\Rightarrow6.3^{x-1}=162\Rightarrow3^{x-1}=27=3^3\)x-1=3 nên x=4
a)5x+5x+2=650
\(\Rightarrow5^x\left(1+5^2\right)=650\)
\(\Rightarrow5^x\cdot26=650\)
\(\Rightarrow5^x=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)
b)\(3^{x-1}+5\cdot3^{x-1}=162\)
\(\Rightarrow3^{x-1}\cdot\left(1+5\right)=162\)
\(\Rightarrow3^{x-1}\cdot6=162\)
\(\Rightarrow3^{x-1}=27\)
\(\Rightarrow3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
a) 5x + 5x+2 = 650
5x+ 5x . 52 = 650
5x . 1 + 5x . 25 = 650
5x . ( 1 + 25 ) = 650
5x . 26 = 650
5x = 650 : 26
5x = 25
5x = 52
=> x = 2
b) 3x-1 + 5.3x-1 = 162
3x-1 . 1 + 5.3x-1 = 162
3x-1 . ( 1 + 5 ) = 162
3x-1 . 6 = 162
3x-1 = 162 : 6
3x-1 = 27
3x-1 = 33
x - 1 = 3
x = 3 + 1
x = 4
a) \(5^x+5^{x+2}=650\)
\(5^x\left(1+25\right)=650\)
\(5^x=25\)
\(x=2\)
b) \(3^{x-1}+5\cdot3^{x-1}=162\)
\(3^{x-1}\left(1+5\right)=162\)
\(3^{x-1}=27\)
\(x=4\)